Quantitative Aptitude Practice Question and Answer
8Q: There are Rs.300 in a box in denomination of Rs.1, 50 paisa and 25 paisa and in the ratio 2:4:8. Find the number of coins of 25 paisa 7000 35d1b179d1fc62311c773687f
5d1b179d1fc62311c773687f- 1300false
- 2200false
- 3400true
- 4100false
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Answer : 3. "400"
Q: In a purse there are 30 coins, twenty one-rupee and remaining 50-paise coins. Eleven coins are picked simultaneously at random and are placed in a box. If a coin is now picked from the box, find the probability of it being a rupee coin? 6969 05b5cc60de4d2b4197774b618
5b5cc60de4d2b4197774b618- 14/7false
- 22/3true
- 31/2false
- 45/6false
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Answer : 2. "2/3"
Explanation :
Answer: B) 2/3 Explanation: Total coins 30 In that, 1 rupee coins 20 50 paise coins 10Probability of total 1 rupee coins = 20C11 Probability that 11 coins are picked = 30C11 Required probability of a coin now picked from the box is 1 rupee = 20C11/30C11 = 2/3.
Q: Which is the next number in the sequence: 1, 3, 6, 11, 20, 37, ?? 6944 05b5cc699e4d2b4197774c6fb
5b5cc699e4d2b4197774c6fb- 149false
- 256false
- 364false
- 470true
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Answer : 4. "70"
Explanation :
Answer: D) 70 Explanation: Here the given series is 1, 3, 6, 11, 20, 37, ??, and the logic behind the series is 1 x 2 + 1 = 3 3 x 2 + 0 = 6 6 x 2 + (-1) = 11 11 x 2 + (-2) = 20 20 x 2 + (-3) = 37 37 x 2 + (-4) = 70 Hence, the next number in the given series is 70.
Q: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples ? 6883 05b5cc6e3e4d2b4197774ec98
5b5cc6e3e4d2b4197774ec98- 16/7false
- 219/21false
- 37/31false
- 45/21true
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Answer : 4. "5/21"
Explanation :
Answer: D) 5/21 Explanation: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁) As remaining person can be any one among three couples left. Required probability = (⁵C₂ x ⁶C₁)/¹⁰C₅= (10 x 6)/252 = 5/21
Q: 30% of first number is 75% of the second number. What is the respective ratio of the first number to the second number? 6864 15d1b04cd8a754124194a751a
5d1b04cd8a754124194a751a- 15:2true
- 25:3false
- 325:14false
- 415:16false
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Answer : 1. "5:2"
Q: Find the missing number? 15, 30, ? , 40, 8, 48 6845 05b5cc6afe4d2b4197774d264
5b5cc6afe4d2b4197774d264- 121false
- 28false
- 319false
- 410true
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Answer : 4. "10"
Explanation :
Answer: D) 10 Explanation: Given nuber series is 15, 30, ? , 40, 8, 48 Here the number series follows a pattern that 15 15 x 2 = 30 30 ÷ 3 = 10 10 x 4 = 40 40 ÷ 5 = 8 8 x 6 = 48 Hence, the missing number in the series is 10.
Q: Which two months in a year have the same calendar? 6800 05b5cc694e4d2b4197774c498
5b5cc694e4d2b4197774c498- 1October, Decemberfalse
- 2April, Novemberfalse
- 3June, Octoberfalse
- 4April, Julytrue
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Answer : 4. "April, July"
Explanation :
Answer: D) April, July Explanation: If the period between the two months is divisible by 7, then that two months will have the same calender . Now,(a). October + November = 31 + 30 = 61 (not divisible by 7) (b). Apr. + May + June + July + Aug. + Sep. + Oct. = 30 + 31 + 30 + 31 + 31 +30 + 31 = 213 (not divisible by 7) (c). June + July + Aug. + Sep. = 30 + 31 + 31 + 30 = 122 (not divisible by 7) (d). Apr. + May + June = 30 + 31 + 30 = 91 (divisible by 7) Hence, April and July months will have the same calendar.
Q: The second day of a month is Sunday, What will be the last day of the next month which has 31 days ? 6743 05b5cc6dee4d2b4197774ea94
5b5cc6dee4d2b4197774ea94- 1Fridayfalse
- 2Saturdayfalse
- 3Sundayfalse
- 4Can't be determinedtrue
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Answer : 4. "Can't be determined"
Explanation :
Answer: D) Can't be determined Explanation: We cannot find out the answer because the number of days of the current month is not given.