Quantitative Aptitude Practice Question and Answer
8Q: If 4th december 1999 is Monday then what day is 3rd january 2000 ? 2983 05b5cc73ae4d2b4197774f8ba
5b5cc73ae4d2b4197774f8ba- 1Sundayfalse
- 2Mondayfalse
- 3Tuesdayfalse
- 4Wednesdaytrue
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Answer : 4. "Wednesday"
Explanation :
Answer: D) Wednesday Explanation: Here from 4th December 1999 to 3rd January 2000,there is a difference of 30 days.Number of odd days = 30/7 = 2 odd days Then no. of odd days = 2 => tuesday and wednesday(from monday). Hence on 3rd january it is wednesday.
Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 2968 15b5cc761e4d2b4197774fd67
5b5cc761e4d2b4197774fd67- 11false
- 22true
- 34false
- 48false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given a2 + b2 = c2 Now 1logc+ab + 1logc-ab = logbc+a + logbc-a = logbc2-a2 = 2logbb = 2
Q: If (1 × 2 × 3 × 4 ........ × n) = n!, then 15! - 14! - 13! is equal to ___? 2967 05b5cc6bee4d2b4197774d997
5b5cc6bee4d2b4197774d997- 114 × 13 × 13!false
- 215 × 14 × 14!false
- 314 × 12 × 12!false
- 415 × 13 × 13!true
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Answer : 4. "15 × 13 × 13!"
Explanation :
Answer: D) 15 × 13 × 13! Explanation: 15! - 14! - 13! = (15 × 14 × 13!) - (14 × 13!) - (13!) = 13! (15 × 14 - 14 - 1) = 13! (15 × 14 - 15) = 13! x 15 (14 - 1) = 15 × 13 × 13!
Q: At a certain rate of interest the compound interest of 3 years and simple interest of 5 years for certain sum of money is respectively Rs. 1513.2 and Rs. 2400. Find the common rate of interest per annum ? 2966 05b5cc6cde4d2b4197774e1cc
5b5cc6cde4d2b4197774e1cc- 15%true
- 26%false
- 34%false
- 43%false
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Answer : 1. "5%"
Explanation :
Answer: A) 5% Explanation: Given compound interest for 3 years = Rs. 1513.2 and simple interest for 5 years = Rs. 2400 Now, we know that C.I = P1+R100n - 1 => 1513.2 = P1+R1003 - 1 ...........(A) And S.I = PTR/100 => 2400 = P5R/100 ..................(B) By solving (A) & (B), we get R = 5%.
Q: Running 3/4th of his usual rate, a man is 15min late. Find his usual time in hours ? 2960 05b5cc6d8e4d2b4197774e782
5b5cc6d8e4d2b4197774e782- 12/3 hrsfalse
- 23/4 hrstrue
- 31/3 hrsfalse
- 41/4 hrsfalse
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Answer : 2. "3/4 hrs"
Explanation :
Answer: B) 3/4 hrs Explanation: Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time so 1/3rd of the usual time = 15minor usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.
Q: The average age of seven persons sitting in a row facing east is 26 years. If the average age of the first three persons is 19 years and the average age of the last three persons is 32 years, then find the age of the person sitting in the middle of the row ? 2952 05b5cc6dce4d2b4197774e97e
5b5cc6dce4d2b4197774e97e- 132 yrsfalse
- 229 yrstrue
- 324 yrsfalse
- 427 yrsfalse
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Answer : 2. "29 yrs"
Explanation :
Answer: B) 29 yrs Explanation: Total age seven persons = (26 x 7)yearsTotal age of the first three persons and the last three persons are (19 x 3) years and (32 x 3) years respectively.Age of the person sitting in the middle of the row = 26 x 7 - 19 x 3 - 32 x 3 = 182 - 57 - 96 = 29 years.
Q: Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ? 2950 05b5cc6d8e4d2b4197774e7c6
5b5cc6d8e4d2b4197774e7c6- 1360 mfalse
- 2420 mtrue
- 3460 mfalse
- 4320 mfalse
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Answer : 2. "420 m"
Explanation :
Answer: B) 420 m Explanation: Let the length of the stationary train Y be LY Given that length of train X, LX = 300 m Let the speed of Train X be V. Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively. => 300/V = 25 ---> ( 1 ) (300 + LY) / V = 60 ---> ( 2 ) From (1) V = 300/25 = 12 m/sec. From (2) (300 + LY)/12 = 60 => 300 + LY = 60 (12) = 720 => LY = 720 - 300 = 420 m Length of the stationary train = 420 m
Q: A supplier supplies cartridges to a news paper publishing house. He earns a profit of 25% by selling cartridges for Rs. 1540. Find the cost price of the Cartridges ? 2948 05b5cc741e4d2b4197774f9a9
5b5cc741e4d2b4197774f9a9- 1Rs. 1100false
- 2Rs. 1793.4false
- 3Rs. 1440false
- 4Rs. 1232true
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Answer : 4. "Rs. 1232"
Explanation :
Answer: D) Rs. 1232 Explanation: Let Cost Price(C.P) = Pgain% = {(S.P-C.P)/C.P} x 10025 = {(1540-P)/P} x 10025/100 = (1540-P)/P=> P = 4(1540)-4P=> 5P = 4(1540)=> P = 1232So, Cost Price = Rs. 1232