Quantitative Aptitude Practice Question and Answer
8Q: K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ? 2413 05b5cc741e4d2b4197774f9e5
5b5cc741e4d2b4197774f9e5- 112 pmtrue
- 21 pmfalse
- 311 amfalse
- 411:30 amfalse
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Answer : 1. "12 pm"
Explanation :
Answer: A) 12 pm Explanation: let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon.
Q: Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ? 2412 05b5cc6c5e4d2b4197774dd23
5b5cc6c5e4d2b4197774dd23- 15.75 kmsfalse
- 27.36 kmstrue
- 38.2 kmsfalse
- 46.98 kmsfalse
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Answer : 2. "7.36 kms"
Explanation :
Answer: B) 7.36 kms Explanation: Total running distance in four weeks = (24 x 240) + (4 x 400) = 5760 + 1600 = 7360 meters = 7360/1000 => 7.36 kms
Q: If x is a whole number, then x²(x² - 1) is always divisible by ? 2412 05b5cc761e4d2b4197774fd58
5b5cc761e4d2b4197774fd58- 14false
- 28false
- 312true
- 4Nonefalse
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Answer : 3. "12"
Explanation :
Answer: C) 12 Explanation: we can do this by trial and error method. Putting x = 2,we get 2²(2² - 1) = 12.checking with other integers, the above equation always gives a value which is a multiple of 12,So, x²(x² - 1) is always divisible by 12.
Q: In how many ways the letters of the word NUMERICAL can be arranged so that the consonants always occupy the even places ? 2400 05b5cc6cde4d2b4197774e1e0
5b5cc6cde4d2b4197774e1e0- 15!false
- 26!false
- 34!false
- 4Can't determinetrue
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Answer : 4. "Can't determine"
Explanation :
Answer: D) Can't determine Explanation: NUMERICAL has 9 positions in which 2, 4, 6, 8 are even positions. And it contains 5 consonents i.e, N, M, R, C & L. Hence this cannot be done as 5 letters cannot be placed in 4 positions. Therefore, Can't be determined.
Q: A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is : 2399 05b5cc783e4d2b419777501e7
5b5cc783e4d2b419777501e7- 19.5 km/hrfalse
- 210 km/hrtrue
- 310.5 km/hrfalse
- 411 km/hrfalse
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Answer : 2. "10 km/hr"
Explanation :
Answer: B) 10 km/hr Explanation: Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr. Therefore, Man's rate against the current = (12.5 - 2.5) = 10 km/hr.
Q: A 250 metre long train crosses a pole in 15 seconds. What is its speed in km/hour? 2394 05d15fcbb5fdb2c68495d9dff
5d15fcbb5fdb2c68495d9dff- 190false
- 245false
- 370false
- 4None of thesetrue
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Answer : 4. "None of these"
Q: 80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 2388 05b5cc6d3e4d2b4197774e4c8
5b5cc6d3e4d2b4197774e4c8- 1120 litfalse
- 2140 litfalse
- 3110 litfalse
- 4150 littrue
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Answer : 4. "150 lit"
Explanation :
Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.
Q: Find the Odd One Out? 3 24 186 1008 5040 20160 2382 05b5cc6a8e4d2b4197774ceac
5b5cc6a8e4d2b4197774ceac- 124false
- 220160false
- 3186true
- 45040false
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Answer : 3. "186"
Explanation :
Answer: C) 186 Explanation: The given number series is 3 24 186 1008 5040 20160 Here the given series follows a pattern that, 3 3 x 8 = 24 24 x 7 = 168 not 186 168 x 6 = 1008 1008 x 5 = 5040 5040 x 4 = 20160 Hence the Odd One in the number series is 186.

