Quantitative Aptitude Practice Question and Answer
8Q: Selling an article at a profit of 20%, Aman gets Rs. 400 more than selling at a loss of 20%. The cost price of the article is ? 2330 05b5cc6c2e4d2b4197774dbeb
5b5cc6c2e4d2b4197774dbeb- 1Rs.1000true
- 2Rs. 1020false
- 3Rs.1210false
- 4Rs.1140false
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Answer : 1. "Rs.1000"
Explanation :
Answer: A) Rs.1000 Explanation: Cost price of the article is given by = 400x100/(20+20) = Rs.1000
Q: Find the ratio of the areas of the incircle and circumcircle of a square ? 2324 05b5cc77fe4d2b419777501c9
5b5cc77fe4d2b419777501c9- 11 : 4false
- 24 : 1false
- 32 : 1false
- 41 : 2true
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Answer : 4. "1 : 2"
Explanation :
Answer: D) 1 : 2 Explanation: Let the side of the square be x. Then, its diagonal = 2x. Radius of incircle = x/2 and radius of circumcircle =2x2 . Therefore, required ratio = πx24:πx22 = 14:12=1:2
Q: Arun is a cashew merchant in Telangana. He has cashews in sealed wooden boxes of 10kg each. The price of the cashew increases by Rs.20 per kg for every year, but at the same time, 10% of the cashews are eaten by rodents every year. If the price of a 1 kg of fresh cashew is Rs.120, what is the change in his profits if he sells a sealed box after one year of storage, rather than selling it fresh ? (In Rs.) 2320 05b5cc728e4d2b4197774f719
5b5cc728e4d2b4197774f719- 1Rs. 60true
- 2Rs. 54false
- 3Rs. 80false
- 4Rs. 75false
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Answer : 1. "Rs. 60"
Explanation :
Answer: A) Rs. 60 Explanation: Price of 1kg fresh cashew = Rs.120Therefore, price of 10kg = Rs.120 x 10 = Rs.1200 10% of 10kg which eaten by rodents = 10 x 10/100 = 1kg. So, End of Year he had 10kg - 1kg = 9kg So, he sells that 9kg with Rs.20 per kg profit = 9 x 140 = 1260. He buy 10kg wooden box with cashew for Rs.1200 and sell that for Rs. 1260 So, profit = 1260 - 1200 = Rs.60 more money he get.
Q: The average of a non-zero number and its square is 11 times the number. The number is ? 2320 05b5cc72ce4d2b4197774f741
5b5cc72ce4d2b4197774f741- 122true
- 221false
- 311false
- 417false
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Answer : 1. "22"
Explanation :
Answer: A) 22 Explanation: Let the number be 'x'. x+x22 = 11x x2= 22x => x = 22.
Q: The average of five numbers is 49. The average of the first and the second numbers is 48 and the average of fourth and fifth numbers is 28. What is the third number?
2319 05d4a9cab11160f20523711a5
5d4a9cab11160f20523711a5- 192false
- 291false
- 395false
- 4Cannot determinedfalse
- 5None of thesetrue
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Answer : 5. "None of these"
Q: A man walks 6 km at a speed of 112kmph, runs 8 km at a speed of 2 kmph and goes by bus another 32 km. Speed of the bus is 8 kmph. Find the average speed of the man in kmph. 2311 05b5cc764e4d2b4197774fd8a
5b5cc764e4d2b4197774fd8a- 14314false
- 24213true
- 32413false
- 43414false
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Answer : 2. "4213"
Explanation :
Answer: B) Option B Explanation: Man walked 6 km at 1.5 kmph, again he walked 8 km at speed of 2 kmph and 40 km at a speed of 8kmphtime taken indivisually: => 6/1.5 = 4 m=> 8/2 = 4 m=> 40/8 = 5 m Average speed of man= total distance/ total time=> 54/13 = 4213 kmph
Q: The average age of the district level hockey team of eleven is 22 years.The average age gets increased by 1 year when the coach age is also included.what is the age of the coach ? 2308 05b5cc705e4d2b4197774f24e
5b5cc705e4d2b4197774f24e- 133 yrsfalse
- 234 yrstrue
- 335 yrsfalse
- 436 yrsfalse
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Answer : 2. "34 yrs"
Explanation :
Answer: B) 34 yrs Explanation: Total age of players in team = 22 x 11 = 242When coach is included, total members = 12, Avg age increases by one becomes 23Total age when coach is included = 23x12 = 276Age of coach = 276-242 = 34 yrs.
Q: 5 boys and 3 girls can together cultivate a 23 acre field in 4 days and 3 boys and 2 girls together can cultivate a 7 acre field in 2 days. How many girls will be needed together with 7 boys, if they cultivate 45 acres of field in 6 days? 2302 05b5cc60ae4d2b4197774b5bf
5b5cc60ae4d2b4197774b5bf- 14false
- 23false
- 32true
- 41false
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Answer : 3. "2"
Explanation :
Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a) 2(3b + 2g) = 7 6b + 4g = 7 ........(b) Solving (a) & (b), we get b = 1, g = 1/4 Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2. Hence, number of girls required = 2