Quantitative Aptitude Practice Question and Answer
8Q: If log72 = m, then log4928 is equal to ? 2593 05b5cc761e4d2b4197774fd5d
5b5cc761e4d2b4197774fd5d- 11/(1+2m)false
- 2(1+2m)/2true
- 32m/(2m+1)false
- 4(2m+1)/2mfalse
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Answer : 2. "(1+2m)/2"
Explanation :
Answer: B) (1+2m)/2 Explanation: log4928 = 12log77×4 = 12+122log72= 12+log72= 12 + m= 1+2m2.
Q: A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ? 2589 05b5cc6f4e4d2b4197774f004
5b5cc6f4e4d2b4197774f004- 124 - 1false
- 22425-1false
- 3(24-1)(23-1)25true
- 4Nonefalse
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Answer : 3. "(24-1)(23-1)25"
Explanation :
Answer: C) C Explanation: It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects. Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection. Hence, we can select 1 black ball from 4 black ballsor 2 black balls from 4 black balls.or 3 black balls from 4 black balls.or 4 black balls from 4 black balls. Hence, number of ways in which we can select the black balls = 4C1 + 4C2 + 4C3 + 4C4= 24-1 ........(A) Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection. Hence, we can select 1 red ball from 3 red ballsor 2 red balls from 3 red ballsor 3 red balls from 3 red balls Hence, number of ways in which we can select the red balls= 3C1 + 3C2 + 3C3=23-1........(B) Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)or 1 blue ball from 5 blue ballsor 2 blue balls from 5 blue ballsor 3 blue balls from 5 blue ballsor 4 blue balls from 5 blue ballsor 5 blue balls from 5 blue balls. Hence, number of ways in which we can select the blue balls= 5C0 + 5C1 + 5C2 + … + 5C5= 25..............(C) From (A), (B) and (C), required number of ways= 2524-123-1
Q: The circumference of a circular base of Cylinder is 44 cm and its hight is 15 cm. Then the volume of the cylinder is? 2588 05b5cc6ade4d2b4197774d109
5b5cc6ade4d2b4197774d109- 12759 cub. cmfalse
- 22247 cub. cmfalse
- 32614 cub. cmfalse
- 42311 cub. cmtrue
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Answer : 4. "2311 cub. cm"
Explanation :
Answer: D) 2311 cub. cm Explanation: Given Circumference of a circular base of a cylinder = 44 cm We know that Circumference of a circle = 2πr = 44⇒r = 22π Now given the height of a cylinder h = 15 cm Volume of a cylinder V = πr2h = π22π215 = 22 x 22 x 153.14 = 2311 cm3.
Q: If a quarter kg of carrots costs 60 paise, how many paise will 200 gms cost ? 2583 05b5cc6d7e4d2b4197774e70a
5b5cc6d7e4d2b4197774e70a- 178 paisefalse
- 248 paisetrue
- 354 paisefalse
- 462 paisefalse
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Answer : 2. "48 paise"
Explanation :
Answer: B) 48 paise Explanation: Quarter of Kg means 250 gm Less weight, less price (Direct Proportion) So, 250 : 200 :: 60 : x => x = 48 So 200 gm will cost 48 paise.
Q: If two fractions, each of which has a value between 0 and 1, are multiplied together, the product will be : 2581 05b5cc6cfe4d2b4197774e303
5b5cc6cfe4d2b4197774e303- 1always greater than either of the original fractionsfalse
- 2always less than either of the original fractionstrue
- 3sometimes greater and sometimes less than either of the original fractionsfalse
- 4remains the samefalse
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Answer : 2. "always less than either of the original fractions"
Explanation :
Answer: B) always less than either of the original fractions Explanation: We can easily Answer this by taking some values. The question states that the two fractions, each have values between 0 and 1.Let us say one of the fraction is 1/2 and the other fraction is 1/3 .The product of the two fractions is 1/2 x 1/3 = 1/6 . is lesser than both 1/2 and 1/3 .So, the correct answer is that the product is always less than either of the original fractions.
Q: Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? 2577 05b5cc60ae4d2b4197774b5b5
5b5cc60ae4d2b4197774b5b5- 15 kmphtrue
- 26 kmphfalse
- 37.5 kmphfalse
- 48 kmphfalse
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Answer : 1. "5 kmph"
Explanation :
Answer: A) 5 kmph Explanation: Let p be the speed of man in kmph According to the given data in the question, Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction => 20 x 10/60 = 8/60 (20 + p) => 200 = 160 + 8p => p = 40/8 = 5 kmph.
Q: A dishonest dealer professes to sell his good at cost price, but he uses a weight of 800 gm. For one kg. Find his gain percent? 2567 05d132e47925caa2d5bbbff61
5d132e47925caa2d5bbbff61- 120false
- 225true
- 340false
- 410false
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Answer : 2. "25"
Q: On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ? 2560 05b5cc75ce4d2b4197774fc20
5b5cc75ce4d2b4197774fc20- 1Wednesdaytrue
- 2Tuesdayfalse
- 3Fridayfalse
- 4Thursdayfalse
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Answer : 1. "Wednesday"
Explanation :
Answer: A) Wednesday Explanation: The year 2006 is an ordinary year. So, it has 1 odd day.So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.But, 24th Nov, 2007 is Thursday. 24 - 10 = 14 days. Therefore, 2 weeks ago it is same day. Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.

