Quantitative Aptitude Practice Question and Answer
8Q: Jagan went to another town covering 240 km by car moving at 60 kmph. Then he covered 400km by train moving at 100 kmph and then rest 200 km he covered by a bus moving at 50 kmph. The average speed during the whole journey was ? 2670 05b5cc705e4d2b4197774f244
5b5cc705e4d2b4197774f244- 136 kmphfalse
- 235 kmphfalse
- 372 kmphfalse
- 470 kmphtrue
- Show Answer
- Workspace
- SingleChoice
Answer : 4. "70 kmph"
Explanation :
Answer: D) 70 kmph Explanation: By car 240 km at 60 kmphTime taken = 240/60 = 4 hr. By train 240 km at 60 kmphTime taken = 400/100 = 4 hr. By bus 240 km at 60 kmphTime taken = 200/50 = 4 hr. So total time = 4 + 4 + 4 = 12 hr. and total speed = 240+400+200 = 840 kmAverage speed of the whole journey = 840/12 = 70 kmph.
Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 2670 15b5cc761e4d2b4197774fd67
5b5cc761e4d2b4197774fd67- 11false
- 22true
- 34false
- 48false
- Show Answer
- Workspace
- SingleChoice
Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given a2 + b2 = c2 Now 1logc+ab + 1logc-ab = logbc+a + logbc-a = logbc2-a2 = 2logbb = 2
Q: A supplier supplies cartridges to a news paper publishing house. He earns a profit of 25% by selling cartridges for Rs. 1540. Find the cost price of the Cartridges ? 2669 05b5cc741e4d2b4197774f9a9
5b5cc741e4d2b4197774f9a9- 1Rs. 1100false
- 2Rs. 1793.4false
- 3Rs. 1440false
- 4Rs. 1232true
- Show Answer
- Workspace
- SingleChoice
Answer : 4. "Rs. 1232"
Explanation :
Answer: D) Rs. 1232 Explanation: Let Cost Price(C.P) = Pgain% = {(S.P-C.P)/C.P} x 10025 = {(1540-P)/P} x 10025/100 = (1540-P)/P=> P = 4(1540)-4P=> 5P = 4(1540)=> P = 1232So, Cost Price = Rs. 1232
Q: Running 3/4th of his usual rate, a man is 15min late. Find his usual time in hours ? 2659 05b5cc6d8e4d2b4197774e782
5b5cc6d8e4d2b4197774e782- 12/3 hrsfalse
- 23/4 hrstrue
- 31/3 hrsfalse
- 41/4 hrsfalse
- Show Answer
- Workspace
- SingleChoice
Answer : 2. "3/4 hrs"
Explanation :
Answer: B) 3/4 hrs Explanation: Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time so 1/3rd of the usual time = 15minor usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.
Q: The percentage discount offered for "Buy 6 get 1 free is" ? 2642 05b5cc72ce4d2b4197774f788
5b5cc72ce4d2b4197774f788- 185.78 %false
- 258. 48 %false
- 319.25 %false
- 414.285 %true
- Show Answer
- Workspace
- SingleChoice
Answer : 4. "14.285 %"
Explanation :
Answer: D) 14.285 % Explanation: Total Items = 7Discounted = 1Percentage = 1/7 x 100= 14.285%
Q: Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay ? 2642 05b5cc6eee4d2b4197774ef04
5b5cc6eee4d2b4197774ef04- 141 yrsfalse
- 240 yrstrue
- 337 yrsfalse
- 433 yrsfalse
- Show Answer
- Workspace
- SingleChoice
Answer : 2. "40 yrs"
Explanation :
Answer: B) 40 yrs Explanation: Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively. => A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8) => 3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8 V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8 => 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8 => 10 - 20/3 = 10/12 A - 9/12 A => 10/3 = A/12 => A = 40.
Q: The concentration of glucose in three different mixtures (glucose and alcohol) is 12,35 and 45 respectively. If 2 litres, 3 litres and 1 litre are taken from these three different vessels and mixed. What is the ratio of glucose and alcohol in the new mixture? 2628 05b5cc6b9e4d2b4197774d76b
5b5cc6b9e4d2b4197774d76b- 13:2true
- 24:3false
- 32:3false
- 43:4false
- Show Answer
- Workspace
- SingleChoice
Answer : 1. "3:2"
Explanation :
Answer: A) 3:2 Explanation: Concentration of glucose are in the ratio = 12:35:45 Quantity of glucose taken from A = 1 liter out of 2 Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit Quantity of glucose taken from C = 0.8 lit So, total quantity of glucose taken from A,B and C = 3.6 lit So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit Ratio of glucose to alcohol = 3.6/2.4 = 3:2
Q: How many prime numbers exist in 65×359×113 ? 2627 05b5cc77fe4d2b419777501ab
5b5cc77fe4d2b419777501ab- 129false
- 231true
- 333false
- 427false
- Show Answer
- Workspace
- SingleChoice
Answer : 2. "31"
Explanation :
Answer: B) 31 Explanation: Given 65×359×113 ⇒2×35×5×79×113 ⇒25×35×59×79×113 Thus, there are (5 + 5 + 9 + 9 + 3)= 31 prime numbers.