Quantitative Aptitude Practice Question and Answer
8Q: The first 8 alphabets are written down at random. what is the probability that the letters b,c,d,e always come together ? 2193 05b5cc6d3e4d2b4197774e4d7
5b5cc6d3e4d2b4197774e4d7- 11/7false
- 28!false
- 37!false
- 41/14true
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Answer : 4. "1/14"
Explanation :
Answer: D) 1/14 Explanation: The 8 letters can be written in 8! ways.n(S) = 8!Let E be the event that the letters b,c,d,e always come together when the first 8 alphabets are written down.Now the letters a, (bcde), f, g and h can be arranged in 5! ways.The letters b,c,d and e can be arranged themselves in 4! ways.n(E) = 5! x 4!Now, the required P(E) = n(E)/n(S) = 5! x 4!/8! = 1/14Hence the answer is 1/14.
Q: The third proportional to 9 and 12 is ? 2192 05b5cc6e9e4d2b4197774ede8
5b5cc6e9e4d2b4197774ede8- 114false
- 216true
- 318false
- 420false
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Answer : 2. "16"
Explanation :
Answer: B) 16 Explanation: Let the third proportion to 9 & 12 be 'x'. => 9:12 = 12 :p => p = 12x12/9 = 16.
Q: One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture. 2192 05b5cc75ee4d2b4197774fcc0
5b5cc75ee4d2b4197774fcc0- 127 %true
- 226 %false
- 329 %false
- 421 %false
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Answer : 1. "27 %"
Explanation :
Answer: A) 27 % Explanation: Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135 X = 27 So, required percentage of benzene = 27 %
Q: Two bottles contains mixture of milk and water. First bottle contains 64% milk and second bottle contains 26% water. In what ratio these two mixtures are mixed so that new mixture contains 68% milk? 2190 05b5cc626e4d2b4197774b82a
5b5cc626e4d2b4197774b82a- 13 : 2true
- 22 : 1false
- 31 : 2false
- 42 : 3false
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Answer : 1. "3 : 2"
Explanation :
Answer: A) 3 : 2 Explanation: % of milk in first bottle = 64% % of milk in second bottle = 100 - 26 = 74% Now, ATQ 64% 74% 68% 6 4 Hence, by using allegation method, Required ratio = 3 : 2
Q: The difference between the time taken by two trains to travel a distance of 350 km is 2 hours 20 minutes. If the difference between their speeds is 5 km/hr, what is the speed of faster train ? 2189 05b5cc6c9e4d2b4197774df6a
5b5cc6c9e4d2b4197774df6a- 136 kmphfalse
- 230 kmphtrue
- 334 kmphfalse
- 440 kmphfalse
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Answer : 2. "30 kmph"
Explanation :
Answer: B) 30 kmph Explanation: Let the speed of the faster train be 'S' kmph Then speed of the slower train will be '(S-5)' kmph Time taken by faster train = 350/S hrs Time taken by slower train = 350/(S-5) hrs 350s-5 - 350s = 2 hrs 20 min = 213 = 73 => S = 30 km/hr.
Q: Find the missing number in the following Series ? 18, 97, 26, 91, ? , 83 2187 05b5cc6c2e4d2b4197774dbaf
5b5cc6c2e4d2b4197774dbaf- 132false
- 236false
- 330false
- 434true
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Answer : 4. "34"
Explanation :
Answer: D) 34 Explanation: The given series follows the pattern that, 18, 97, 26, 91, ?, 83 => 18 + 8 = 26 => 97 - 8 = 91 => 26 + 8 = 34 => 91 - 8 = 83 Hence, the missing number is 34.
Q: A person says that his son is 5 times as old as his daughter and his wife is 5 times older than his son and he is twice the age of his wife . The sum total of all the ages equals the age of the grand mother who celebrated her 81st birthday today. How old was his son? 2187 05b5cc715e4d2b4197774f413
5b5cc715e4d2b4197774f413- 150 yrstrue
- 225 yrsfalse
- 372 yrsfalse
- 440 yrsfalse
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Answer : 1. "50 yrs"
Explanation :
Answer: A) 50 yrs Explanation: Let the daughter age be 'x'Therefore, Son age = 5x, Mother age = 25x, Person age = 50x. Thus we get, x+5x+25x+50x = 8181x = 81x = 1 Daughter's age = 1, Son's = 5, Mother's = 25, Person's age = 50.
Q: A person got Rs.48 more when he invested a certain sum at compound interest instead of simple interest for two years at 8% p.a. Find the sum ? 2186 05b5cc6e0e4d2b4197774eb61
5b5cc6e0e4d2b4197774eb61- 1Rs.8000false
- 2Rs.6500false
- 3Rs.7500true
- 4Rs.5000false
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Answer : 3. "Rs.7500"
Explanation :
Answer: C) Rs.7500 Explanation: p=d×1002R2 Where d is difference, r is rate of interest. => (48 x 100 x 100) / 8 x 8 = Rs.7500