Quantitative Aptitude Practice Question and Answer
8Q: A can build a wall in 16 days while B can destroy it in 8 days. A worked for 5 days. Then B joined with A for the next 2 days. Find in how many days could A build the remaining wall ? 2349 05b5cc6cee4d2b4197774e208
5b5cc6cee4d2b4197774e208- 112 daysfalse
- 214 daysfalse
- 313 daystrue
- 416 daysfalse
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Answer : 3. "13 days"
Explanation :
Answer: C) 13 days Explanation: Now, Total work = LCM(16, 8) = 48 A's one day work = + 48/16 = + 3 B's one day work = - 48/8 = -6 Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15 2days B joined with A in working = 2(3 - 6) = - 6 Remaining Work of building wall = 48 - (15 - 6) = 39 Now this remaining work will be done by A in = 39/3 = 13 days.
Q: Find the next number in the following number series? 11, 13, 30, 96, ? 2347 05b5cc688e4d2b4197774c318
5b5cc688e4d2b4197774c318- 1264false
- 2392true
- 3412false
- 4459false
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Answer : 2. "392"
Explanation :
Answer: B) 392 Explanation: The given number series 11, 13, 30, 96, ? follows a pattern that, 11 11 x 1 + 2 = 13 13 x 2 + 4 = 30 30 x 3 + 6 = 96 96 x 4 + 8 = 392 Hence, the next number in the given series is 392.
Q: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man ? 2347 05b5cc6d7e4d2b4197774e728
5b5cc6d7e4d2b4197774e728- 14.58 kmsfalse
- 26.35 kmsfalse
- 35.76 kmstrue
- 45.24 kmsfalse
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Answer : 3. "5.76 kms"
Explanation :
Answer: C) 5.76 kms Explanation: Speed in still water = 6 kmph Stream speed = 1.2 kmph Down stream = 7.2 kmph Up Stream = 4.8 kmph x/7.2 + x/4.8 = 1 x = 2.88 Total Distance = 2.88 x 2 = 5.76 kms
Q: Three milkmen rented a pasture. A grazed 24 cows for 4 months; B 10 cows for 6 months; C 56 cows for 5 months. If A's share of rent is Rs. 960, find the total rent of the field? 2341 05b5cc783e4d2b419777501f1
5b5cc783e4d2b419777501f1- 14530false
- 24440false
- 34360true
- 44280false
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Answer : 3. "4360"
Explanation :
Answer: C) 4360 Explanation: Ratio of shares of A,B,C = (24 x 4) : (10 x 6) : (56 x 5) = 96 : 60 : 280. Let total rent be Rs. x. Then, A's share = Rs.96x436 ∴96x436=960 ⇔x=960×43696=4360 Hence total rent of the field is Rs. 4360.
Q: In what time will Rs. 1860 amount to Rs. 2641.20 at simple interest 12% per annum? 2339 05b5cc6bee4d2b4197774d988
5b5cc6bee4d2b4197774d988- 12.9 yearsfalse
- 23.5 yearstrue
- 34.2 yearsfalse
- 44.7 yearsfalse
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Answer : 2. "3.5 years"
Explanation :
Answer: B) 3.5 years Explanation: Given that Rs. 1860 will become Rs. 2641.20 at 12% => Simple Interest = 2641.20 - 1860 = Rs. 781.20 We know I = PTR/100 => 781.20 x 100 = 1860 x T x 12 => T = 78120/1860x12 => T = 78120/22320 => T = 3.5 years.
Q: Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ? 2331 05b5cc6c5e4d2b4197774dd23
5b5cc6c5e4d2b4197774dd23- 15.75 kmsfalse
- 27.36 kmstrue
- 38.2 kmsfalse
- 46.98 kmsfalse
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Answer : 2. "7.36 kms"
Explanation :
Answer: B) 7.36 kms Explanation: Total running distance in four weeks = (24 x 240) + (4 x 400) = 5760 + 1600 = 7360 meters = 7360/1000 => 7.36 kms
Q: P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ? 2327 05b5cc6c7e4d2b4197774de73
5b5cc6c7e4d2b4197774de73- 199true
- 2100false
- 389false
- 41false
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Answer : 1. "99"
Explanation :
Answer: A) 99 Explanation: Let, Distance between A and B = d Distance travelled by P while it meets Q = d + 11 Distance travelled by Q while it meets P = d – 11 Distance travelled by Q while it meets R = d + 9 Distance travelled by R while it meets Q = d – 9 Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11 The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9 But given Ratio of speeds of P & R => P : R = 3 : 2 SPSR = SPSQxSQSR = d+11d+9d-11d-9 => d+11d+9d-11d-9 = 3/2 => d = 1, 99 => d = 99 satisfies. Therefore, Distance between A and B = 99
Q: The average temperature of Monday to Wednesday was 37 C and of Tuesday to Thursday was 34 C. If the temperature on Thursday was 4/5 th of that of Monday, the temperature on Thursday was ? 2324 05b5cc741e4d2b4197774f986
5b5cc741e4d2b4197774f986- 135 cfalse
- 236 ctrue
- 334 cfalse
- 432 cfalse
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Answer : 2. "36 c"
Explanation :
Answer: B) 36 c Explanation: Monday + Tuesday + Wednesday = 37 x 3 -----------(1)Tuesday + Wednesday + Thursday = 34 x 3---------(2)Thursday = 4/5 of Monday ------------------(3)subtract eqn (1) from (2) we get,Thursday - Monday = -9 => Monday - Thursday = 9.......(4)From (3) & (4), we get So,Thursday = 36 C

