Quantitative Aptitude Practice Question and Answer
8Q: There is 50% increase in an amount in 5 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate ? 1932 05b5cc767e4d2b4197774fe01
5b5cc767e4d2b4197774fe01- 1Rs. 5422false
- 2Rs. 5489false
- 3Rs. 3972true
- 4Rs. 6145false
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Answer : 3. "Rs. 3972"
Explanation :
Answer: C) Rs. 3972 Explanation: Let p = Rs. 100. Then, S.I is Rs. 50 and time = 5 years. ∴ R = 100×50100×5= 10% p.a. Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a. C.I. = Rs. 12000×1+101003-1= Rs. 3972
Q: Madhu started a business and he invested in 76000, After some month, Amar came to join with him and invest 57000.The end of the year the total profit was divided among them into ratio form 2 : 1.Find after how many months Amar join. 1931 05b5cc767e4d2b4197774fe27
5b5cc767e4d2b4197774fe27- 17 monthsfalse
- 28 monthsfalse
- 33 monthsfalse
- 44 monthstrue
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Answer : 4. "4 months"
Explanation :
Answer: D) 4 months Explanation: we can assume that Amar join into business after x months. So Amar money was invest into (12 – x ) months. 76000×1257000×(12-x)=21 --> 912000 = 114000 ( 12 – x ) = 114 ( 12 – x ) = 912 --> x = 4 After 4 months amar join the business.
Q: If 6 years are subtracted from the present age of Arun and the remainder is divided by 18, then the present age of his grandson Gokul is obtained. If Gokul is 2 years younger to Madan whose age is 5 years, then what is the age of Arun ? 1930 05b5cc71be4d2b4197774f53a
5b5cc71be4d2b4197774f53a- 172 yearsfalse
- 254 yearsfalse
- 360 yearstrue
- 447 yearsfalse
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Answer : 3. "60 years"
Explanation :
Answer: C) 60 years Explanation: Let the Present age of arun is xGokul's age = 5-2 = 3x-6/18 = 3x-6 = 54x = 60Arun's present age = 60 years
Q: A sum of Rs. 731 is divided among A,B and C, such that 'A' receives 255 more than 'B' and 'B' receives 25% less than 'C'. What is 'C' s share in the amount? 1929 05b5cc7c8e4d2b41977750e2c
5b5cc7c8e4d2b41977750e2c- 1Rs.172false
- 2Rs.200false
- 3Rs.262false
- 4None of thesetrue
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Answer : 4. "None of these"
Explanation :
Answer: D) None of these Explanation:
Q: In a test, minimum passing percentage for girls and boys is 35% and 40% respectively. A boy scored 483 marks and failed by 117 marks. What is the minimum passing marks for girls ? 1926 05b5cc72ce4d2b4197774f75a
5b5cc72ce4d2b4197774f75a- 1625false
- 2525true
- 3425false
- 4325false
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Answer : 2. "525"
Explanation :
Answer: B) 525 Explanation: Given 40% minimum passing marks for boys = 483 + 117 = 600=> 1% = 600/40 => 100% = 600 x 100/40 = 1500Minimum passing marks for girls = 35% of 1500 = 35 x 1500/100 = 525.
Q: There is sufficient salary to give K for 10 days and L for 15 days. Then how many days will the money last if both has to be given the salary ? 1926 05b5cc715e4d2b4197774f404
5b5cc715e4d2b4197774f404- 16 daystrue
- 212 daysfalse
- 34 daysfalse
- 49 daysfalse
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Answer : 1. "6 days"
Explanation :
Answer: A) 6 days Explanation: K's 1 day's salary = 1/10 L's 1 day's salary = 1/15 Together their 1 day's salary = 1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6 So the money will be enough for paying them both for 6 days.
Q: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 1924 05b5cc774e4d2b41977750011
5b5cc774e4d2b41977750011- 1205false
- 2194false
- 3209true
- 4159false
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Answer : 3. "209"
Explanation :
Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16× C34) + C26×C24 + (C36× C14) + (C46) = (24+90+80+15) = 209.
Q: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most ? 1923 05b5cc6e1e4d2b4197774ebde
5b5cc6e1e4d2b4197774ebde- 1215true
- 2268false
- 3254false
- 4216false
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Answer : 1. "215"
Explanation :
Answer: A) 215 Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt. Maximum number of unsuccessful attempts = 216 - 1 = 215.