Quantitative Aptitude Practice Question and Answer
8Q: Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ? 2256 05b5cc6c7e4d2b4197774de6e
5b5cc6c7e4d2b4197774de6e- 1108false
- 2107false
- 3109true
- 4110false
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Answer : 3. "109"
Explanation :
Answer: C) 109 Explanation: From given data, R : M = 5 : 7 M : A = 5 : 7 R : M : A = 25 : 35 : 49 25 + 35 + 49 = 109
Q: Two numbers are respectively 40% and 30% more than a third number. The second number expressed in terms of percentage of the first is ? 2250 05b5cc75ce4d2b4197774fc43
5b5cc75ce4d2b4197774fc43- 192.8%true
- 284.23%false
- 387.14%false
- 494.1%false
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Answer : 1. "92.8%"
Explanation :
Answer: A) 92.8% Explanation: Here, x = 40 and y = 30;Therefore second number= [[100+y100+x] x 100 ]% of first number= [[100+y100+x] x 100 ]% of first numberSecond number = 92.8% of the first number.
Q: Find value of log27 +log 8 +log1000log 120 2247 15b5cc7d0e4d2b4197775120e
5b5cc7d0e4d2b4197775120e- 11/2false
- 23/2true
- 32false
- 42/3false
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Answer : 2. "3/2"
Explanation :
Answer: B) 3/2 Explanation: = log 33 + log 23+ log 103log10×3×22 =log33 12+log 23+log 10312log(10×3×22) =12log 33+3 log 2+12 log103log10+log3+log22 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32
Q: There are 10 Letters and 10 correspondingly 10 different Address. If the letter are put into envelope randomly, then find the Probability that Exactly 9 letters will at the Correct Address ? 2246 05b5cc705e4d2b4197774f1ee
5b5cc705e4d2b4197774f1ee- 11/10false
- 21/9false
- 31false
- 40true
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Answer : 4. "0"
Explanation :
Answer: D) 0 Explanation: As we know we have 10 letter and 10 different address and one more information given that exactly 9 letter will at the correct address....so the remaining one letter automatically reach to their correct address P(E) = favorable outcomes /total outcomesHere favorable outcomes are '0'.So probability is '0'.
Q: If 25a + 25b = 115, then what is the average of a and b? 2246 05b5cc7c7e4d2b41977750daf
5b5cc7c7e4d2b41977750daf- 14.6false
- 23.4false
- 32.5false
- 4None of thesetrue
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Answer : 4. "None of these"
Explanation :
Answer: D) None of these Explanation:
Q: There is 50% increase in an amount in 5 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate ? 2244 05b5cc767e4d2b4197774fe01
5b5cc767e4d2b4197774fe01- 1Rs. 5422false
- 2Rs. 5489false
- 3Rs. 3972true
- 4Rs. 6145false
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Answer : 3. "Rs. 3972"
Explanation :
Answer: C) Rs. 3972 Explanation: Let p = Rs. 100. Then, S.I is Rs. 50 and time = 5 years. ∴ R = 100×50100×5= 10% p.a. Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a. C.I. = Rs. 12000×1+101003-1= Rs. 3972
Q: Find the odd one out of the series ? 35, 48, 54, 63, 81, 105 2242 05b5cc6dae4d2b4197774e8c3
5b5cc6dae4d2b4197774e8c3- 163false
- 248false
- 335true
- 481false
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Answer : 3. "35"
Explanation :
Answer: C) 35 Explanation: 48, 54, 63, 81 and 105 are divisible by 3 but not 35.
Q: A letter is takenout at random from 'ASSISTANT' and another is taken out from 'STATISTICS'. The probability that they are the same letter is : 2238 05b5cc7d0e4d2b41977751213
5b5cc7d0e4d2b41977751213- 135/96false
- 219/90true
- 319/96false
- 4None of thesefalse
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Answer : 2. "19/90"
Explanation :
Answer: B) 19/90 Explanation: ASSISTANT→AAINSSSTT STATISTICS→ACIISSSTTT Here N and C are not common and same letters can be A, I, S, T. Therefore Probability of choosing A = 2C19C1×1C110C1 = 1/45 Probability of choosing I = 19C1×2C110C1 = 1/45 Probability of choosing S = 3C19C1×3C110C1 = 1/10 Probability of choosing T = 2C19C1×3C110C1 = 1/15 Hence, Required probability = 145+145+110+115= 1990