Quantitative Aptitude Practice Question and Answer
8Q: Ayush was born two years after his father's marriage. His mother is five years younger than his father but 20 years older than Ayush who is 10 years old. At what age did the father get married ? 2548 05b5cc71be4d2b4197774f50d
5b5cc71be4d2b4197774f50d- 125 yearsfalse
- 224 yearsfalse
- 323 yearstrue
- 422 yearsfalse
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Answer : 3. "23 years"
Explanation :
Answer: C) 23 years Explanation: Ayush's present age = 10 years.His mother's present age = (10 + 20) years = 30 years.Ayush's father's present age = (30 + 5) years = 35 years.Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years. Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.
Q: If A: B=3:4, B:C=8:9, and C:D=15:16, Find A:D 2546 15d1b15621fc62311c7736872
5d1b15621fc62311c7736872- 15:8true
- 25:7false
- 315:32false
- 420:44false
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Answer : 1. "5:8"
Q: A contractor undertook to complete a piece of work in 120 Days and employed 140 men upon it. At the end of 66 days only half of the work was done,so he put on 25 extra men. By how much time did he exceed the specific time ? 2544 05b5cc709e4d2b4197774f2ad
5b5cc709e4d2b4197774f2ad- 12 daystrue
- 23 daysfalse
- 34 daysfalse
- 45 daysfalse
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Answer : 1. "2 days"
Explanation :
Answer: A) 2 days Explanation: work done=total number of person x number of days;half of work done = 140 x 66;For half of remaining work 25 extra men are added.Therefore, total men for half work remaining = 140 + 25 = 165;Let 2nd half work will be completed in K days;140 x 66 = 165 x KK = 122;Hence, extra days => 122-120 = 2days.
Q: How many 6-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that the digits should not repeat and the second last digit is even ? 2541 05b5cc731e4d2b4197774f7bf
5b5cc731e4d2b4197774f7bf- 1521false
- 2720true
- 3420false
- 4225false
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Answer : 2. "720"
Explanation :
Answer: B) 720 Explanation: Let last digit is 2when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways.so for last digit = 2, total numbers=240 Similarly for 4 and 6When last digit = 4, total no. of ways =240and last digit = 6, total no. of ways =240so total of 720 even numbers are possible.
Q: When Raj Tarun was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Raj Tarun's brother is 6 years older than Raj Tarun and his mother is 3 years younger than his father, how old was Raj Tarun's sister when Raj Tarun was born ? 2532 05b5cc74ae4d2b4197774fa6d
5b5cc74ae4d2b4197774fa6d- 15false
- 210true
- 315false
- 48false
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Answer : 2. "10"
Explanation :
Answer: B) 10 Explanation: Raj Tarun's age = 0 when he was born.Then, given his brother is 6 years old.Then his father is 6 + 32 = 38 when Raj Tarun was bornAnd his mother is 3 years yonger than his father => so his mother was 35 years old when Raj Tarun was bornand his sister is 25 year younger than his mother so Raj Tarun's sister was 10 years old when Raj Tarun was born.
Q: A,B and C enter into a partnership in the ratio 72:43:65. After 4 months, A increases his share by 50%. If the total profit at the end of one year be Rs. 21600, then B's share in the profit is : 2528 05b5cc783e4d2b419777501ec
5b5cc783e4d2b419777501ec- 1Rs. 4000true
- 2Rs. 6000false
- 3Rs. 9000false
- 4Rs. 3000false
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Answer : 1. "Rs. 4000"
Explanation :
Answer: A) Rs. 4000 Explanation: Given ratio of initial investments = 72:43:65 = 105 : 40 : 36. Let the initial investments be 105x, 40x and 36x. ∴A:B:C = 105x×4 + 150100×105x×8 : 40x×12 : 36x×12 = 1680x : 480x : 432x = 35 : 10 : 9. Hence, B's share = 21600×1054 = Rs. 4000.
Q: Find the missing number in the series 1, 6, ?, 15, 45, 66, 91 2522 15b5cc6afe4d2b4197774d230
5b5cc6afe4d2b4197774d230- 124false
- 228true
- 332false
- 426false
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Answer : 2. "28"
Explanation :
Answer: B) 28 Explanation: Here the given series 1, 6, ?, 15, 45, 66, 91 follows a Pattern in the series is, +5, +9, +13,...,.. +21, +25 So +4 is getting increased at every term addition. Missing Number in the series will be 15+(9+4) = 15 + 13 = 28.
Q: Two persons Shyam and Rahim can do a job in 32 days together. Rahim can do the same job in 48 days alone. They started working together and after working 8 days Rahim is replaced by a third person Ram whose efficiency is half that of Rahim. Find in how many days the remaining work will be completed by both Shyam and Ram together? 2520 05b5cc6a3e4d2b4197774cc20
5b5cc6a3e4d2b4197774cc20- 116 daysfalse
- 272/5 daystrue
- 315 daysfalse
- 496/5 daysfalse
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Answer : 2. "72/5 days"
Explanation :
Answer: B) 72/5 days Explanation: Work done by Shyam and Rahim in 8 days = 8/32 = 1/4 Remaining work to be done by Shyam and Ram = 1 - 1/4 = 3/4 Given efficieny of Ram is half of Rahim i.e, as Rahim can do the work in 48 days, Ram can do the work in 24 days. One day work of Ram and Shyam = (1/32 - 1/48) + 1/24 = 5/96 Hence, the total work can be done by Shyam and Ram together in 96/5 days. Therefore, remaining work 3/4 can be done by them in 3/4 x 96/5 = 72/5 = 14.4 days.