Answer: B) K=1 & L=4 Explanation: As per divisibility rule a number is divisible by 6 means it should be divisible by 2 and 3 case 1 : the divisibility rule for 2 is the number should be end with even number in this case R =2 & R=4 case 2 : The divisibility rule for 3 is the sum of numbers should be divisible by 3so if we take option (2) Q=1 & R=4 the sum is 39 if we take option (3) Q=1 & R=2 the sum is 37 So Option (2) is correct 39 is divided by 3

Answer: B) 36 c Explanation: Monday + Tuesday + Wednesday = 37 x 3 -----------(1)Tuesday + Wednesday + Thursday = 34 x 3---------(2)Thursday = 4/5 of Monday ------------------(3)subtract eqn (1) from (2) we get,Thursday - Monday = -9 => Monday - Thursday = 9.......(4)From (3) & (4), we get So,Thursday = 36 C

Answer: A) 84 years Explanation: Let the age of ruler is x so that of son = x/2 (given)Now according to the given condition (x/6) + (x/12) + (x/7) + 5 + (x/2) + 4 = x=> x = 84

Answer: B) 1/5 Explanation: Number of applicants = 5On a day, only 1 leave is approved.Now favourable events =  1 of 5 applicants is approvedProbability that Laxmi priya's leave is granted = 1/5.

Answer: D) Rs. 1250 Explanation: 2500 in 5th year and 3000 in 7th year So in between 2 years Rs. 500 is increased => for a year 500/2 = 250So, per year it is increasing Rs.250 then in 5 years => 250 x 5 = 1250Hence, the initial amount must be 2500 - 1250 = Rs. 1250

Answer: D) 44 & 28 Explanation: Letx = peacocks y = deers 2x + 4y = 200 x + y = 72 y = 72 - x 2x + 288 - 4x = 200 x = 44 peacocks y = 28 deers

Answer: B) 26.166 minutes Explanation: Upto first 5 minutes I, J and K will fill => 5[(1/20)+(1/30)+(1/40)] = 65/120 For next 6 minutes, J and K will fill => 6[(1/30)+(1/40)] = 42/120 So tank filled upto first 11 minutes = (65/120) + (42/120) = 107/120 So remaining tank = 13/120 Now at the moment filling with C and leakage @ 1/60 per minute= (1/40) - (1/70) = 3/280.So time taken to fill remaining 13/120 tank =(13/120) /(3/280) = 91/6 minutes   Hence total time taken to completely fill the tank = 5 + 6 + 91/6 = 26.16 minutes.

Answer: C) [6 + (261/315)] days Explanation: After day 1, A finishes 1/9 of the work. After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished. After day 3, C finishes 1/5 more of total work. Total finished is 143/315. So, after day 6, total work finished is 286/315.   Now remaining work =  29 /315   On day 7, A will work again    Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work.   Since he takes 9 days to finish the total task, he will need 261/315 of the day.    Total days required is 6 + (261/315) days.