Quantitative Aptitude Practice Question and Answer

Q: Karthik read 613 th of a book in 1st week and 59 th of the remaining book in 2nd week. If there were 100 pages unread after 2nd week, how many pages were there in the book ? 2699 0

  • 1
    404
    Correct
    Wrong
  • 2
    415
    Correct
    Wrong
  • 3
    418
    Correct
    Wrong
  • 4
    420
    Correct
    Wrong
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Answer : 3. "418"
Explanation :

Answer: C) 418 Explanation: Let the total book be 1 Then, in the 1st week 613th of book is read i.e remaining pages =  1-613=713 in 2nd week he read 59th of it i.e 59×713=35117Remaining pages after 2nd week = 713-35117=28117 But given remaining pages after 2nd week = 100   28x117=100 --> x = 418   The total pages in the book are 418

Q: How many four digit even numbers can be formed using the digits {2, 7, 5, 3, 9, 1} ? 2698 0

  • 1
    59
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  • 2
    60
    Correct
    Wrong
  • 3
    61
    Correct
    Wrong
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    64
    Correct
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Answer : 2. "60"
Explanation :

Answer: B) 60 Explanation: The given digits are 1, 2, 3, 5, 7, 9   A number is even when its units digit is even. Of the given digits, two is the only even digit.Units place is filled with only '2' and the remaining three places can be filled in ⁵P₃ ways.   Number of even numbers = ⁵P₃ = 60.

Q: A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook ? 2698 0

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    15
    Correct
    Wrong
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    20
    Correct
    Wrong
  • 3
    10
    Correct
    Wrong
  • 4
    8
    Correct
    Wrong
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Answer : 3. "10"
Explanation :

Answer: C) 10 Explanation: Let the price of each note book be Rs.x. Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y. Hence xy = 300 => y = 300/x (x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy =>5(300/x) - 10x - 50 = 0 => -150+x2+5x multiplying both sides by -1/10x => x2+15x-10x-150=0 => x(x + 15) - 10(x + 15) = 0 => x = 10 or -15 As x>0, x = 10.

Q: The number of ways that 8 beads of different colours be strung as a necklace is 2695 0

  • 1
    2520
    Correct
    Wrong
  • 2
    2880
    Correct
    Wrong
  • 3
    4320
    Correct
    Wrong
  • 4
    5040
    Correct
    Wrong
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Answer : 1. "2520"
Explanation :

Answer: A) 2520 Explanation: The number of ways of arranging n beads in a necklace is (n-1)!2=(8-1)!2=7!2 = 2520  (since n = 8)

Q: The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a.  ? 2693 0

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    Rs. 22.5
    Correct
    Wrong
  • 2
    Rs. 2.5
    Correct
    Wrong
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    Rs. 202
    Correct
    Wrong
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    Rs. 25
    Correct
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Answer : 1. "Rs. 22.5"
Explanation :

Answer: A) Rs. 22.5 Explanation: We know that I = PTR/100=> P = 20250/4.5 = 4500Now, new Interest at 5% = 4500x1x5/100 = 225Now the additional amount = 225 - 202.5 = Rs. 22.5

Q: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats ? 2691 0

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    1 : 2 : 3
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    2 : 3 : 4
    Correct
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  • 3
    3: 4 : 5
    Correct
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    4 : 5 : 6
    Correct
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Answer : 2. "2 : 3 : 4"
Explanation :

Answer: B) 2 : 3 : 4 Explanation: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. Seats for Mathematics, Physics and Biology in a school are 5x, 7x and 8x. There is a proposal to increase these seats by 40%, 50% and 75% respectively. Then Seats for Mathematics, Physics and Biology in a school will be 1.4 X 5x, 1.5 X 7x and 1.75 X 8x and ratio will be 7 : 10.5 : 14  => 2:3:4.

Q: Out of 135 applicants for a post, 60 are graduates and 80 have experience. What is the ratio of minimum to maximum numberof graduates having experience? 2690 0

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    12:1
    Correct
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  • 2
    5:1
    Correct
    Wrong
  • 3
    1:5
    Correct
    Wrong
  • 4
    1:12
    Correct
    Wrong
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Answer : 4. "1:12"
Explanation :

Answer: D) 1:12 Explanation: Given total applicants = 135Given graduates are G=60 Otherthan graduates=135-60 = 75Given experienced candidates = 801) For maximum number of graduates have experience    Total graduates to have experience = 60 2) For minimum number of graduates have experience    Remaining after taking other than graduates in experience= 80-75 = 5

Q: X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished? 2688 0

  • 1
    1/3
    Correct
    Wrong
  • 2
    2/3
    Correct
    Wrong
  • 3
    1/6
    Correct
    Wrong
  • 4
    5/6
    Correct
    Wrong
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Answer : 3. "1/6"
Explanation :

Answer: C) 1/6 Explanation: Given X can do in 10 days  => 1 day work of X = 1/10   Y can do in 15 days  => 1 day work of Y = 1/15   1day work of (X + Y) = 1/10 + 1/15 = 1/6   Given they are hired for 5 days  => 5 days work of (X + Y) = 5 x 1/6 = 5/6  Therefore, Unfinished work = 1 - 5/6 = 1/6

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