Quantitative Aptitude Practice Question and Answer
8Q: There are 10 Letters and 10 correspondingly 10 different Address. If the letter are put into envelope randomly, then find the Probability that Exactly 9 letters will at the Correct Address ? 2181 05b5cc705e4d2b4197774f1ee
5b5cc705e4d2b4197774f1ee- 11/10false
- 21/9false
- 31false
- 40true
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Answer : 4. "0"
Explanation :
Answer: D) 0 Explanation: As we know we have 10 letter and 10 different address and one more information given that exactly 9 letter will at the correct address....so the remaining one letter automatically reach to their correct address P(E) = favorable outcomes /total outcomesHere favorable outcomes are '0'.So probability is '0'.
Q: If a+b=5 and 3a+2b=20,then (3a+b)will be : 2181 05b5cc783e4d2b419777501fb
5b5cc783e4d2b419777501fb- 120false
- 215false
- 325true
- 430false
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Answer : 3. "25"
Explanation :
Answer: C) 25 Explanation: a+b=5 ...(1) and 3a+2b=20 ...(2) Multiplying (1) by 2 and subtracting from (2), we get : a=10. Putting a=10 in (1), we get : b=-5 Therefore, (3a+b) = 3 x 10+(-5)=30-5=25.
Q: In a mixture of three varities of oils , the ratio of their weight is 4 : 5 : 8. If 5 kg of oils of the first variety, 10 kg of the second variety and some quantity of oils of the third variety are added to the mixture, the ratio of the weights of three varieties of oils becomes as 5 : 7 : 9 in the final mixture, find the quantity of third variety of oil was ? 2181 05b5cc6cce4d2b4197774e177
5b5cc6cce4d2b4197774e177- 115 kgfalse
- 225 kgfalse
- 335 kgfalse
- 445 kgtrue
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Answer : 4. "45 kg"
Explanation :
Answer: D) 45 kg Explanation: Let the ratio of initial quantity of oils be 'x' => 4x, 5x & 8x.Let k be the quantity of third variety of oil in the final mixture.Let the ratio of initial quantity of oils be 'y'From given details,4x + 5 = 5y ..... (1)5x + 10 = 7y .....(2)8x + k = 9y ......(3) By solving (1) & (2), we getx = 5 & y = 5 From (3) => k = 5 Therefore, quantity of third variety of oil was 9y = 9(5) = 45kg.
Q: Madhu started a business and he invested in 76000, After some month, Amar came to join with him and invest 57000.The end of the year the total profit was divided among them into ratio form 2 : 1.Find after how many months Amar join. 2178 05b5cc767e4d2b4197774fe27
5b5cc767e4d2b4197774fe27- 17 monthsfalse
- 28 monthsfalse
- 33 monthsfalse
- 44 monthstrue
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Answer : 4. "4 months"
Explanation :
Answer: D) 4 months Explanation: we can assume that Amar join into business after x months. So Amar money was invest into (12 – x ) months. 76000×1257000×(12-x)=21 --> 912000 = 114000 ( 12 – x ) = 114 ( 12 – x ) = 912 --> x = 4 After 4 months amar join the business.
Q: Find the odd man out in the following number series? 71, 88, 113, 150, 203, 277 2177 05b5cc678e4d2b4197774c158
5b5cc678e4d2b4197774c158- 1277true
- 2203false
- 3150false
- 4113false
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Answer : 1. "277"
Explanation :
Answer: A) 277 Explanation: The given number series is 71 88 113 150 203 277 +17 +25 +37 +53 +74 +8 +12 +16 +21 +4 +4 +5 The series should be 71 88 112 150 203 276 i.e, the differences of the difference should be +4. Hence, the odd man in the given series is 277.
Q: Find value of log27 +log 8 +log1000log 120 2172 15b5cc7d0e4d2b4197775120e
5b5cc7d0e4d2b4197775120e- 11/2false
- 23/2true
- 32false
- 42/3false
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Answer : 2. "3/2"
Explanation :
Answer: B) 3/2 Explanation: = log 33 + log 23+ log 103log10×3×22 =log33 12+log 23+log 10312log(10×3×22) =12log 33+3 log 2+12 log103log10+log3+log22 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32
Q: If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr, Find the time taken by boat to cover 126 km downstream. 2171 05b5cc6afe4d2b4197774d278
5b5cc6afe4d2b4197774d278- 12.8 hrsfalse
- 22.7 hrstrue
- 32.6 hrsfalse
- 42.5 hrsfalse
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Answer : 2. "2.7 hrs"
Explanation :
Answer: B) 2.7 hrs Explanation: Let Speed of boat in still water = b Let Speed of still water = w Then we know that, Speed of Upstream = U = boat - water Speed of Downstream = D = boat + water Given, U + D = 82 b - w + b + w = 82 2b = 82 => b = 41 kmph From the given data, 41 - w = 105/3 = 35 w = 6 kmph Now, b + w = 126/t => 41 + 6 = 126/t => t = 126/47 = 2.68 hrs.
Q: Adam and Smith are working on a project. Adam takes 6 hrs to type 36 pages on a computer, while Smith takes 5 hrs to type 40 pages. How much time will they take, working together on two different computers to type a project of 120 pages? 2171 05b5cc76fe4d2b4197774ff58
5b5cc76fe4d2b4197774ff58- 18 hrs 45 minfalse
- 28 hrs 42 minfalse
- 38 hrsfalse
- 48 hrs 34 mintrue
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Answer : 4. "8 hrs 34 min"
Explanation :
Answer: D) 8 hrs 34 min Explanation: Number of pages typed by Adam in 1 hour = 36/6 = 6 Number of pages typed by Smith in 1 hour = 40/5 = 8Number of pages typed by both in 1 hour = (6 + 8) = 14Time taken by both to type 110 pages = (120 * 1/14) = 847 = 8 hrs 34 min.

