Quantitative Aptitude Practice Question and Answer
8Q: In what time will Rs. 1860 amount to Rs. 2641.20 at simple interest 12% per annum? 2169 05b5cc6bee4d2b4197774d988
5b5cc6bee4d2b4197774d988- 12.9 yearsfalse
- 23.5 yearstrue
- 34.2 yearsfalse
- 44.7 yearsfalse
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Answer : 2. "3.5 years"
Explanation :
Answer: B) 3.5 years Explanation: Given that Rs. 1860 will become Rs. 2641.20 at 12% => Simple Interest = 2641.20 - 1860 = Rs. 781.20 We know I = PTR/100 => 781.20 x 100 = 1860 x T x 12 => T = 78120/1860x12 => T = 78120/22320 => T = 3.5 years.
Q: The angles of a quadrilateral are in the ratio of 2:4:7:5. The smallest angle of the quadrilateral is equal to the smallest angle of a triangle. One of the angles of the triangle is twice the smallest angle of the triangle. What is the second largest angle of the triangle ? 2168 05b5cc72ce4d2b4197774f764
5b5cc72ce4d2b4197774f764- 180 degreesfalse
- 260 degreestrue
- 3120 degreesfalse
- 440 degreesfalse
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Answer : 2. "60 degrees"
Explanation :
Answer: B) 60 degrees Explanation: Given the angles of a quadrilateral are in the ratio of 2:4:7:5Let the angles of a quadrilateral are 2x, 4x, 7x, 5xBut we know that sum of the angles = 360 degrees.=> 2x + 4x + 7x + 5x = 360=> x = 20Therfore, the smallest angle of the quadrilateral = 2x = 2x20 = 40 degrees.One of the angle of the triangle = 2 x 40 = 80 degreesThe other angle is 180 - (40 + 80) = 60 degrees. Hence the second largest angle of the triangle is 60 degrees.
Q: 80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 2168 05b5cc6d3e4d2b4197774e4c8
5b5cc6d3e4d2b4197774e4c8- 1120 litfalse
- 2140 litfalse
- 3110 litfalse
- 4150 littrue
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Answer : 4. "150 lit"
Explanation :
Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.
Q: The average temperature of Monday to Wednesday was 37 C and of Tuesday to Thursday was 34 C. If the temperature on Thursday was 4/5 th of that of Monday, the temperature on Thursday was ? 2168 05b5cc741e4d2b4197774f986
5b5cc741e4d2b4197774f986- 135 cfalse
- 236 ctrue
- 334 cfalse
- 432 cfalse
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Answer : 2. "36 c"
Explanation :
Answer: B) 36 c Explanation: Monday + Tuesday + Wednesday = 37 x 3 -----------(1)Tuesday + Wednesday + Thursday = 34 x 3---------(2)Thursday = 4/5 of Monday ------------------(3)subtract eqn (1) from (2) we get,Thursday - Monday = -9 => Monday - Thursday = 9.......(4)From (3) & (4), we get So,Thursday = 36 C
Q: The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned ? 2163 05b5cc6dee4d2b4197774ea74
5b5cc6dee4d2b4197774ea74- 1Rs. 11828.80false
- 2Rs. 19828.80true
- 3Rs. 9828.80false
- 4Rs. 19328.80false
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Answer : 2. "Rs. 19828.80"
Explanation :
Answer: B) Rs. 19828.80 Explanation: Let the sum be Rs. P P{ 1+81002- 1 } = 2828.80 It is in the form of a2-b2 = a+ba-b P(8/100)(2 + 8/100) = 2828.80 P = 2828.80 / (0.08)(2.08) = 1360/0.08 = 17000 Principal + Interest = Rs. 19828.80
Q: Ronika deposited Rs.7000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much ? 2155 05b5cc6d4e4d2b4197774e5c5
5b5cc6d4e4d2b4197774e5c5- 19850false
- 29500false
- 39620true
- 49760false
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Answer : 3. "9620"
Explanation :
Answer: C) 9620 Explanation: As the interest rate increases by 2%=> (7000x3x2)/100 = 420 9200 -------- 9620
Q: In what ratio must wheat at Rs. 3.20/kg be mixed with wheat at Rs. 2.90/kg so that the mixture be worth Rs. 3/kg? 2148 05b5cc639e4d2b4197774baa0
5b5cc639e4d2b4197774baa0- 11:2false
- 23:2false
- 32:1true
- 42:3false
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Answer : 3. "2:1"
Explanation :
Answer: C) 2:1 Explanation: Given rate of wheat at cheap = Rs. 2.90/kg Rate of wheat at cost = Rs. 3.20/kg Mixture rate = Rs. 3/kg Ratio of mixture = 2.90 3.20 3 (3.20 - 3 = 0.20) (3 - 2.90 = 0.10) 0.20 : 0.10 = 2:1 Hence, wheat at Rs. 3.20/kg be mixed with wheat at Rs. 2.90/kg in the ratio of 2:1, so that the mixture be worth Rs. 3/kg.
Q: Find out the wrong number in the following series ? 2880, 480, 92, 24, 8, 4, 4 2146 05b5cc720e4d2b4197774f64f
5b5cc720e4d2b4197774f64f- 1480false
- 292true
- 324false
- 44false
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Answer : 2. "92"
Explanation :
Answer: B) 92 Explanation: The given series of numbers follow the rule that, 2880/6 = 480480/5 = 9696/4 = 2424/3 = 88/2 = 44/1 = 4 But 92 is not in the rule. It is the wrong number in the given series.

