Quantitative Aptitude Practice Question and Answer
8Q: Eighteen years ago, a mother was three times as old as her daughter. Now the mother is only twice as old as her daughter. Then the sum of the present ages of daughter and the mother is ? 1857 05b5cc6f8e4d2b4197774f06d
5b5cc6f8e4d2b4197774f06d- 184 yrsfalse
- 296 yrsfalse
- 3116 yrsfalse
- 4108 yrstrue
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Answer : 4. "108 yrs"
Explanation :
Answer: D) 108 yrs Explanation: Let the present ages of the mother and daughter be 2x and x years respectively. Then, (2x - 18) = 3(x - 18) => x = 36 Required sum = (2x + x) = 108 years.
Q: The largest 4 digit number exactly divisible by 88 is ? 1857 05b5cc728e4d2b4197774f6d2
5b5cc728e4d2b4197774f6d2- 19944true
- 29768false
- 38888false
- 49988false
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Answer : 1. "9944"
Explanation :
Answer: A) 9944 Explanation: The largest 4 digit number is = 9999After dividing 9999 with 88, we get 55 as remainderso largest 4 digit number divisible by 88 = 9999-55 = 9944.
Q: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey ? 1854 05b5cc6dce4d2b4197774e997
5b5cc6dce4d2b4197774e997- 15 kmphfalse
- 27 kmphfalse
- 33 kmphfalse
- 44 kmphtrue
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Answer : 4. "4 kmph"
Explanation :
Answer: D) 4 kmph Explanation: Speed of Man = 4.5 kmphSpeed of stream = 1.5 kmphSpeed in DownStream = 6 kmphSpeed in UpStream = 3 kmphAverage Speed = (2 x 6 x 3)/9 = 4 kmph.
Q: Find the odd man out of the following number sequence? 3, 5, 13, 43, 167 1852 05b5cc622e4d2b4197774b820
5b5cc622e4d2b4197774b820- 1167true
- 243false
- 313false
- 45false
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Answer : 1. "167"
Explanation :
Answer: A) 167 Explanation: The given number series is 3, 5, 13, 43, 167 3 3 x 1 + 2 = 5 5 x 2 + 3 = 13 13 x 3 + 4 = 43 43 x 4 + 5 = 177 (not equal to 167) Hence, the odd number in the given number sequence is 167.
Q: There is 50% increase in an amount in 5 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate ? 1852 05b5cc767e4d2b4197774fe01
5b5cc767e4d2b4197774fe01- 1Rs. 5422false
- 2Rs. 5489false
- 3Rs. 3972true
- 4Rs. 6145false
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Answer : 3. "Rs. 3972"
Explanation :
Answer: C) Rs. 3972 Explanation: Let p = Rs. 100. Then, S.I is Rs. 50 and time = 5 years. ∴ R = 100×50100×5= 10% p.a. Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a. C.I. = Rs. 12000×1+101003-1= Rs. 3972
Q: Which value is equal to 5% of 1,500? 1851 05b5cc666e4d2b4197774bee9
5b5cc666e4d2b4197774bee9- 135false
- 255false
- 375true
- 445false
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Answer : 3. "75"
Explanation :
Answer: C) 75 Explanation: In the question it is asked for 5% of 1500 5 x 1500/100 = 15 x 5 = 75. Hence, 5% of 1,500 is equal to 75.
Q: 5 boys and 3 girls can together cultivate a 23 acre field in 4 days and 3 boys and 2 girls together can cultivate a 7 acre field in 2 days. How many girls will be needed together with 7 boys, if they cultivate 45 acres of field in 6 days? 1847 05b5cc60ae4d2b4197774b5bf
5b5cc60ae4d2b4197774b5bf- 14false
- 23false
- 32true
- 41false
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Answer : 3. "2"
Explanation :
Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a) 2(3b + 2g) = 7 6b + 4g = 7 ........(b) Solving (a) & (b), we get b = 1, g = 1/4 Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2. Hence, number of girls required = 2
Q: 20 men went to a restaurant. Ninteen of them paid Rs.70 each and the twentieth man paid Rs.90.25 more than the average of all the 20 men. What is the total bill ? 1845 05b5cc73ae4d2b4197774f8b5
5b5cc73ae4d2b4197774f8b5- 1Rs. 1495true
- 2Rs. 548false
- 3Rs. 850false
- 4Rs. 1750false
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Answer : 1. "Rs. 1495"
Explanation :
Answer: A) Rs. 1495 Explanation: Let the average bill paid by twenty members = 'x' But 19 men paid each = Rs. 70 20th man paid Rs. 90.25 more than the avg bill of 20 = x + 90.25 20x = 19(70) + x + 90.2519x = 1330 + 90.2519x = 1420.25x = 1420.25/19 = Rs. 74.75 But the total bill = 20 x 74.75 = Rs. 1495.