Quantitative Aptitude Practice Question and Answer
8Q: A trader mixes 36 kg of rice at Rs. 20 per kg with 14 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is: 2674 05b5cc76ae4d2b4197774fe4a
5b5cc76ae4d2b4197774fe4a- 125%false
- 221.14%false
- 322.54%true
- 427.32%false
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Answer : 3. "22.54%"
Explanation :
Answer: C) 22.54% Explanation: C.P. of 50 kg rice = Rs. (36 x 20 + 14 x 36) = Rs. (720 + 504) = Rs.1224. S.P. of 56 kg rice = Rs. (50 x 30) = Rs.1500. Profit = 1500 - 1224 = Rs.276 Profit % = ProfitC.P×100 = 2761224×100 = 22.54%.
Q: A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1½ times of the previous in how many days will he cover 840 km ? 2672 05b5cc745e4d2b4197774fa0e
5b5cc745e4d2b4197774fa0e- 139 daysfalse
- 237 daysfalse
- 335 daystrue
- 433 daysfalse
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Answer : 3. "35 days"
Explanation :
Answer: C) 35 days Explanation: Distance d = 1200kmlet S be the speed he walks 15 hours a day(i.e 24 - 9)so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speedso 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs=> 490/14 = 35 days So he will take 35 days to cover 840 km.
Q: The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ? 2667 15b5cc73ae4d2b4197774f8bf
5b5cc73ae4d2b4197774f8bf- 114th elementfalse
- 29th elementfalse
- 312th elementtrue
- 47th elementfalse
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Answer : 3. "12th element"
Explanation :
Answer: C) 12th element Explanation: If we consider the third term to be ‘x”The 15th term will be (x + 12d)6th term will be (x + 3d)11th term will be (x + 8d) and 13th term will be (x + 10d).Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.x + 9d will be the 12th term. Thus, 12th term of the A.P will be zero.
Q: A contractor undertook to complete a piece of work in 120 Days and employed 140 men upon it. At the end of 66 days only half of the work was done,so he put on 25 extra men. By how much time did he exceed the specific time ? 2662 05b5cc709e4d2b4197774f2ad
5b5cc709e4d2b4197774f2ad- 12 daystrue
- 23 daysfalse
- 34 daysfalse
- 45 daysfalse
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Answer : 1. "2 days"
Explanation :
Answer: A) 2 days Explanation: work done=total number of person x number of days;half of work done = 140 x 66;For half of remaining work 25 extra men are added.Therefore, total men for half work remaining = 140 + 25 = 165;Let 2nd half work will be completed in K days;140 x 66 = 165 x KK = 122;Hence, extra days => 122-120 = 2days.
Q: The average speed of a train is 3 times the average speed of car. The car covers a distance of 520 km in 8 hours. How much distance will the train cover in 13 hours?
2660 05d4aa50111160f2052371686
5d4aa50111160f2052371686- 12553 kmfalse
- 22585 kmfalse
- 32355 kmfalse
- 42535 kmtrue
- 5None of thesefalse
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Answer : 4. "2535 km"
Explanation :
Train Car
3 1
Speed of car is =520/8=65km/h
so that speed of train = 65*3=195 km/hour
Distance covered by train=speed*time=195*13=2535 km
Q: Find the missing number in the given number series? 514, 470, ?, 415, 404 2659 05b5cc6a9e4d2b4197774cf19
5b5cc6a9e4d2b4197774cf19- 1441false
- 2437true
- 3426false
- 4420false
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Answer : 2. "437"
Explanation :
Answer: B) 437 Explanation: Given number series is 514 470 ? 415 404 Here the pattern it follows is 514 514 - 44 = 470 470 - 33 = 437 437 - 22 = 415 415 - 11 = 404 Hence, the missing number in the given number series is 437.
Q: An employee may claim Rs. 7.00 for each km when he travels by taxi and Rs. 6.00 for each km if he drives his own car. If in one week he claimed Rs. 595 for traveling 90 km. How many kms did he travel by taxi ? 2659 05b5cc736e4d2b4197774f87e
5b5cc736e4d2b4197774f87e- 155 kmstrue
- 235 kmsfalse
- 325 kmsfalse
- 465 kmsfalse
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Answer : 1. "55 kms"
Explanation :
Answer: A) 55 kms Explanation: Let x and y be the respective km's travelled by man via taxi and by his own car.Given x + y = 90 => x = 90 - yBut according to the question,7x + 6y = 5957(90-y) + 6y = 595=> 630 - 7y + 6y = 595=> y = 630 - 595 = 35=> x = 90 - 35 = 55Therefore, the distance travelled by taxi is 55 kms.
Q: Rajesh rows in still water with a speed of 4.5 kmph to go to a certain place and comes back. Find his average speed for the whole journey, if the river is flowing with a speed of 1.5 kmph? 2657 05b5cc67ee4d2b4197774c245
5b5cc67ee4d2b4197774c245- 12 kmphfalse
- 24 kmphtrue
- 36 kmphfalse
- 48 kmphfalse
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Answer : 2. "4 kmph"
Explanation :
Answer: B) 4 kmph Explanation: Let the distance in one direction = k kms Speed in still water = 4.5 kmph Speed of river = 1.5 Hence, speed in upstream = 4.5 - 1.5 = 3 kmph Speed in downstream = 4.5 + 1.5 = 6 kmph Time taken by Rajesh to row upwards = k/3 hrs Time taken by Rajesh to row downwards = k/6 hrs Now, required Average speed =Total distanceTotal speed = 2kk3 + k6 = 2k x 186k + 3k = 4 kmph Therefore, the average speed of the whole journey = 4kmph.