Quantitative Aptitude Practice Question and Answer

Q: Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ? 2224 0

  • 1
    31 years
    Correct
    Wrong
  • 2
    37 years
    Correct
    Wrong
  • 3
    46 years
    Correct
    Wrong
  • 4
    29 years
    Correct
    Wrong
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Answer : 1. "31 years"
Explanation :

Answer: A) 31 years Explanation: Let the present age of Pinky be x years   Then the age of Mary is x - 12 years   After 3 years,   Ratio of  MaryPinky = x - 9x + 3 = 58   8x - 72 = 5x +15   => 3x = 87   => x = 29   => Age of Pinky = 29 years   => Age of Mary = 29 - 12 = 17 years   Present age of Sam = 29 + 17 = 46   Before 15 years Sam age = 46 - 15 = 31 years.

Q: Eighteen years ago, a mother was three times as old as her daughter. Now the mother is only twice as old as her daughter. Then the sum of the present ages of daughter and the mother is ? 2223 0

  • 1
    84 yrs
    Correct
    Wrong
  • 2
    96 yrs
    Correct
    Wrong
  • 3
    116 yrs
    Correct
    Wrong
  • 4
    108 yrs
    Correct
    Wrong
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Answer : 4. "108 yrs"
Explanation :

Answer: D) 108 yrs Explanation: Let the present ages of the mother and daughter be 2x and x years respectively. Then, (2x - 18) = 3(x - 18) => x = 36 Required sum = (2x + x) = 108 years.

Q: After working for 8 days, Hari Ram finds that only 1/3 rd of the work has been done. He employs Satya who is 60% as efficient as Hari Ram. How many days more would Satya take to complete the work ? 2222 0

  • 1
    24 1/2 days
    Correct
    Wrong
  • 2
    25 3/2 days
    Correct
    Wrong
  • 3
    24 2/3 days
    Correct
    Wrong
  • 4
    26 2/3 days
    Correct
    Wrong
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Answer : 4. "26 2/3 days"
Explanation :

Answer: D) 26 2/3 days Explanation: 1/3 ---- 8 1 -------? Hari can do total work in = 24 days As satya is 60% efficient as Hari, then Satya = 1/24 x 60/100 = 1/40 => Satya can do total work in 40 days 1 ----- 40 2/3 ---- ? => 26 2/3 days.

Q: Find the odd one out of the following number series? 56, 64, 48, 90, 16, 144 2220 0

  • 1
    48
    Correct
    Wrong
  • 2
    64
    Correct
    Wrong
  • 3
    90
    Correct
    Wrong
  • 4
    16
    Correct
    Wrong
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Answer : 3. "90"
Explanation :

Answer: C) 90 Explanation: The given number series follows a pattern that, 56 56 + 8 = 64 64 - 16 = 48 48 + 32 = 80 (Not equal to 90) 80 - 64 = 16 16 + 128 = 144    Hence, the odd number in the given number series is 90.

Q: Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ? 2219 0

  • 1
    Rs. 1,24,000
    Correct
    Wrong
  • 2
    Rs. 1,44,000
    Correct
    Wrong
  • 3
    Rs. 1,32,000
    Correct
    Wrong
  • 4
    Rs. 1,62,000
    Correct
    Wrong
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Answer : 2. "Rs. 1,44,000"
Explanation :

Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.

Q: Ram sell his goods 25% cheaper than Shyam and 25% dearer than Bram. How much % is Bram's good cheaper than Shyam ? 2217 0

  • 1
    60%
    Correct
    Wrong
  • 2
    40%
    Correct
    Wrong
  • 3
    50%
    Correct
    Wrong
  • 4
    30%
    Correct
    Wrong
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Answer : 2. "40%"
Explanation :

Answer: B) 40% Explanation: Lets say shyam sells at 100,   Since Ram sells 25% cheaper than Shyam,   Therefor Ram sells at less than 25% of100 or 75 rs.   Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or   125% of x (say x price of bram )=75rs.or 100% of x =60rs.hence price of bram is 60rs.   now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%.   Hence Brams Good is 40% cheaper than that of Shyam's good.

Q: A sum of Rs. 731 is divided among A,B and C, such that 'A' receives 255 more than 'B' and 'B' receives 25% less than 'C'. What is 'C' s share in the amount? 2216 0

  • 1
    Rs.172
    Correct
    Wrong
  • 2
    Rs.200
    Correct
    Wrong
  • 3
    Rs.262
    Correct
    Wrong
  • 4
    None of these
    Correct
    Wrong
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Answer : 4. "None of these"
Explanation :

Answer: D) None of these Explanation:

Q: At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other?  A. 5111 B. 15415 C. 16411 D. 4415 2214 0

  • 1
    Option A
    Correct
    Wrong
  • 2
    Option B
    Correct
    Wrong
  • 3
    Option C
    Correct
    Wrong
  • 4
    Option D
    Correct
    Wrong
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Answer : 3. "Option C"
Explanation :

Answer: C) Option C Explanation: At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand.     To be coincident, it must gain 15 min. spaces.     55 min. are gained in 60 min.     Then 15 min spaces are gained in  = 6055×15 min.     Therefore,  The hands are coincident at  16411 min. past 3 o'clock.

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