Answer: D) 500 mts Explanation: Using pythagarous theorem,distance travelled by first train = 36x5/18x30 = 300mdistance travelled by second train = 48x5/18x30 = 400mso distance between them =√( 90000 + 160000) = √250000 = 500mts.

Answer: A) 330/29 m/s Explanation: Second gun shot take 30 sec to reach rahul imples distance between two. given speed of sound = 330 m/s Now, distance = 330 m/s x 30 sec    Hence, speed of the bus = d/t = 330x30/(14x60 + 30) = 330/29 m/s.

Answer: B) 28 Explanation: Here the given series 1, 6,  ?, 15, 45, 66, 91 follows a Pattern in the series is, +5, +9, +13,...,.. +21, +25 So +4 is getting increased at every term addition. Missing Number in the series will be 15+(9+4) = 15 + 13 = 28.

Answer: B) 5 Explanation: Let M, N and O worked together for x days. From the given data,M alone worked for 8 daysM,N,O worked for x daysN, O worked for 1 day But given thatM alone can complete the work in 18 daysN alone can complete the work in 36 daysO alone can complete the work in 54 days The total work can be the LCM of 18, 6, 54 = 108 units M's 1 day work = 108/18 = 6 unitsN's 1 day work = 108/36 = 3 unitsO's 1 day work = 108/54 = 2 units Now, the equation is8 x 6 + 11x + 5 x 1 = 10848 + 11x + 5 = 10811x = 103 - 4811x = 55x = 5 days. Hence, all M,N and O together worked for 5 days.

Answer: D) 6 Explanation: Let us assume Amount be 100 Rs and we calculate in CI  First year 60% of 100 = 60 amount (100+60) is 160  Second year 60% of 160 = 96 amount (160+96) is 256  Third year 60% of 256 =153.6 amount (256+153.6) is 409.6  Here the Amount of 100 Rs is quadrapled in 3 years.  One year contains 2 half years  Three year has 6 half years.  Therefore,  It takes 6 half years.

Answer: B) 60 Explanation: We know that, ● Each digit has a fixed position called its place. ● Each digit has a value depending on its place called the place value of the digit. ● The face value of a digit for any place in the given number is the value of the digit itself ● Place value of a digit = (face value of the digit) × (value of the place).   Hence, the place value of 6 in 64 = 6 x 10 = 60.

Answer: B) 72/5 days Explanation: Work done by Shyam and Rahim in 8 days = 8/32 = 1/4 Remaining work to be done by Shyam and Ram = 1 - 1/4 = 3/4 Given efficieny of Ram is half of Rahim i.e, as Rahim can do the work in 48 days, Ram can do the work in 24 days. One day work of Ram and Shyam = (1/32 - 1/48) + 1/24 = 5/96 Hence, the total work can be done by Shyam and Ram together in 96/5 days.   Therefore, remaining work 3/4 can be done by them in 3/4 x 96/5 = 72/5 = 14.4 days.