Quantitative Aptitude Practice Question and Answer
8Q: Find the odd one out of the series ? 35, 48, 54, 63, 81, 105 1777 05b5cc6dae4d2b4197774e8c3
5b5cc6dae4d2b4197774e8c3- 163false
- 248false
- 335true
- 481false
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- SingleChoice
Answer : 3. "35"
Explanation :
Answer: C) 35 Explanation: 48, 54, 63, 81 and 105 are divisible by 3 but not 35.
Q: Arun has certain number of books. It is not less than 15 and not more than 30. If he wants to give these books equally to 2 of his friends, then 1 book will remain. If he wants to give these books equally to 3 of his friends, then 2 books will remain. If he wants to give these books equally to 4 of his friends, then 3 books will remain. What is the number of books he had ? 1776 05b5cc718e4d2b4197774f4a4
5b5cc718e4d2b4197774f4a4- 119false
- 223true
- 317false
- 415false
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Answer : 2. "23"
Explanation :
Answer: B) 23 Explanation: If he wants to give these books equally to 2 of his friends, then 1 book will remain, it means possible number of books = 15,17,19,21,23,25,27,29If he wants to give these books equally to 3 of his friends, then 2 books will remain, it means possible number of books = 17,20,23,26,29If he wants to give these books equally to 4 of his friends, then 3 book will remain, it means possible number of books = 15,19,23,27common number is only 23 so it will be answer
Q: One girl can eat 112 chocolates in half a minute, and her boy friend can eat half as many in twice the length of time. How many chocolates can both boy and girl eat in 12 seconds ? 1775 05b5cc745e4d2b4197774fa27
5b5cc745e4d2b4197774fa27- 144false
- 232false
- 356true
- 449false
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Answer : 3. "56"
Explanation :
Answer: C) 56 Explanation: Girl eats 112 chocolates in 30 sec so she can eat in 12 sec is 12 x 112/30 = 44.8 chocolates. Her boy friend can eat one-half of 112 in twice of 30 sec so he can eat 56 in 60 sec Then he can eat in 12 sec is 56 x 12/60 = 11.2 chocolates. Hence, together they can eat = 44.8 + 11.2 =56 chocolates in 12 seconds.
Q: Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ? 1775 05b5cc6cae4d2b4197774e068
5b5cc6cae4d2b4197774e068- 131 yearstrue
- 237 yearsfalse
- 346 yearsfalse
- 429 yearsfalse
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Answer : 1. "31 years"
Explanation :
Answer: A) 31 years Explanation: Let the present age of Pinky be x years Then the age of Mary is x - 12 years After 3 years, Ratio of MaryPinky = x - 9x + 3 = 58 8x - 72 = 5x +15 => 3x = 87 => x = 29 => Age of Pinky = 29 years => Age of Mary = 29 - 12 = 17 years Present age of Sam = 29 + 17 = 46 Before 15 years Sam age = 46 - 15 = 31 years.
Q: The ratio of earnings of A and B is 4:5. If the earnings of A increase by 20% and the earnings of B decrease by 20%, the new ratio of their earnings becomes 6:5. What are A's earnings? 1773 05b5cc7c9e4d2b41977750ed6
5b5cc7c9e4d2b41977750ed6- 1Rs.22,000false
- 2Rs.27,500false
- 3Rs. 26,400false
- 4Cannot be determinedtrue
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Answer : 4. "Cannot be determined"
Explanation :
Answer: D) Cannot be determined Explanation:
Q: 6 boys and 8 girls can do job in 10 days , 26 boys & 48 women do work in 2 days. Find time taken by 15 boys and 20 girls to do same work ? 1771 05b5cc74ae4d2b4197774fadb
5b5cc74ae4d2b4197774fadb- 12 daysfalse
- 23 daysfalse
- 34 daystrue
- 45 daysfalse
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Answer : 3. "4 days"
Explanation :
Answer: C) 4 days Explanation: One day work of 6 boys and 8 girls is given as 6b + 8g = 1/10 -------->(I) One day work of 26 boys and 48 women is given as 26b + 48w = 1/2 -------->(II) Divide both sides by 2 in (I) and then multiply both sides by 5 Now we get, 15b + 20g = 1/4. Therefore, 15 boys and 20 girls can do the same work in 4 days.
Q: K is 4 times as fast as L and working together, they can complete a work in 24 days. In how many days can L alone complete the work ? 1771 05b5cc774e4d2b4197775003e
5b5cc774e4d2b4197775003e- 130 daystrue
- 240 daysfalse
- 3120 daysfalse
- 480 daysfalse
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Answer : 1. "30 days"
Explanation :
Answer: A) 30 days Explanation: Given K=4L -->K+L = 4L+L = 5L These 5L people can complete the work in 24 days, which means L alone can do the work in (24 x 5)=120 days. Hence, K alone can do the work in 120/4= 30 days.
Q: A letter is takenout at random from 'ASSISTANT' and another is taken out from 'STATISTICS'. The probability that they are the same letter is : 1770 05b5cc7d0e4d2b41977751213
5b5cc7d0e4d2b41977751213- 135/96false
- 219/90true
- 319/96false
- 4None of thesefalse
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Answer : 2. "19/90"
Explanation :
Answer: B) 19/90 Explanation: ASSISTANT→AAINSSSTT STATISTICS→ACIISSSTTT Here N and C are not common and same letters can be A, I, S, T. Therefore Probability of choosing A = 2C19C1×1C110C1 = 1/45 Probability of choosing I = 19C1×2C110C1 = 1/45 Probability of choosing S = 3C19C1×3C110C1 = 1/10 Probability of choosing T = 2C19C1×3C110C1 = 1/15 Hence, Required probability = 145+145+110+115= 1990