Quantitative Aptitude Practice Question and Answer

Q: Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ? 2599 0

  • 1
    5.75 kms
    Correct
    Wrong
  • 2
    7.36 kms
    Correct
    Wrong
  • 3
    8.2 kms
    Correct
    Wrong
  • 4
    6.98 kms
    Correct
    Wrong
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Answer : 2. "7.36 kms"
Explanation :

Answer: B) 7.36 kms Explanation: Total running distance in four weeks = (24 x 240) + (4 x 400) = 5760 + 1600 = 7360 meters = 7360/1000 => 7.36 kms

Q: In what time will Rs. 1860 amount to Rs. 2641.20 at simple interest 12% per annum? 2595 0

  • 1
    2.9 years
    Correct
    Wrong
  • 2
    3.5 years
    Correct
    Wrong
  • 3
    4.2 years
    Correct
    Wrong
  • 4
    4.7 years
    Correct
    Wrong
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Answer : 2. "3.5 years"
Explanation :

Answer: B) 3.5 years Explanation: Given that Rs. 1860 will become Rs. 2641.20 at 12% => Simple Interest = 2641.20 - 1860 = Rs. 781.20 We know I = PTR/100 => 781.20 x 100 = 1860 x T x 12 => T = 78120/1860x12 => T = 78120/22320 => T = 3.5 years.

Q:

What approximate values should come in place of the question mark(?) in the following question?

2592 0

  • 1
    57
    Correct
    Wrong
  • 2
    47
    Correct
    Wrong
  • 3
    67
    Correct
    Wrong
  • 4
    37
    Correct
    Wrong
  • 5
    27
    Correct
    Wrong
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Answer : 2. "47"

Q: The average temperature of Monday to Wednesday was 37 C and of Tuesday to Thursday was 34 C. If the temperature on Thursday was 4/5 th of that of Monday, the temperature on Thursday was ? 2591 0

  • 1
    35 c
    Correct
    Wrong
  • 2
    36 c
    Correct
    Wrong
  • 3
    34 c
    Correct
    Wrong
  • 4
    32 c
    Correct
    Wrong
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Answer : 2. "36 c"
Explanation :

Answer: B) 36 c Explanation: Monday + Tuesday + Wednesday = 37 x 3 -----------(1)Tuesday + Wednesday + Thursday = 34 x 3---------(2)Thursday = 4/5 of Monday ------------------(3)subtract eqn (1) from (2) we get,Thursday - Monday = -9 => Monday - Thursday = 9.......(4)From (3) & (4), we get So,Thursday = 36 C

Q: What is the common ratio of the following geometric sequence? 4, 2, 1, 0.5, 0.25, 0.125,... 2587 0

  • 1
    0.5
    Correct
    Wrong
  • 2
    -1
    Correct
    Wrong
  • 3
    1.5
    Correct
    Wrong
  • 4
    -0.5
    Correct
    Wrong
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Answer : 1. "0.5"
Explanation :

Answer: A) 0.5 Explanation: In mathematics, a geometric progression, also known as a geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.   Herein the given sequence, 4, 2, 1, 0.5, 0.25, 0.125,... Common Ratio r = 2/4 = 1/2 = 0.5/1 = 0.25/0.5 = 0.125/0.25 == 0.5.

Q: If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ? 2587 0

  • 1
    31/25
    Correct
    Wrong
  • 2
    15/17
    Correct
    Wrong
  • 3
    14/25
    Correct
    Wrong
  • 4
    11/16
    Correct
    Wrong
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Answer : 2. "15/17"
Explanation :

Answer: B) 15/17 Explanation: The original fraction is  2551 × 350+100150+100  = 15/17.

Q: What comes next in this sequence 196, 169, 144, 121, 100, 81, ? 2585 0

  • 1
    77
    Correct
    Wrong
  • 2
    74
    Correct
    Wrong
  • 3
    67
    Correct
    Wrong
  • 4
    64
    Correct
    Wrong
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Answer : 4. "64"
Explanation :

Answer: D) 64 Explanation: The given number series follows a pattern that 196, 169, 144, 121, 100, 81, ?     -27  -25   -23   -21  -19  -17   => 81 - 17 = 64 Therefore, the series is 196, 169, 144, 121, 100, 81, 64.

Q: What is the probability that a leap year has 53 Saturdays and 52 Sundays ? 2585 0

  • 1
    1/7
    Correct
    Wrong
  • 2
    2/7
    Correct
    Wrong
  • 3
    1/2
    Correct
    Wrong
  • 4
    3/2
    Correct
    Wrong
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Answer : 1. "1/7"
Explanation :

Answer: A) 1/7 Explanation: A leap year has 52 weeks and two daysTotal number of cases = 7Number of favourable cases = 1i.e., {Friday, Saturday} Required Probability = 1/7

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