Quantitative Aptitude Practice Question and Answer
8Q: What is the equivalent compound ratio of 5:6::7:10::6:5 ? 1998 05b5cc6e3e4d2b4197774eccf
5b5cc6e3e4d2b4197774eccf- 17 : 9false
- 29 : 7false
- 37 : 4false
- 47 : 10true
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Answer : 4. "7 : 10"
Explanation :
Answer: D) 7 : 10 Explanation: Given 5:6 :: 7:10 :: 6:5 We know that compound ratio is calculated as a:b :: c:d :: e:f(axcxe):(bxdxf) => (5x7x6):(6x10x5)=> (210):(300)= 7:10
Q: Three friends Rudra, Siva and Anvesh start to run around a circular stadium. They complete a revolution in 24, 36 and 30 seconds respectively. After how many minutes will they meet at the starting point ? 1997 05b5cc6c2e4d2b4197774dbb4
5b5cc6c2e4d2b4197774dbb4- 160false
- 2120false
- 3360false
- 46true
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Answer : 4. "6"
Explanation :
Answer: D) 6 Explanation: For this we have to find the LCM of 24, 36 and 30 LCM of 24, 36 and 30 = 360 sec 360/60 min = 6 minutes.
Q: 5 boys and 3 girls can together cultivate a 23 acre field in 4 days and 3 boys and 2 girls together can cultivate a 7 acre field in 2 days. How many girls will be needed together with 7 boys, if they cultivate 45 acres of field in 6 days? 1997 05b5cc60ae4d2b4197774b5bf
5b5cc60ae4d2b4197774b5bf- 14false
- 23false
- 32true
- 41false
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Answer : 3. "2"
Explanation :
Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a) 2(3b + 2g) = 7 6b + 4g = 7 ........(b) Solving (a) & (b), we get b = 1, g = 1/4 Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2. Hence, number of girls required = 2
Q: K and L starts walking towards each other at 4 pm at speed of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet ? 1994 05b5cc6c6e4d2b4197774ddfa
5b5cc6c6e4d2b4197774ddfa- 16:00 amfalse
- 26:30 pmtrue
- 35:45 amfalse
- 45:52 pmfalse
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Answer : 2. "6:30 pm"
Explanation :
Answer: B) 6:30 pm Explanation: Suppose they meet after 'h' hours Then 3h + 4h = 17.5 7h = 17.5 h = 2.5 hours So they meet at => 4 + 2.5 = 6:30 pm
Q: Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ? 1993 05b5cc75ee4d2b4197774fc9d
5b5cc75ee4d2b4197774fc9d- 1Rs.2010false
- 2Rs.2200false
- 3Rs.2000true
- 4Rs.2100false
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Answer : 3. "Rs.2000"
Explanation :
Answer: C) Rs.2000 Explanation: Let money invested by Raghu = Rs. xMoney invested by Trishul = 9/10 x = 0.9xMoney invested by Vishal = 9/10x * 110/100 = 0.99xAlso, x+0.9x+0.99x = 5780= x= 5780/2.89 = 2000 Therefore, amount invested by Raghu is Rs. 2000.
Q: 7 years ago, the ratio of the ages of Anirudh to that of Bhavana, was 7:9. Chandhu is 12 years older than Anirudh and 12 years younger than Bhavana. What is Chandhu's present age? 1991 05b5cc6bbe4d2b4197774d849
5b5cc6bbe4d2b4197774d849- 191 yearsfalse
- 2115 yearsfalse
- 3103 yearstrue
- 4Can't be determinedfalse
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Answer : 3. "103 years"
Explanation :
Answer: C) 103 years Explanation: Let present Anirudh's age be 'A' and Bhavana's age be 'B' Given seven years, their ratio is 7:9 => A-7 : B-7 = 7 : 9 => 9A - 7B = 14 .......(1) And given, Chandhu is 12 years older than A nad 12 years younger than B => C = A + 12....(2) => B = C + 12 => B = A + 12 + 12 .....(From (2)) => B = A + 24 ....(3) Put (3) in (1) 9A - 7(A+24) = 14 9A - 7A - 168 = 14 2A = 182 => A = 91 years => C = A + 12 = 91 +12 = 103 years.
Q: If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr, Find the time taken by boat to cover 126 km downstream. 1990 05b5cc6afe4d2b4197774d278
5b5cc6afe4d2b4197774d278- 12.8 hrsfalse
- 22.7 hrstrue
- 32.6 hrsfalse
- 42.5 hrsfalse
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Answer : 2. "2.7 hrs"
Explanation :
Answer: B) 2.7 hrs Explanation: Let Speed of boat in still water = b Let Speed of still water = w Then we know that, Speed of Upstream = U = boat - water Speed of Downstream = D = boat + water Given, U + D = 82 b - w + b + w = 82 2b = 82 => b = 41 kmph From the given data, 41 - w = 105/3 = 35 w = 6 kmph Now, b + w = 126/t => 41 + 6 = 126/t => t = 126/47 = 2.68 hrs.
Q: Ram sell his goods 25% cheaper than Shyam and 25% dearer than Bram. How much % is Bram's good cheaper than Shyam ? 1986 05b5cc70be4d2b4197774f2f6
5b5cc70be4d2b4197774f2f6- 160%false
- 240%true
- 350%false
- 430%false
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Answer : 2. "40%"
Explanation :
Answer: B) 40% Explanation: Lets say shyam sells at 100, Since Ram sells 25% cheaper than Shyam, Therefor Ram sells at less than 25% of100 or 75 rs. Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or 125% of x (say x price of bram )=75rs.or 100% of x =60rs.hence price of bram is 60rs. now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%. Hence Brams Good is 40% cheaper than that of Shyam's good.