Quantitative Aptitude Practice Question and Answer
8Q: What is the ratio of 18 minutes to one hour ? 2321 05b5cc6bfe4d2b4197774da24
5b5cc6bfe4d2b4197774da24- 11/5false
- 23/4false
- 31/7false
- 43/10true
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Answer : 4. "3/10"
Explanation :
Answer: D) 3/10 Explanation: One hour = 60 min 18/60 = 3/10
Q: The circumference of a circular base of Cylinder is 44 cm and its hight is 15 cm. Then the volume of the cylinder is? 2316 05b5cc6ade4d2b4197774d109
5b5cc6ade4d2b4197774d109- 12759 cub. cmfalse
- 22247 cub. cmfalse
- 32614 cub. cmfalse
- 42311 cub. cmtrue
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Answer : 4. "2311 cub. cm"
Explanation :
Answer: D) 2311 cub. cm Explanation: Given Circumference of a circular base of a cylinder = 44 cm We know that Circumference of a circle = 2πr = 44⇒r = 22π Now given the height of a cylinder h = 15 cm Volume of a cylinder V = πr2h = π22π215 = 22 x 22 x 153.14 = 2311 cm3.
Q: If log72 = m, then log4928 is equal to ? 2315 05b5cc761e4d2b4197774fd5d
5b5cc761e4d2b4197774fd5d- 11/(1+2m)false
- 2(1+2m)/2true
- 32m/(2m+1)false
- 4(2m+1)/2mfalse
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Answer : 2. "(1+2m)/2"
Explanation :
Answer: B) (1+2m)/2 Explanation: log4928 = 12log77×4 = 12+122log72= 12+log72= 12 + m= 1+2m2.
Q: 40% of 265 + 35% of 180 = 50% of ? 2311 05b5cc75ce4d2b4197774fc57
5b5cc75ce4d2b4197774fc57- 1383false
- 2338true
- 384.5false
- 4253.5false
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Answer : 2. "338"
Explanation :
Answer: B) 338 Explanation: We know that 40% = 25 40% of 265 + 35% of 180 = 50% ? 25 x 265 + 35% of 180 = 50% ? We know that (35% of 180 = 180% of 35) & 180% = 95 25 x 265 + 95 x 35 = 50% ? 106 + 63 = 50% ? ?= 2 x 169 = 338.
Q: On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ? 2307 05b5cc75ce4d2b4197774fc20
5b5cc75ce4d2b4197774fc20- 1Wednesdaytrue
- 2Tuesdayfalse
- 3Fridayfalse
- 4Thursdayfalse
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Answer : 1. "Wednesday"
Explanation :
Answer: A) Wednesday Explanation: The year 2006 is an ordinary year. So, it has 1 odd day.So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.But, 24th Nov, 2007 is Thursday. 24 - 10 = 14 days. Therefore, 2 weeks ago it is same day. Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.
Q: Rajesh rows in still water with a speed of 4.5 kmph to go to a certain place and comes back. Find his average speed for the whole journey, if the river is flowing with a speed of 1.5 kmph? 2303 05b5cc67ee4d2b4197774c245
5b5cc67ee4d2b4197774c245- 12 kmphfalse
- 24 kmphtrue
- 36 kmphfalse
- 48 kmphfalse
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Answer : 2. "4 kmph"
Explanation :
Answer: B) 4 kmph Explanation: Let the distance in one direction = k kms Speed in still water = 4.5 kmph Speed of river = 1.5 Hence, speed in upstream = 4.5 - 1.5 = 3 kmph Speed in downstream = 4.5 + 1.5 = 6 kmph Time taken by Rajesh to row upwards = k/3 hrs Time taken by Rajesh to row downwards = k/6 hrs Now, required Average speed =Total distanceTotal speed = 2kk3 + k6 = 2k x 186k + 3k = 4 kmph Therefore, the average speed of the whole journey = 4kmph.
Q: How much does a clock lose per day, if its hands coincide ever 65 minutes ? 2300 05b5cc6f8e4d2b4197774f077
5b5cc6f8e4d2b4197774f077- 11440/143 minfalse
- 2184/13 minfalse
- 31425/18 mintrue
- 4541/9 minfalse
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Answer : 3. "1425/18 min"
Explanation :
Answer: C) 1425/18 min Explanation: 55 min. spaces are covered in 60 min.60 min. spaces are covered in ((60/55) x 60) min = 720/11 min.Loss in 65 min. = (720/11 - 65 ) = 5/11Loss in 24 hrs = (5/11 x 1/65 x 24 x 60)min = 1440/143 min.
Q: A dishonest dealer professes to sell his good at cost price, but he uses a weight of 800 gm. For one kg. Find his gain percent? 2300 05d132e47925caa2d5bbbff61
5d132e47925caa2d5bbbff61- 120false
- 225true
- 340false
- 410false
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