Quantitative Aptitude Practice Question and Answer
8Q: K and L starts walking towards each other at 4 pm at speed of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet ? 1891 05b5cc6c6e4d2b4197774ddfa
5b5cc6c6e4d2b4197774ddfa- 16:00 amfalse
- 26:30 pmtrue
- 35:45 amfalse
- 45:52 pmfalse
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Answer : 2. "6:30 pm"
Explanation :
Answer: B) 6:30 pm Explanation: Suppose they meet after 'h' hours Then 3h + 4h = 17.5 7h = 17.5 h = 2.5 hours So they meet at => 4 + 2.5 = 6:30 pm
Q: Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 cm x 6 m when 10% of its volume is occupied by mortar ? 1891 05b5cc6d8e4d2b4197774e76e
5b5cc6d8e4d2b4197774e76e- 1720true
- 2600false
- 3660false
- 46000false
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Answer : 1. "720"
Explanation :
Answer: A) 720 Explanation: Let the number of bricks be 'N' 10 x 4/100 x 6 x 90/100 = 25/100 x 15/100 x 8/100 x N 10 x 4 x 6 x 90 = 15 x 2 x N => N = 720.
Q: In a mixture of three varities of oils , the ratio of their weight is 4 : 5 : 8. If 5 kg of oils of the first variety, 10 kg of the second variety and some quantity of oils of the third variety are added to the mixture, the ratio of the weights of three varieties of oils becomes as 5 : 7 : 9 in the final mixture, find the quantity of third variety of oil was ? 1884 05b5cc6cce4d2b4197774e177
5b5cc6cce4d2b4197774e177- 115 kgfalse
- 225 kgfalse
- 335 kgfalse
- 445 kgtrue
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Answer : 4. "45 kg"
Explanation :
Answer: D) 45 kg Explanation: Let the ratio of initial quantity of oils be 'x' => 4x, 5x & 8x.Let k be the quantity of third variety of oil in the final mixture.Let the ratio of initial quantity of oils be 'y'From given details,4x + 5 = 5y ..... (1)5x + 10 = 7y .....(2)8x + k = 9y ......(3) By solving (1) & (2), we getx = 5 & y = 5 From (3) => k = 5 Therefore, quantity of third variety of oil was 9y = 9(5) = 45kg.
Q: A sum is divided among K, L and M in such a way that for each rupee K gets, L gets 45 paisa and M gets 30 paisa. If the share of L is Rs. 27, what is the total amount ? 1883 05b5cc6e0e4d2b4197774eb66
5b5cc6e0e4d2b4197774eb66- 1Rs. 159false
- 2Rs. 96false
- 3Rs. 147false
- 4Rs. 105true
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Answer : 4. "Rs. 105"
Explanation :
Answer: D) Rs. 105 Explanation: K : L : M = 100 : 45 : 30 = 20 : 9 : 6 Given L share is 27 => 9 ------ 27 35 ------ ? => 105
Q: Find value of log27 +log 8 +log1000log 120 1882 15b5cc7d0e4d2b4197775120e
5b5cc7d0e4d2b4197775120e- 11/2false
- 23/2true
- 32false
- 42/3false
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Answer : 2. "3/2"
Explanation :
Answer: B) 3/2 Explanation: = log 33 + log 23+ log 103log10×3×22 =log33 12+log 23+log 10312log(10×3×22) =12log 33+3 log 2+12 log103log10+log3+log22 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32
Q: A store owner is packing books into larger boxes that measure 25 by 42 by 60 inches. If the measurement of each book is 7 by 6 by 5 inches, then how many books can be placed in the box ? 1880 05b5cc74ae4d2b4197774fad6
5b5cc74ae4d2b4197774fad6- 1175false
- 2345false
- 3265false
- 4300true
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Answer : 4. "300"
Explanation :
Answer: D) 300 Explanation: Number of books that can be placed in the larger box is given by Volume of Box / Volume of book.Now, n = 25 x 42 x 60 / 7 x 6 x 5 = 63000 / 210 = 300.Therefore, 300 books can be in that box.
Q: The marked price of a Watch is Rs.8400. It is to be sold at Rs.6896 at two successive discounts. If the first discount is 12%, the second discount is ? 1877 05b5cc720e4d2b4197774f627
5b5cc720e4d2b4197774f627- 17.2 %false
- 29.14 %false
- 37.13 %false
- 46.709 %true
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Answer : 4. "6.709 %"
Explanation :
Answer: D) 6.709 % Explanation: (100-x)% of 88% of 8400 = 6896 => 100-x10088100x8400 = 6896 => x = 6.709%
Q: Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ? 1876 05b5cc74fe4d2b4197774fb21
5b5cc74fe4d2b4197774fb21- 179true
- 277false
- 376false
- 473false
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Answer : 1. "79"
Explanation :
Answer: A) 79 Explanation: Assuming Sripad has scored the least marks in subject other than science,Then the marks he could secure in other two are 58 each.Since the average mark of all the 3 subject is 65.i.e (58+58+x)/3 = 65116 + x = 195x = 79 marks. Therefore, the maximum marks he can score in maths is 79.