Quantitative Aptitude Practice Question and Answer

Q: The simple interest on a sum of money will be Rs.600 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year ? 2026 0

  • 1
    Rs. 1100
    Correct
    Wrong
  • 2
    Rs. 1200
    Correct
    Wrong
  • 3
    Rs. 1000
    Correct
    Wrong
  • 4
    Rs. 1840
    Correct
    Wrong
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Answer : 2. "Rs. 1200"
Explanation :

Answer: B) Rs. 1200 Explanation: P --- 10 ----- 600    P --- 5 ----- 300 3P --- 5 ----- 900                __________                   1200

Q: The Simple interest accrued on an amount of Rs. 2,500 at the end of six years is Rs.1875. What would be the simple interest accrued on an amount of Rs. 6875 at the same rate and Same period? 2026 0

  • 1
    Rs. 4,556.5
    Correct
    Wrong
  • 2
    Rs. 5,025.25
    Correct
    Wrong
  • 3
    Rs.5,245.5
    Correct
    Wrong
  • 4
    None of these
    Correct
    Wrong
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Answer : 4. "None of these"
Explanation :

Answer: D) None of these Explanation:

Q: 14 persons are seated around a circular table. Find the probability that 3 particular persons always seated together. 2022 0

  • 1
    11/379
    Correct
    Wrong
  • 2
    21/628
    Correct
    Wrong
  • 3
    24/625
    Correct
    Wrong
  • 4
    26/247
    Correct
    Wrong
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Answer : 3. "24/625"
Explanation :

Answer: C) 24/625 Explanation: Total no of ways = (14 – 1)! = 13! Number of favorable ways = (12 – 1)! = 11!   So, required probability = 11!×3!13! = 39916800×66227020800 = 24625

Q: If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ? 2019 0

  • 1
    100 mts
    Correct
    Wrong
  • 2
    96 mts
    Correct
    Wrong
  • 3
    98 mts
    Correct
    Wrong
  • 4
    120 mts
    Correct
    Wrong
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Answer : 3. "98 mts"
Explanation :

Answer: C) 98 mts Explanation: Let the distance between home and school is 'x'.Let actual time to reach be 't'.Thus, x/4 = t + 4 ---- (1)and x/6 = t - 30 -----(2)Solving equation (1) and (2)=> x = 98 mts.

Q: Twelve percent of Kalyan's monthly salary is equal to the sixteen per cent of Nandu's monthly salary. Sarnesh's monthly salary is half that of Nandu's monthly salary. If sarnesh's annual salary is Rs. 1.08 lacs, What is Kalyan's monthly salary ? 2018 0

  • 1
    15,000
    Correct
    Wrong
  • 2
    36,000
    Correct
    Wrong
  • 3
    24,000
    Correct
    Wrong
  • 4
    12,500
    Correct
    Wrong
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Answer : 3. "24,000"
Explanation :

Answer: C) 24,000 Explanation: Let K = Kalyan's monthly salaryN = Nandu's monthly salaryS = Sarnesh's monthly salary.Then from given data, 12% of K = 16% of NS = N/2 => N = 2SK = 16/12 x N = 16/12 x 2S= 16/6 x 1.08/12 = 16/6 x 0.09 = 0.24 lacs = 24,000

Q: 5/9 of the part of the population in a village are females. If 30 % of the females are married. The percentage of unmarried males in the total males is ? 2016 0

  • 1
    62.5 %
    Correct
    Wrong
  • 2
    125 %
    Correct
    Wrong
  • 3
    84.32 %
    Correct
    Wrong
  • 4
    46.87 %
    Correct
    Wrong
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Answer : 1. "62.5 %"
Explanation :

Answer: A) 62.5 % Explanation: Let total population = p number of females = 5p/9number of males =(p-5p/9) = 4p/9married females = 30% of 5p/9 = 30x5p/100x9 = p/6married males = p/6unmarried males =(4p/9-p/6) = 5p/18Percentage of unmarried males in the total males = {(5p/18)/4p/9}x100 = (5p/18)x(9/4p) = 125/2 % = 62.5%

Q: A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ? 2015 0

  • 1
    14.69 cm
    Correct
    Wrong
  • 2
    29.39 cm
    Correct
    Wrong
  • 3
    18.65 cm
    Correct
    Wrong
  • 4
    22.21 cm
    Correct
    Wrong
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Answer : 2. "29.39 cm"
Explanation :

Answer: B) 29.39 cm Explanation: Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms.   As speed is same, area of cross sections should be same.    Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12  i.e πR2 = 6πR12    Here R = R and R1 = 12/2 = 6    ⇒R2 = 6×6×6    R = 14.696    => D = X = 14.696 * 2 = 29.3938 cm.

Q: In a certain Business, the profit is 220% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 2015 0

  • 1
    61%
    Correct
    Wrong
  • 2
    75%
    Correct
    Wrong
  • 3
    55%
    Correct
    Wrong
  • 4
    81%
    Correct
    Wrong
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Answer : 1. "61%"
Explanation :

Answer: A) 61% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs.220,  S.P. = Rs.320.   New C.P. = 125% of Rs. 100 = Rs. 125  New S.P. = Rs.320. Profit = Rs. (320 - 125) = Rs. 195   Required percentage = 195320×100== 60.9 =~ 61%

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