Quantitative Aptitude Practice Question and Answer
8 Q: What approximate values should come in place of the question mark(?) in the following question?
2691 05d4ab07211160f2052373ec4
5d4ab07211160f2052373ec4- 157false
- 247true
- 367false
- 437false
- 527false
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Answer : 2. "47"
Q: 3131×31-27 =? 2690 05b5cc783e4d2b419777501e2
5b5cc783e4d2b419777501e2- 1961 x 861false
- 2961 x 961true
- 3961 x 2false
- 429791false
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Answer : 2. "961 x 961"
Explanation :
Answer: B) 961 x 961 Explanation: We know that am×an=am+n ∴3131-27 = 314 = 961 x 961.
Q: Find the next number in the following number series? 11, 13, 30, 96, ? 2689 05b5cc688e4d2b4197774c318
5b5cc688e4d2b4197774c318- 1264false
- 2392true
- 3412false
- 4459false
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Answer : 2. "392"
Explanation :
Answer: B) 392 Explanation: The given number series 11, 13, 30, 96, ? follows a pattern that, 11 11 x 1 + 2 = 13 13 x 2 + 4 = 30 30 x 3 + 6 = 96 96 x 4 + 8 = 392 Hence, the next number in the given series is 392.
Q: P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ? 2689 05b5cc6c7e4d2b4197774de73
5b5cc6c7e4d2b4197774de73- 199true
- 2100false
- 389false
- 41false
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Answer : 1. "99"
Explanation :
Answer: A) 99 Explanation: Let, Distance between A and B = d Distance travelled by P while it meets Q = d + 11 Distance travelled by Q while it meets P = d – 11 Distance travelled by Q while it meets R = d + 9 Distance travelled by R while it meets Q = d – 9 Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11 The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9 But given Ratio of speeds of P & R => P : R = 3 : 2 SPSR = SPSQxSQSR = d+11d+9d-11d-9 => d+11d+9d-11d-9 = 3/2 => d = 1, 99 => d = 99 satisfies. Therefore, Distance between A and B = 99
Q: The ratio of efficiencies of P, Q and R is 2 : 3 : 4. While P and R work on alternate days and Q work for all days. Now the work completed in total 10 days and the total amount they get is Rs. 1200. Find the amount of each person(respectively). 2689 05b5cc69de4d2b4197774c914
5b5cc69de4d2b4197774c914- 1200, 600, 400true
- 2400, 600, 200false
- 3600, 200, 400false
- 4400, 200, 600false
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Answer : 1. "200, 600, 400"
Explanation :
Answer: A) 200, 600, 400 Explanation: Ratio of efficiencies of P, Q and R = 2 : 3 : 4 From the given data, Number of working days of P, Q, R = 5 : 10 : 5 Hence, ratio of amount of p, Q, R = 2x5 : 3x10 : 4x5 = 10 : 30 : 20 Amounts of P, Q, R = 200, 600 and 400.
Q: In what time will Rs. 1860 amount to Rs. 2641.20 at simple interest 12% per annum? 2686 05b5cc6bee4d2b4197774d988
5b5cc6bee4d2b4197774d988- 12.9 yearsfalse
- 23.5 yearstrue
- 34.2 yearsfalse
- 44.7 yearsfalse
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Answer : 2. "3.5 years"
Explanation :
Answer: B) 3.5 years Explanation: Given that Rs. 1860 will become Rs. 2641.20 at 12% => Simple Interest = 2641.20 - 1860 = Rs. 781.20 We know I = PTR/100 => 781.20 x 100 = 1860 x T x 12 => T = 78120/1860x12 => T = 78120/22320 => T = 3.5 years.
Q: 80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 2680 05b5cc6d3e4d2b4197774e4c8
5b5cc6d3e4d2b4197774e4c8- 1120 litfalse
- 2140 litfalse
- 3110 litfalse
- 4150 littrue
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Answer : 4. "150 lit"
Explanation :
Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.
Q: If 5th March, 2005 is Monday, what was the day of the week on 5th March, 2004 ? 2674 05b5cc72ce4d2b4197774f74b
5b5cc72ce4d2b4197774f74b- 1Sundaytrue
- 2Mondayfalse
- 3Tuesdayfalse
- 4Wednesdayfalse
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Answer : 1. "Sunday"
Explanation :
Answer: A) Sunday Explanation: The year 2004 is a leap year. So, it has 2 odd days. But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only. The day on 5th March, 2005 will be 1 day beyond the day on 5th March, 2004. Given that, 5th March, 2005 is Monday. 5th March, 2004 is Sunday (1 day before to 5th March, 2005).