Quantitative Aptitude Practice Question and Answer

Q: If log72 = m, then log4928 is equal to ? 2593 0

  • 1
    1/(1+2m)
    Correct
    Wrong
  • 2
    (1+2m)/2
    Correct
    Wrong
  • 3
    2m/(2m+1)
    Correct
    Wrong
  • 4
    (2m+1)/2m
    Correct
    Wrong
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Answer : 2. "(1+2m)/2"
Explanation :

Answer: B) (1+2m)/2 Explanation: log4928 = 12log77×4   = 12+122log72= 12+log72= 12 + m= 1+2m2.

Q: A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ? 2589 0

  • 1
    24 - 1
    Correct
    Wrong
  • 2
    2425-1
    Correct
    Wrong
  • 3
    (24-1)(23-1)25
    Correct
    Wrong
  • 4
    None
    Correct
    Wrong
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Answer : 3. "(24-1)(23-1)25"
Explanation :

Answer: C) C Explanation: It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects.   Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection.   Hence, we can select 1 black ball from 4 black ballsor 2 black balls from 4 black balls.or 3 black balls from 4 black balls.or 4 black balls from 4 black balls.   Hence, number of ways in which we can select the black balls   = 4C1 + 4C2 + 4C3 + 4C4= 24-1 ........(A)   Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection.   Hence, we can select 1 red ball from 3 red ballsor 2 red balls from 3 red ballsor 3 red balls from 3 red balls   Hence, number of ways in which we can select the red balls= 3C1 + 3C2 + 3C3=23-1........(B)   Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)or 1 blue ball from 5 blue ballsor 2 blue balls from 5 blue ballsor 3 blue balls from 5 blue ballsor 4 blue balls from 5 blue ballsor 5 blue balls from 5 blue balls.   Hence, number of ways in which we can select the blue balls= 5C0 + 5C1 + 5C2 + … + 5C5= 25..............(C)   From (A), (B) and (C), required number of ways=  2524-123-1

Q: The circumference of a circular base of Cylinder is 44 cm and its hight is 15 cm. Then the volume of the cylinder is? 2588 0

  • 1
    2759 cub. cm
    Correct
    Wrong
  • 2
    2247 cub. cm
    Correct
    Wrong
  • 3
    2614 cub. cm
    Correct
    Wrong
  • 4
    2311 cub. cm
    Correct
    Wrong
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Answer : 4. "2311 cub. cm"
Explanation :

Answer: D) 2311 cub. cm Explanation: Given Circumference of a circular base of a cylinder = 44 cm We know that Circumference of a circle = 2πr = 44⇒r = 22π Now given the height of a cylinder h = 15 cm Volume of a cylinder V = πr2h = π22π215 = 22 x 22 x 153.14 = 2311 cm3.

Q: If a quarter kg of carrots costs 60 paise, how many paise will 200 gms cost ? 2583 0

  • 1
    78 paise
    Correct
    Wrong
  • 2
    48 paise
    Correct
    Wrong
  • 3
    54 paise
    Correct
    Wrong
  • 4
    62 paise
    Correct
    Wrong
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Answer : 2. "48 paise"
Explanation :

Answer: B) 48 paise Explanation: Quarter of Kg means 250 gm Less weight, less price (Direct Proportion) So, 250 : 200 :: 60 : x => x = 48 So 200 gm will cost 48 paise.

Q: If two fractions, each of which has a value between 0 and 1, are multiplied together, the product will be : 2581 0

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    always greater than either of the original fractions
    Correct
    Wrong
  • 2
    always less than either of the original fractions
    Correct
    Wrong
  • 3
    sometimes greater and sometimes less than either of the original fractions
    Correct
    Wrong
  • 4
    remains the same
    Correct
    Wrong
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Answer : 2. "always less than either of the original fractions"
Explanation :

Answer: B) always less than either of the original fractions Explanation: We can easily Answer this by taking some values.   The question states that the two fractions, each have values between 0 and 1.Let us say one of the fraction is 1/2 and the other fraction is 1/3 .The product of the two fractions is 1/2 x 1/3 = 1/6 . is lesser than both 1/2  and 1/3 .So, the correct answer is that the product is always less than either of the original fractions.

Q: Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? 2577 0

  • 1
    5 kmph
    Correct
    Wrong
  • 2
    6 kmph
    Correct
    Wrong
  • 3
    7.5 kmph
    Correct
    Wrong
  • 4
    8 kmph
    Correct
    Wrong
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Answer : 1. "5 kmph"
Explanation :

Answer: A) 5 kmph Explanation: Let p be the speed of man in kmph According to the given data in the question, Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction => 20 x 10/60 = 8/60 (20 + p) => 200 = 160 + 8p => p = 40/8 = 5 kmph.

Q: A dishonest dealer professes to sell his good at cost price, but he uses a weight of 800 gm. For one kg. Find his gain percent? 2567 0

  • 1
    20
    Correct
    Wrong
  • 2
    25
    Correct
    Wrong
  • 3
    40
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
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Answer : 2. "25"

Q: On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ? 2560 0

  • 1
    Wednesday
    Correct
    Wrong
  • 2
    Tuesday
    Correct
    Wrong
  • 3
    Friday
    Correct
    Wrong
  • 4
    Thursday
    Correct
    Wrong
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Answer : 1. "Wednesday"
Explanation :

Answer: A) Wednesday Explanation: The year 2006 is an ordinary year. So, it has 1 odd day.So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.But, 24th Nov, 2007 is Thursday. 24 - 10 = 14 days. Therefore, 2 weeks ago it is same day. Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.

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