Quantitative Aptitude Practice Question and Answer
8Q: Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ? 2888 05b5cc6d8e4d2b4197774e7c6
5b5cc6d8e4d2b4197774e7c6- 1360 mfalse
- 2420 mtrue
- 3460 mfalse
- 4320 mfalse
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Answer : 2. "420 m"
Explanation :
Answer: B) 420 m Explanation: Let the length of the stationary train Y be LY Given that length of train X, LX = 300 m Let the speed of Train X be V. Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively. => 300/V = 25 ---> ( 1 ) (300 + LY) / V = 60 ---> ( 2 ) From (1) V = 300/25 = 12 m/sec. From (2) (300 + LY)/12 = 60 => 300 + LY = 60 (12) = 720 => LY = 720 - 300 = 420 m Length of the stationary train = 420 m
Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 2886 15b5cc761e4d2b4197774fd67
5b5cc761e4d2b4197774fd67- 11false
- 22true
- 34false
- 48false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given a2 + b2 = c2 Now 1logc+ab + 1logc-ab = logbc+a + logbc-a = logbc2-a2 = 2logbb = 2
Q: The average age of seven persons sitting in a row facing east is 26 years. If the average age of the first three persons is 19 years and the average age of the last three persons is 32 years, then find the age of the person sitting in the middle of the row ? 2884 05b5cc6dce4d2b4197774e97e
5b5cc6dce4d2b4197774e97e- 132 yrsfalse
- 229 yrstrue
- 324 yrsfalse
- 427 yrsfalse
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Answer : 2. "29 yrs"
Explanation :
Answer: B) 29 yrs Explanation: Total age seven persons = (26 x 7)yearsTotal age of the first three persons and the last three persons are (19 x 3) years and (32 x 3) years respectively.Age of the person sitting in the middle of the row = 26 x 7 - 19 x 3 - 32 x 3 = 182 - 57 - 96 = 29 years.
Q: The calendar for the year 2018 will be the same for the year 2883 05b5cc6ace4d2b4197774d096
5b5cc6ace4d2b4197774d096- 12023false
- 22027false
- 32029true
- 42022false
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Answer : 3. "2029"
Explanation :
Answer: C) 2029 Explanation: How to find the years which have the same Calendars : Leap year calendar repeats every 28 years. Here 28 is distributed as 6 + 11 + 11. Rules: a) If given year is at 1st position after Leap year then next repeated calendar year is Givenyear+6. b) If given year is at 2nd position after Leap year then next repeated calendar year is Givenyear+11. c) If given year is at 3rd position after Leap year then next repeated calendar year is Givenyear+11. Now, the given year is 2018 We know that 2016 is a Leap year. 2016 2017 2018 2019 2020 Lp Y 1st 2nd 3rd Lp Y Here 2018 is at 2 nd position after the Leap year. According to rule b) the calendar of 2018 is repeated for the year is 2018 + 11 = 2029.
Q: At a certain rate of interest the compound interest of 3 years and simple interest of 5 years for certain sum of money is respectively Rs. 1513.2 and Rs. 2400. Find the common rate of interest per annum ? 2881 05b5cc6cde4d2b4197774e1cc
5b5cc6cde4d2b4197774e1cc- 15%true
- 26%false
- 34%false
- 43%false
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Answer : 1. "5%"
Explanation :
Answer: A) 5% Explanation: Given compound interest for 3 years = Rs. 1513.2 and simple interest for 5 years = Rs. 2400 Now, we know that C.I = P1+R100n - 1 => 1513.2 = P1+R1003 - 1 ...........(A) And S.I = PTR/100 => 2400 = P5R/100 ..................(B) By solving (A) & (B), we get R = 5%.
Q: A supplier supplies cartridges to a news paper publishing house. He earns a profit of 25% by selling cartridges for Rs. 1540. Find the cost price of the Cartridges ? 2881 05b5cc741e4d2b4197774f9a9
5b5cc741e4d2b4197774f9a9- 1Rs. 1100false
- 2Rs. 1793.4false
- 3Rs. 1440false
- 4Rs. 1232true
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Answer : 4. "Rs. 1232"
Explanation :
Answer: D) Rs. 1232 Explanation: Let Cost Price(C.P) = Pgain% = {(S.P-C.P)/C.P} x 10025 = {(1540-P)/P} x 10025/100 = (1540-P)/P=> P = 4(1540)-4P=> 5P = 4(1540)=> P = 1232So, Cost Price = Rs. 1232
Q: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ? 2867 05b5cc6cae4d2b4197774dffc
5b5cc6cae4d2b4197774dffc- 1100true
- 21false
- 34false
- 40false
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Answer : 1. "100"
Explanation :
Answer: A) 100 Explanation: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 It is in the form of a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c Here a = 37, b = 35 & c = 28 => a + b + c = 37 + 35 + 28 = 100 Therefore, = 100
Q: Running 3/4th of his usual rate, a man is 15min late. Find his usual time in hours ? 2864 05b5cc6d8e4d2b4197774e782
5b5cc6d8e4d2b4197774e782- 12/3 hrsfalse
- 23/4 hrstrue
- 31/3 hrsfalse
- 41/4 hrsfalse
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Answer : 2. "3/4 hrs"
Explanation :
Answer: B) 3/4 hrs Explanation: Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time so 1/3rd of the usual time = 15minor usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.

