3% of SI=PRT/100

10,000*3*2/100= 3 of x
then x =20,000

Answer: D) 67 Explanation: Here the given series 7, 11, 19, 35, ? follows a pattern that (x 2 - 3) i.e, 7 7 x 2 - 3 = 11 11 x 2 - 3 = 19 19 x 2 - 3 = 35 35 x 2 - 3 = 67 67 x 2 - 3 = 131   Hence the next number in the given number series is 67.

Answer: A) 12 days Explanation: It is given that efficiency ratio =3:1 so time ratio will be 1:3 (since work is same)   Also given that time diff = 32 days. ratio difference = 3-1 =2  2 ratio = 32 days 1 ratio = 16 days. So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days.   Total work = LCM of 16 and 48 = 48. Total time = Total work/Total efficiency  ie; 48/4= 12 days.

Answer: D) 12% p.a. Explanation: If the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate. Let the earlier rate of interest be x%. Now it will be (x + 3)% % increase = (x + 3) - x/x * 100 = 25=> x = 12%

Answer: C) 3 Explanation: When 16nis divided by 9, we have  1619, remainder = 7   1629, remainder = 4  1639, remainder = 1  1649, remainder = 7  1659, remainder = 4  1669, remainder = 1  So, we have cyclicity of 3 factors i.e 7,4,1.  Hence only 3 remainders are possible.

Answer: C) C Explanation: It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects.   Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection.   Hence, we can select 1 black ball from 4 black ballsor 2 black balls from 4 black balls.or 3 black balls from 4 black balls.or 4 black balls from 4 black balls.   Hence, number of ways in which we can select the black balls   = 4C1 + 4C2 + 4C3 + 4C4= 24-1 ........(A)   Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection.   Hence, we can select 1 red ball from 3 red ballsor 2 red balls from 3 red ballsor 3 red balls from 3 red balls   Hence, number of ways in which we can select the red balls= 3C1 + 3C2 + 3C3=23-1........(B)   Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)or 1 blue ball from 5 blue ballsor 2 blue balls from 5 blue ballsor 3 blue balls from 5 blue ballsor 4 blue balls from 5 blue ballsor 5 blue balls from 5 blue balls.   Hence, number of ways in which we can select the blue balls= 5C0 + 5C1 + 5C2 + … + 5C5= 25..............(C)   From (A), (B) and (C), required number of ways=  2524-123-1