Quantitative Aptitude Practice Question and Answer
8Q: A contractor undertook to complete a piece of work in 120 Days and employed 140 men upon it. At the end of 66 days only half of the work was done,so he put on 25 extra men. By how much time did he exceed the specific time ? 2387 05b5cc709e4d2b4197774f2ad
5b5cc709e4d2b4197774f2ad- 12 daystrue
- 23 daysfalse
- 34 daysfalse
- 45 daysfalse
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Answer : 1. "2 days"
Explanation :
Answer: A) 2 days Explanation: work done=total number of person x number of days;half of work done = 140 x 66;For half of remaining work 25 extra men are added.Therefore, total men for half work remaining = 140 + 25 = 165;Let 2nd half work will be completed in K days;140 x 66 = 165 x KK = 122;Hence, extra days => 122-120 = 2days.
Q: At what time between 3 and 4 o’clock will the minute hand and the hour hand are on the same straight line but facing opposite directions ? 2379 05b5cc75ee4d2b4197774fcee
5b5cc75ee4d2b4197774fcee- 13:15 2/8false
- 23:49false
- 33:49 1/11true
- 43:51false
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Answer : 3. "3:49 1/11"
Explanation :
Answer: C) 3:49 1/11 Explanation: On straight line means 180 degree angle.180 = 11/2 min – 30 hrs180 = 11/2 m – 30 × 3180 = 11/2 m – 90(180 + 90) 2 = 11 mm = 540/11 = 49 1/11 minutes.
Q: Find the missing number in the series 1, 6, ?, 15, 45, 66, 91 2379 15b5cc6afe4d2b4197774d230
5b5cc6afe4d2b4197774d230- 124false
- 228true
- 332false
- 426false
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Answer : 2. "28"
Explanation :
Answer: B) 28 Explanation: Here the given series 1, 6, ?, 15, 45, 66, 91 follows a Pattern in the series is, +5, +9, +13,...,.. +21, +25 So +4 is getting increased at every term addition. Missing Number in the series will be 15+(9+4) = 15 + 13 = 28.
Q: A student can divide her books into groups of 5, 9 and 13. what is the smallest possible number of the books ? 2378 05b5cc74ae4d2b4197774fab3
5b5cc74ae4d2b4197774fab3- 1487false
- 2585true
- 3635false
- 4705false
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Answer : 2. "585"
Explanation :
Answer: B) 585 Explanation: The smallest possible number of books = L.C.M of 5, 9 and 13.Therefore, L.C.M of 5,9 and 13 is = 5 x 9 x 13 = 585.
Q: 6 men can complete a piece of work in 12 days. 8 women can complete the same piece of work in 18 days whereas 18 children can complete the piece of work in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day how many men would be required totally? 2366 05b5cc6ade4d2b4197774d125
5b5cc6ade4d2b4197774d125- 138false
- 272false
- 336true
- 476false
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Answer : 3. "36"
Explanation :
Answer: C) 36 Explanation: Given 4men, 12 women and 20 children work for 2 days. Workdone for 2 days by 4men, 12 women and 20 children = 4 x 26 x 12 + 12 x 28 x 18 + 20 x 218 x 10 = 12 Therefore, remaining work = 1 - 12 = 12 To complete the same work by only men in 1 day, We know that M1 x D1 = M2 x D2 Here M1 = 6 , D1 = 12 and M2 = M , D2 = 1 12 x 6 = M x 1 => M = 12 x 6 = 72 => But the remaining work = 1/2 Men required => 1/2 x 72 = 36 Only men required to Complete the remaining work in 1 day = 36.
Q: Rajan's present age is three times his daughter's and nine-thirteenth of his mother's present age. The sum of the present ages of all three of them is 125 years. What is the difference between the present ages of Rajan's daughter and Rajan's mather ? 2359 05b5cc72ce4d2b4197774f773
5b5cc72ce4d2b4197774f773- 132 yearsfalse
- 248 yearsfalse
- 362 yearsfalse
- 450 yearstrue
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Answer : 4. "50 years"
Explanation :
Answer: D) 50 years Explanation: Let Rajan's present age be 'x' years.=> Then his daughter's present age is = x/3 years.His mother's present age = 13x/9 yearsNow, according to the question,x + x/3 + 13x/9 = 125=> x = 125x9/25 = 45Therefore, required difference = 13x/9 - x/3 = 13x - 3x/9 = 10x/9=> 10 x 45/9 = 50 years.
Q: If a number 72k23l is divisible by 88. Then find value of k and l ? 2354 05b5cc745e4d2b4197774fa36
5b5cc745e4d2b4197774fa36- 1k=8 & l=2false
- 2k=7 & l=2true
- 3k=8 & l=3false
- 4k=7 & l=1false
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Answer : 2. "k=7 & l=2"
Explanation :
Answer: B) k=7 & l=2 Explanation: If a number to be divisile by 88, it should be divisible by both "8" and "11" Check for '8' :For a number to be divisible by "8", the last 3-digit should be divisible by "8"Here 72x23y --> last 3-digit is '23y'So y=2 [ (i.e) 232 is absolutely divisible by "8"] Chech for '11' :For a number to be divisible by "11" , sum of odd digits - sum of even digits should be divisible by "11"(7 + x + 3) - (2 + 2 + y)(7 + x + 3) - (2 + 2 + 2)(10 + x) - 6 should be divisible by "11"for x = 7=> 17 - 6 = 11 [ which is absolutely divisible by "11"] So x = 7 , y= 2.
Q: If two fractions, each of which has a value between 0 and 1, are multiplied together, the product will be : 2351 05b5cc6cfe4d2b4197774e303
5b5cc6cfe4d2b4197774e303- 1always greater than either of the original fractionsfalse
- 2always less than either of the original fractionstrue
- 3sometimes greater and sometimes less than either of the original fractionsfalse
- 4remains the samefalse
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Answer : 2. "always less than either of the original fractions"
Explanation :
Answer: B) always less than either of the original fractions Explanation: We can easily Answer this by taking some values. The question states that the two fractions, each have values between 0 and 1.Let us say one of the fraction is 1/2 and the other fraction is 1/3 .The product of the two fractions is 1/2 x 1/3 = 1/6 . is lesser than both 1/2 and 1/3 .So, the correct answer is that the product is always less than either of the original fractions.