Quantitative Aptitude Practice Question and Answer
8Q: What is the probability that a leap year has 53 Saturdays and 52 Sundays ? 2585 05b5cc6dfe4d2b4197774eada
5b5cc6dfe4d2b4197774eada- 11/7true
- 22/7false
- 31/2false
- 43/2false
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Answer : 1. "1/7"
Explanation :
Answer: A) 1/7 Explanation: A leap year has 52 weeks and two daysTotal number of cases = 7Number of favourable cases = 1i.e., {Friday, Saturday} Required Probability = 1/7
Q: If (2a + 3b)/(5a - 3b) = 23/5 , then the value of ba is ? 2580 05b5cc761e4d2b4197774fd39
5b5cc761e4d2b4197774fd39- 15false
- 24false
- 320true
- 428false
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Answer : 3. "20"
Explanation :
Answer: C) 20 Explanation: Given (2a + 3b)/(5a - 3b) = 23/5 => 10a + 15b = 115a - 69b=> 105a = 84b => 5a = 4b a/b = 4/5 => a=4 & b=5=> bxa = 5x4 = 20.
Q: Two trains 85 m and 75 m long are running in same direction with speeds of 62 km/hr and 44 km/hr respectively. In what time will the first train cross the second train ? 2579 15b5cc783e4d2b41977750214
5b5cc783e4d2b41977750214- 122 secfalse
- 232 sectrue
- 342 secfalse
- 452 secfalse
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Answer : 2. "32 sec"
Explanation :
Answer: B) 32 sec Explanation: Given that, 1st train speed = 62 km/hr 2nd train speed = 44 km/hr Hence the relative speed of two trains is : 62-44 = 18 km/hr = 18×518 m/s = 5 m/s. There fore, the first train crosses the second train i.e (85+75)mts of distance with a speed of 5m/s in, time = distancespeed = 85+755 = 32 sec.
Q: If 5th March, 2005 is Monday, what was the day of the week on 5th March, 2004 ? 2575 05b5cc72ce4d2b4197774f74b
5b5cc72ce4d2b4197774f74b- 1Sundaytrue
- 2Mondayfalse
- 3Tuesdayfalse
- 4Wednesdayfalse
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Answer : 1. "Sunday"
Explanation :
Answer: A) Sunday Explanation: The year 2004 is a leap year. So, it has 2 odd days. But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only. The day on 5th March, 2005 will be 1 day beyond the day on 5th March, 2004. Given that, 5th March, 2005 is Monday. 5th March, 2004 is Sunday (1 day before to 5th March, 2005).
Q: A person says that his son is 5 times as old as his daughter and his wife is 5 times older than his son and he is twice the age of his wife . The sum total of all the ages equals the age of the grand mother who celebrated her 81st birthday today. How old was his son? 2572 05b5cc715e4d2b4197774f413
5b5cc715e4d2b4197774f413- 150 yrstrue
- 225 yrsfalse
- 372 yrsfalse
- 440 yrsfalse
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Answer : 1. "50 yrs"
Explanation :
Answer: A) 50 yrs Explanation: Let the daughter age be 'x'Therefore, Son age = 5x, Mother age = 25x, Person age = 50x. Thus we get, x+5x+25x+50x = 8181x = 81x = 1 Daughter's age = 1, Son's = 5, Mother's = 25, Person's age = 50.
Q: The angles of a quadrilateral are in the ratio of 2:4:7:5. The smallest angle of the quadrilateral is equal to the smallest angle of a triangle. One of the angles of the triangle is twice the smallest angle of the triangle. What is the second largest angle of the triangle ? 2572 05b5cc72ce4d2b4197774f764
5b5cc72ce4d2b4197774f764- 180 degreesfalse
- 260 degreestrue
- 3120 degreesfalse
- 440 degreesfalse
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Answer : 2. "60 degrees"
Explanation :
Answer: B) 60 degrees Explanation: Given the angles of a quadrilateral are in the ratio of 2:4:7:5Let the angles of a quadrilateral are 2x, 4x, 7x, 5xBut we know that sum of the angles = 360 degrees.=> 2x + 4x + 7x + 5x = 360=> x = 20Therfore, the smallest angle of the quadrilateral = 2x = 2x20 = 40 degrees.One of the angle of the triangle = 2 x 40 = 80 degreesThe other angle is 180 - (40 + 80) = 60 degrees. Hence the second largest angle of the triangle is 60 degrees.
Q: What is the remainder when 1523+2323 is divided by 19 ? 2570 05b5cc77ae4d2b4197775014c
5b5cc77ae4d2b4197775014c- 14false
- 23false
- 31false
- 40true
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Answer : 4. "0"
Explanation :
Answer: D) 0 Explanation: 1523+2323=19-423+19+423 The remainder on dividing by 19 will be -423+423= 0.
Q: 80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 2569 05b5cc6d3e4d2b4197774e4c8
5b5cc6d3e4d2b4197774e4c8- 1120 litfalse
- 2140 litfalse
- 3110 litfalse
- 4150 littrue
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Answer : 4. "150 lit"
Explanation :
Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.