Quantitative Aptitude Practice Question and Answer

Q: In a 40 litre mixture of alcohol & water, the ratio of alcohol and water is 5 : 3. If 20% of this mixture is taken out and the same amount of water is added then what will be the ratio of alcohol and water in final mixture? 2691 0

  • 1
    1:1
    Correct
    Wrong
  • 2
    2:1
    Correct
    Wrong
  • 3
    3:1
    Correct
    Wrong
  • 4
    1:2
    Correct
    Wrong
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Answer : 1. "1:1"
Explanation :

Answer: A) 1:1 Explanation: Quantity of alohol in the mixture = 40 x 5/8 = 25 lit Quantity of water = 40 - 25 = 15 lit According to question, Required ratio = 20 - 40 x 20100 x 5815 - 40 x 20100 x 38 + 40 x 20100 = 2015 - 3 + 8 = 1 : 1

Q: P, Q, R, S, T and U are six consecutive odd numbers and their average is 52. What is the product of P and U ? 2691 0

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    2212
    Correct
    Wrong
  • 2
    2154
    Correct
    Wrong
  • 3
    2349
    Correct
    Wrong
  • 4
    2679
    Correct
    Wrong
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Answer : 4. "2679"
Explanation :

Answer: D) 2679 Explanation: Let x, x+2, x+4, x+6, x+8 and x+10 are six consecutive odd numbers. Given that their average is 52 Then, x + x+2 + x+4 + x+6 + x+8 + x+10 = 52×6 6x + 30 = 312 x = 47 So Product = 47 × 57 = 2679

Q: A number increased by 30% gives 390. The number is 2689 0

  • 1
    180
    Correct
    Wrong
  • 2
    300
    Correct
    Wrong
  • 3
    480
    Correct
    Wrong
  • 4
    260
    Correct
    Wrong
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Answer : 2. "300"
Explanation :

Answer: B) 300 Explanation: Let the number be 'N'Given N + 30N/100 = 390=> 130N/100 = 390=> N = 390 x 10/13=> N = 300.

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Answer : 3. "36"
Explanation :

Answer: C) 36 Explanation: Given 4men, 12 women and 20 children work for  2 days. Workdone for 2 days by 4men, 12 women and 20 children = 4 x 26 x 12 + 12 x 28 x 18 + 20 x 218 x 10 = 12 Therefore, remaining work = 1 - 12 = 12 To complete the same work by only men in 1 day, We know that M1 x D1 = M2 x D2 Here M1 = 6 , D1 = 12 and M2 = M , D2 = 1 12 x 6 = M x 1 => M = 12 x 6 = 72 => But the remaining work = 1/2 Men required => 1/2 x 72 = 36 Only men required to Complete the remaining work in 1 day = 36.

Q: Find the odd man out from the given alternatives ? 2681 0

  • 1
    97
    Correct
    Wrong
  • 2
    233
    Correct
    Wrong
  • 3
    437
    Correct
    Wrong
  • 4
    599
    Correct
    Wrong
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Answer : 3. "437"
Explanation :

Answer: C) 437 Explanation: Except 437 all others are prime numbers.

Q: A,B and C enter into a partnership in the ratio  72:43:65. After 4 months, A increases his share by 50%. If the total profit at the end of one year be Rs. 21600, then B's share in the profit is : 2679 0

  • 1
    Rs. 4000
    Correct
    Wrong
  • 2
    Rs. 6000
    Correct
    Wrong
  • 3
    Rs. 9000
    Correct
    Wrong
  • 4
    Rs. 3000
    Correct
    Wrong
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Answer : 1. "Rs. 4000"
Explanation :

Answer: A) Rs. 4000 Explanation: Given ratio of initial investments = 72:43:65 = 105 : 40 : 36.  Let the initial investments be 105x, 40x and 36x.   ∴A:B:C = 105x×4 + 150100×105x×8 : 40x×12 : 36x×12                  = 1680x : 480x : 432x = 35 : 10 : 9.   Hence, B's share = 21600×1054 = Rs. 4000.

Q: 40 % of 250 = 50% ? 2678 0

  • 1
    200
    Correct
    Wrong
  • 2
    100
    Correct
    Wrong
  • 3
    150
    Correct
    Wrong
  • 4
    400
    Correct
    Wrong
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Answer : 1. "200"
Explanation :

Answer: A) 200 Explanation: As per given     40100×250 =50100×x   ⇒x=200

Q: If selling price is doubled, the profit triples. Find the profit percent ? 2677 0

  • 1
    100%
    Correct
    Wrong
  • 2
    200%
    Correct
    Wrong
  • 3
    300%
    Correct
    Wrong
  • 4
    400%
    Correct
    Wrong
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Answer : 1. "100%"
Explanation :

Answer: A) 100% Explanation: Let the C.P be Rs.100 and S.P be Rs.x, Then The profit is (x-100)Now the S.P is doubled, then the new S.P is 2xNew profit is (2x-100)Now as per the given condition; => 3(x-100) = 2x-100By solving, we get x = 200Then the Profit percent = (200-100)/100 = 100Hence the profit percentage is 100%

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