Quantitative Aptitude Practice Question and Answer
8Q: Karthik read 613 th of a book in 1st week and 59 th of the remaining book in 2nd week. If there were 100 pages unread after 2nd week, how many pages were there in the book ? 2699 05b5cc76fe4d2b4197774ff76
5b5cc76fe4d2b4197774ff76- 1404false
- 2415false
- 3418true
- 4420false
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Answer : 3. "418"
Explanation :
Answer: C) 418 Explanation: Let the total book be 1 Then, in the 1st week 613th of book is read i.e remaining pages = 1-613=713 in 2nd week he read 59th of it i.e 59×713=35117Remaining pages after 2nd week = 713-35117=28117 But given remaining pages after 2nd week = 100 28x117=100 --> x = 418 The total pages in the book are 418
Q: How many four digit even numbers can be formed using the digits {2, 7, 5, 3, 9, 1} ? 2698 05b5cc6d7e4d2b4197774e705
5b5cc6d7e4d2b4197774e705- 159false
- 260true
- 361false
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Answer : 2. "60"
Explanation :
Answer: B) 60 Explanation: The given digits are 1, 2, 3, 5, 7, 9 A number is even when its units digit is even. Of the given digits, two is the only even digit.Units place is filled with only '2' and the remaining three places can be filled in ⁵P₃ ways. Number of even numbers = ⁵P₃ = 60.
Q: A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook ? 2698 05b5cc6dde4d2b4197774ea28
5b5cc6dde4d2b4197774ea28- 115false
- 220false
- 310true
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Answer : 3. "10"
Explanation :
Answer: C) 10 Explanation: Let the price of each note book be Rs.x. Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y. Hence xy = 300 => y = 300/x (x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy =>5(300/x) - 10x - 50 = 0 => -150+x2+5x multiplying both sides by -1/10x => x2+15x-10x-150=0 => x(x + 15) - 10(x + 15) = 0 => x = 10 or -15 As x>0, x = 10.
Q: The number of ways that 8 beads of different colours be strung as a necklace is 2695 05b5cc7b4e4d2b4197775089c
5b5cc7b4e4d2b4197775089c- 12520true
- 22880false
- 34320false
- 45040false
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Answer : 1. "2520"
Explanation :
Answer: A) 2520 Explanation: The number of ways of arranging n beads in a necklace is (n-1)!2=(8-1)!2=7!2 = 2520 (since n = 8)
Q: The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a. ? 2693 05b5cc6dde4d2b4197774ea19
5b5cc6dde4d2b4197774ea19- 1Rs. 22.5true
- 2Rs. 2.5false
- 3Rs. 202false
- 4Rs. 25false
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Answer : 1. "Rs. 22.5"
Explanation :
Answer: A) Rs. 22.5 Explanation: We know that I = PTR/100=> P = 20250/4.5 = 4500Now, new Interest at 5% = 4500x1x5/100 = 225Now the additional amount = 225 - 202.5 = Rs. 22.5
Q: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats ? 2691 05b5cc74ae4d2b4197774fad1
5b5cc74ae4d2b4197774fad1- 11 : 2 : 3false
- 22 : 3 : 4true
- 33: 4 : 5false
- 44 : 5 : 6false
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Answer : 2. "2 : 3 : 4"
Explanation :
Answer: B) 2 : 3 : 4 Explanation: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. Seats for Mathematics, Physics and Biology in a school are 5x, 7x and 8x. There is a proposal to increase these seats by 40%, 50% and 75% respectively. Then Seats for Mathematics, Physics and Biology in a school will be 1.4 X 5x, 1.5 X 7x and 1.75 X 8x and ratio will be 7 : 10.5 : 14 => 2:3:4.
Q: Out of 135 applicants for a post, 60 are graduates and 80 have experience. What is the ratio of minimum to maximum numberof graduates having experience? 2690 05b5cc774e4d2b41977750066
5b5cc774e4d2b41977750066- 112:1false
- 25:1false
- 31:5false
- 41:12true
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Answer : 4. "1:12"
Explanation :
Answer: D) 1:12 Explanation: Given total applicants = 135Given graduates are G=60 Otherthan graduates=135-60 = 75Given experienced candidates = 801) For maximum number of graduates have experience Total graduates to have experience = 60 2) For minimum number of graduates have experience Remaining after taking other than graduates in experience= 80-75 = 5
Q: X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished? 2688 05b5cc6bfe4d2b4197774da0a
5b5cc6bfe4d2b4197774da0a- 11/3false
- 22/3false
- 31/6true
- 45/6false
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Answer : 3. "1/6"
Explanation :
Answer: C) 1/6 Explanation: Given X can do in 10 days => 1 day work of X = 1/10 Y can do in 15 days => 1 day work of Y = 1/15 1day work of (X + Y) = 1/10 + 1/15 = 1/6 Given they are hired for 5 days => 5 days work of (X + Y) = 5 x 1/6 = 5/6 Therefore, Unfinished work = 1 - 5/6 = 1/6

