Quantitative Aptitude Practice Question and Answer
8Q: Find the odd man out of the following number sequence? 3, 5, 13, 43, 167 2218 05b5cc622e4d2b4197774b820
5b5cc622e4d2b4197774b820- 1167true
- 243false
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Answer : 1. "167"
Explanation :
Answer: A) 167 Explanation: The given number series is 3, 5, 13, 43, 167 3 3 x 1 + 2 = 5 5 x 2 + 3 = 13 13 x 3 + 4 = 43 43 x 4 + 5 = 177 (not equal to 167) Hence, the odd number in the given number sequence is 167.
Q: In a Plane there are 37 straight lines, of which 13 pass through the point A and 11 pass through the point B. Besides, no three lines pass through one point, no lines passes through both points A and B , and no two are parallel. Find the number of points of intersection of the straight lines. 2218 05b5cc7d1e4d2b41977751281
5b5cc7d1e4d2b41977751281- 1525false
- 2535true
- 3545false
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Answer : 2. "535"
Explanation :
Answer: B) 535 Explanation: The number of points of intersection of 37 lines is C237. But 13 straight lines out of the given 37 straight lines pass through the same point A. Therefore instead of getting C213 points, we get only one point A. Similarly 11 straight lines out of the given 37 straight lines intersect at point B. Therefore instead of getting C211 points, we get only one point B. Hence the number of intersection points of the lines is C237-C213-C211 +2 = 535
Q: What is the next number in this series ? 4, 6, 12, 18, 30, 42, 60, ? 2216 05b5cc70be4d2b4197774f2f0
5b5cc70be4d2b4197774f2f0- 171false
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Answer : 2. "72"
Explanation :
Answer: B) 72 Explanation: With close observation, you will note that each number in the list is in the middle of two prime numbers. Thus: 4 is in the middle of 3 and 5, 6 is in the middle of 5 and 7, 12 is in the middle of 11 and 13, 18 is in the middle of 17 and 19, 30 is in the middle of 29 and 31. 42 is in the middle of 41 and 43, 60 is in the middle of 59 and 61. Therefore, the next number would be the one that is in the middle of the next two prime numbers, which is 72 (which is in the middle of 71 and 73).
Q: What is the equivalent compound ratio of 5:6::7:10::6:5 ? 2204 05b5cc6e3e4d2b4197774eccf
5b5cc6e3e4d2b4197774eccf- 17 : 9false
- 29 : 7false
- 37 : 4false
- 47 : 10true
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Answer : 4. "7 : 10"
Explanation :
Answer: D) 7 : 10 Explanation: Given 5:6 :: 7:10 :: 6:5 We know that compound ratio is calculated as a:b :: c:d :: e:f(axcxe):(bxdxf) => (5x7x6):(6x10x5)=> (210):(300)= 7:10
Q: A store owner is packing books into larger boxes that measure 25 by 42 by 60 inches. If the measurement of each book is 7 by 6 by 5 inches, then how many books can be placed in the box ? 2202 05b5cc74ae4d2b4197774fad6
5b5cc74ae4d2b4197774fad6- 1175false
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Answer : 4. "300"
Explanation :
Answer: D) 300 Explanation: Number of books that can be placed in the larger box is given by Volume of Box / Volume of book.Now, n = 25 x 42 x 60 / 7 x 6 x 5 = 63000 / 210 = 300.Therefore, 300 books can be in that box.
Q: Today is Varun's birthday. One year, from today he will be twice as old as he was 12 years ago. How old is Varun today ? 2198 05b5cc71be4d2b4197774f559
5b5cc71be4d2b4197774f559- 125 yearstrue
- 224 yearsfalse
- 323 yearsfalse
- 422 yearsfalse
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Answer : 1. "25 years"
Explanation :
Answer: A) 25 years Explanation: Let varun's age = x yrs. From the given conditions, x+1 = 2(x-12) x = 25 years.
Q: How many seconds in 10 years? 2198 05b5cc695e4d2b4197774c534
5b5cc695e4d2b4197774c534- 131523500 secfalse
- 2315360000 sectrue
- 3315423000 secfalse
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Answer : 2. "315360000 sec"
Explanation :
Answer: B) 315360000 sec Explanation: We know that, 1 year = 365 days 1 day = 24 hours 1 hour = 60 minutes 1 minute = 60 seconds. Then, 1 year = 365 x 24 x 60 x 60 seconds. = 8760 x 3600 1 year = 31536000 seconds. Hence, 10 years = 31536000 x 10 = 315360000 seconds.
Q: One girl can eat 112 chocolates in half a minute, and her boy friend can eat half as many in twice the length of time. How many chocolates can both boy and girl eat in 12 seconds ? 2197 05b5cc745e4d2b4197774fa27
5b5cc745e4d2b4197774fa27- 144false
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- 356true
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Answer : 3. "56"
Explanation :
Answer: C) 56 Explanation: Girl eats 112 chocolates in 30 sec so she can eat in 12 sec is 12 x 112/30 = 44.8 chocolates. Her boy friend can eat one-half of 112 in twice of 30 sec so he can eat 56 in 60 sec Then he can eat in 12 sec is 56 x 12/60 = 11.2 chocolates. Hence, together they can eat = 44.8 + 11.2 =56 chocolates in 12 seconds.