Quantitative Aptitude Practice Question and Answer

Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 2834 1

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    1
    Correct
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    2
    Correct
    Wrong
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    4
    Correct
    Wrong
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    8
    Correct
    Wrong
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Answer : 2. "2"
Explanation :

Answer: B) 2 Explanation: Given a2 + b2 = c2   Now  1logc+ab  + 1logc-ab    = logbc+a + logbc-a   = logbc2-a2 = 2logbb = 2

Q: At a certain rate of interest the compound interest of 3 years and simple interest of 5 years for certain sum of money is respectively Rs. 1513.2 and Rs. 2400. Find the common rate of interest per annum ? 2828 0

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    5%
    Correct
    Wrong
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    6%
    Correct
    Wrong
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    4%
    Correct
    Wrong
  • 4
    3%
    Correct
    Wrong
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Answer : 1. "5%"
Explanation :

Answer: A) 5% Explanation: Given compound interest for 3 years = Rs. 1513.2   and simple interest for 5 years = Rs. 2400   Now, we know that  C.I = P1+R100n - 1   => 1513.2 = P1+R1003 - 1 ...........(A)   And S.I = PTR/100   => 2400 = P5R/100 ..................(B)   By solving (A) & (B), we get   R = 5%.

Q: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ? 2826 0

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    100
    Correct
    Wrong
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    1
    Correct
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    4
    Correct
    Wrong
  • 4
    0
    Correct
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Answer : 1. "100"
Explanation :

Answer: A) 100 Explanation: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28   It is in the form of  a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c   Here a = 37, b = 35 & c = 28    => a + b + c = 37 + 35 + 28 = 100       Therefore,   = 100

Q: A supplier supplies cartridges to a news paper publishing house. He earns a profit of 25% by selling cartridges for Rs. 1540. Find the cost price of the Cartridges ? 2824 0

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    Rs. 1100
    Correct
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    Rs. 1793.4
    Correct
    Wrong
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    Rs. 1440
    Correct
    Wrong
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    Rs. 1232
    Correct
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Answer : 4. "Rs. 1232"
Explanation :

Answer: D) Rs. 1232 Explanation: Let Cost Price(C.P) = Pgain% = {(S.P-C.P)/C.P} x 10025 = {(1540-P)/P} x 10025/100 = (1540-P)/P=> P = 4(1540)-4P=> 5P = 4(1540)=> P = 1232So, Cost Price = Rs. 1232

Q: A bus is running at 80 kmph without any stoppage. But, with stoppages its average speed is 60 km/hour. Find the time of stoppage by bus per hour. 2810 1

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    12 minutes
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    20 minutes
    Correct
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    30 minutes
    Correct
    Wrong
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    15 minutes
    Correct
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Answer : 4. "15 minutes"

Q: Running 3/4th of his usual rate, a man is 15min late. Find his usual time in hours  ? 2809 0

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    2/3 hrs
    Correct
    Wrong
  • 2
    3/4 hrs
    Correct
    Wrong
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    1/3 hrs
    Correct
    Wrong
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    1/4 hrs
    Correct
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Answer : 2. "3/4 hrs"
Explanation :

Answer: B) 3/4 hrs Explanation: Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time   so 1/3rd of the usual time = 15minor usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.

Q: Jagan went to another town covering 240 km by car moving at 60 kmph. Then he covered 400km by train moving at 100 kmph and then rest 200 km he covered by a bus moving at 50 kmph. The average speed during the whole journey was ? 2809 0

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    36 kmph
    Correct
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    35 kmph
    Correct
    Wrong
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    72 kmph
    Correct
    Wrong
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    70 kmph
    Correct
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Answer : 4. "70 kmph"
Explanation :

Answer: D) 70 kmph Explanation: By car 240 km at 60 kmphTime taken = 240/60 = 4 hr. By train 240 km at 60 kmphTime taken = 400/100 = 4 hr. By bus 240 km at 60 kmphTime taken = 200/50 = 4 hr. So total time = 4 + 4 + 4 = 12 hr. and total speed = 240+400+200 = 840 kmAverage speed of the whole journey = 840/12 = 70 kmph.

Q: The percentage discount offered for "Buy 6 get 1 free is" ? 2808 0

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    85.78 %
    Correct
    Wrong
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    58. 48 %
    Correct
    Wrong
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    19.25 %
    Correct
    Wrong
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    14.285 %
    Correct
    Wrong
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Answer : 4. "14.285 %"
Explanation :

Answer: D) 14.285 % Explanation: Total Items = 7Discounted = 1Percentage = 1/7 x 100= 14.285%

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