Quantitative Aptitude Practice Question and Answer
8Q: When the price of whear was increased by 32%, a family reduced its consumption in such a way that the expenditure on wheat was only 10% more than before. If 30 kg per month were consumed before, find the new monthly consumption of family? 2406 05b5cc61ee4d2b4197774b758
5b5cc61ee4d2b4197774b758- 127 kgsfalse
- 225 kgstrue
- 324 kgsfalse
- 421 kgsfalse
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Answer : 2. "25 kgs"
Explanation :
Answer: B) 25 kgs Explanation: Initial wheat per kg cost be Rs. 100 Then, monthly expenditure of the family = 30 x 100 = 3000 After increase in cost, Let P be new monthly consumption of family. P x 132 = 110/100 x 3000 => P = 25 kg.
Q: Find value of log27 +log 8 +log1000log 120 2401 15b5cc7d0e4d2b4197775120e
5b5cc7d0e4d2b4197775120e- 11/2false
- 23/2true
- 32false
- 42/3false
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Answer : 2. "3/2"
Explanation :
Answer: B) 3/2 Explanation: = log 33 + log 23+ log 103log10×3×22 =log33 12+log 23+log 10312log(10×3×22) =12log 33+3 log 2+12 log103log10+log3+log22 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32
Q: Find the odd one out of the following number series? 56, 64, 48, 90, 16, 144 2401 05b5cc658e4d2b4197774bddd
5b5cc658e4d2b4197774bddd- 148false
- 264false
- 390true
- 416false
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Answer : 3. "90"
Explanation :
Answer: C) 90 Explanation: The given number series follows a pattern that, 56 56 + 8 = 64 64 - 16 = 48 48 + 32 = 80 (Not equal to 90) 80 - 64 = 16 16 + 128 = 144 Hence, the odd number in the given number series is 90.
Q: What percent of a day is 3 hours? 2398 05b5cc69ae4d2b4197774c778
5b5cc69ae4d2b4197774c778- 114.9%false
- 212.5%true
- 315.6%%false
- 411.4%false
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Answer : 2. "12.5%"
Explanation :
Answer: B) 12.5% Explanation: Let p% of a day is 3 hrs. We know that a day has 24 hrs. => p x 24/100 = 3 => p = 300/24 => p = 12.5% Hence, 3 hrs is 12.5% of a day.
Q: Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ? 2394 05b5cc701e4d2b4197774f170
5b5cc701e4d2b4197774f170- 1Rs. 1,24,000false
- 2Rs. 1,44,000true
- 3Rs. 1,32,000false
- 4Rs. 1,62,000false
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Answer : 2. "Rs. 1,44,000"
Explanation :
Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.
Q: The ratio of investments of two partners A and B is 7:5 and the ratio of their profits is 7:10. If A invested the money for 5 months, find for how much time did B invest the money ? 2392 05b5cc6dfe4d2b4197774eaf3
5b5cc6dfe4d2b4197774eaf3- 111 monthsfalse
- 29 monthsfalse
- 37 monthsfalse
- 410 monthstrue
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Answer : 4. "10 months"
Explanation :
Answer: D) 10 months Explanation: 7x5: 5xk = 7:10k = 10 months
Q: A man can row upstream at 16 km/hr and downstream at 24 km/hr. Find the speed of the current. 2391 05b5cc6bde4d2b4197774d942
5b5cc6bde4d2b4197774d942- 14 kmphtrue
- 26 kmphfalse
- 35 kmphfalse
- 43 kmphfalse
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Answer : 1. "4 kmph"
Explanation :
Answer: A) 4 kmph Explanation: Speed of the current = 24-16/2 = 8/2 = 4 km/hr.
Q: A rectangular grassy plot 120 m. by 60 m has a gravel path 1.5 m wide all round it on the inside. Find the cost of gravelling the path at 65 paise per sq. metre ? 2391 05b5cc723e4d2b4197774f690
5b5cc723e4d2b4197774f690- 1Rs. 345.15true
- 2Rs. 245.1false
- 3Rs. 234.18false
- 4Rs. 456.65false
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Answer : 1. "Rs. 345.15"
Explanation :
Answer: A) Rs. 345.15 Explanation: area of the plot = 120m x 60m = 7200 sq.marea of plot excluding gravel = 117m x 57m = 6669 sq.marea of gravel = 7200 sq.m - 6669 sq.m = 531 sq.mcost of building it = 531 sq.m x 65 ps = 34515 psIn Rs. = 34515/100 = Rs. 345.15.