Quantitative Aptitude Practice Question and Answer
8Q: One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture. 2303 05b5cc75ee4d2b4197774fcc0
5b5cc75ee4d2b4197774fcc0- 127 %true
- 226 %false
- 329 %false
- 421 %false
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Answer : 1. "27 %"
Explanation :
Answer: A) 27 % Explanation: Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135 X = 27 So, required percentage of benzene = 27 %
Q: Ronika deposited Rs.7000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much ? 2302 05b5cc6d4e4d2b4197774e5c5
5b5cc6d4e4d2b4197774e5c5- 19850false
- 29500false
- 39620true
- 49760false
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Answer : 3. "9620"
Explanation :
Answer: C) 9620 Explanation: As the interest rate increases by 2%=> (7000x3x2)/100 = 420 9200 -------- 9620
Q: A person got Rs.48 more when he invested a certain sum at compound interest instead of simple interest for two years at 8% p.a. Find the sum ? 2301 05b5cc6e0e4d2b4197774eb61
5b5cc6e0e4d2b4197774eb61- 1Rs.8000false
- 2Rs.6500false
- 3Rs.7500true
- 4Rs.5000false
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Answer : 3. "Rs.7500"
Explanation :
Answer: C) Rs.7500 Explanation: p=d×1002R2 Where d is difference, r is rate of interest. => (48 x 100 x 100) / 8 x 8 = Rs.7500
Q: If Reena’s age was twice of her present age, when subtracted from four times three years from hence, with three times the three years before her present age. What will be her age after one year ? 2299 05b5cc70ee4d2b4197774f37b
5b5cc70ee4d2b4197774f37b- 122 yrstrue
- 221 yrsfalse
- 320 yrsfalse
- 424 yrsfalse
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Answer : 1. "22 yrs"
Explanation :
Answer: A) 22 yrs Explanation: Let Reena’s present age be 'K' yrs.Given:{(K+3) x 4} - {(K-3) x 3)} => K = 21 yrsSo her present age is 21 yrs.Then, her age after 1 year is 22 yrs.
Q: 80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 2299 05b5cc6d3e4d2b4197774e4c8
5b5cc6d3e4d2b4197774e4c8- 1120 litfalse
- 2140 litfalse
- 3110 litfalse
- 4150 littrue
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Answer : 4. "150 lit"
Explanation :
Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.
Q: The first 8 alphabets are written down at random. what is the probability that the letters b,c,d,e always come together ? 2297 05b5cc6d3e4d2b4197774e4d7
5b5cc6d3e4d2b4197774e4d7- 11/7false
- 28!false
- 37!false
- 41/14true
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Answer : 4. "1/14"
Explanation :
Answer: D) 1/14 Explanation: The 8 letters can be written in 8! ways.n(S) = 8!Let E be the event that the letters b,c,d,e always come together when the first 8 alphabets are written down.Now the letters a, (bcde), f, g and h can be arranged in 5! ways.The letters b,c,d and e can be arranged themselves in 4! ways.n(E) = 5! x 4!Now, the required P(E) = n(E)/n(S) = 5! x 4!/8! = 1/14Hence the answer is 1/14.
Q: If (2a + 3b)/(5a - 3b) = 23/5 , then the value of ba is ? 2295 05b5cc761e4d2b4197774fd39
5b5cc761e4d2b4197774fd39- 15false
- 24false
- 320true
- 428false
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Answer : 3. "20"
Explanation :
Answer: C) 20 Explanation: Given (2a + 3b)/(5a - 3b) = 23/5 => 10a + 15b = 115a - 69b=> 105a = 84b => 5a = 4b a/b = 4/5 => a=4 & b=5=> bxa = 5x4 = 20.
Q: If 5th March, 2005 is Monday, what was the day of the week on 5th March, 2004 ? 2292 05b5cc72ce4d2b4197774f74b
5b5cc72ce4d2b4197774f74b- 1Sundaytrue
- 2Mondayfalse
- 3Tuesdayfalse
- 4Wednesdayfalse
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Answer : 1. "Sunday"
Explanation :
Answer: A) Sunday Explanation: The year 2004 is a leap year. So, it has 2 odd days. But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only. The day on 5th March, 2005 will be 1 day beyond the day on 5th March, 2004. Given that, 5th March, 2005 is Monday. 5th March, 2004 is Sunday (1 day before to 5th March, 2005).