Quantitative Aptitude Practice Question and Answer
8Q: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 2082 05b5cc774e4d2b41977750011
5b5cc774e4d2b41977750011- 1205false
- 2194false
- 3209true
- 4159false
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Answer : 3. "209"
Explanation :
Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16× C34) + C26×C24 + (C36× C14) + (C46) = (24+90+80+15) = 209.
Q: The sides of a right-angled triangle are 12 cm, 16 cm, 20 cm respectively. A new right angle Δ is made by joining the midpoints of all the sides. This process continues for infinite then calculate the sum of the areas of all the triangles so made. 2081 05b5cc6b7e4d2b4197774d62e
5b5cc6b7e4d2b4197774d62e- 1312 sq.cmfalse
- 2128 sq.cmtrue
- 3412 sq.cmfalse
- 4246 sq.cmfalse
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Answer : 2. "128 sq.cm"
Explanation :
Answer: B) 128 sq.cm Explanation: Area = = 96 Sum of Area =
Q: The ratio of investments of two partners A and B is 7:5 and the ratio of their profits is 7:10. If A invested the money for 5 months, find for how much time did B invest the money ? 2077 05b5cc6dfe4d2b4197774eaf3
5b5cc6dfe4d2b4197774eaf3- 111 monthsfalse
- 29 monthsfalse
- 37 monthsfalse
- 410 monthstrue
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Answer : 4. "10 months"
Explanation :
Answer: D) 10 months Explanation: 7x5: 5xk = 7:10k = 10 months
Q: 14 persons are seated around a circular table. Find the probability that 3 particular persons always seated together. 2077 05b5cc6b6e4d2b4197774d5b8
5b5cc6b6e4d2b4197774d5b8- 111/379false
- 221/628false
- 324/625true
- 426/247false
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Answer : 3. "24/625"
Explanation :
Answer: C) 24/625 Explanation: Total no of ways = (14 – 1)! = 13! Number of favorable ways = (12 – 1)! = 11! So, required probability = 11!×3!13! = 39916800×66227020800 = 24625
Q: Arun has certain number of books. It is not less than 15 and not more than 30. If he wants to give these books equally to 2 of his friends, then 1 book will remain. If he wants to give these books equally to 3 of his friends, then 2 books will remain. If he wants to give these books equally to 4 of his friends, then 3 books will remain. What is the number of books he had ? 2073 05b5cc718e4d2b4197774f4a4
5b5cc718e4d2b4197774f4a4- 119false
- 223true
- 317false
- 415false
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Answer : 2. "23"
Explanation :
Answer: B) 23 Explanation: If he wants to give these books equally to 2 of his friends, then 1 book will remain, it means possible number of books = 15,17,19,21,23,25,27,29If he wants to give these books equally to 3 of his friends, then 2 books will remain, it means possible number of books = 17,20,23,26,29If he wants to give these books equally to 4 of his friends, then 3 book will remain, it means possible number of books = 15,19,23,27common number is only 23 so it will be answer
Q: Mr. X sold two properties P1 and P2 for Rs 1,00,000 each. He sold property P1 for 20% less than what he paid for it. What is the percentage of profit of property P2, so that he is not in gain or loss on the sale of two properties? 2073 05b5cc6aae4d2b4197774cf6f
5b5cc6aae4d2b4197774cf6f- 133.33%true
- 229.97%false
- 325%false
- 422.22%false
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Answer : 1. "33.33%"
Explanation :
Answer: A) 33.33% Explanation: Let 'A' be the cost price of property P1. Then from the given data, the selling price of P1 = Rs. 1,00,000 He got 20% loss on selling P1 ⇒A - 20A100 = 100000⇒A = 1,25,000 Therefore, the amount he lossed on selling P1 = 25,000 As ge he got no loss or gain on sale of P1 and P2, the gain on selling P2 = 25,000 But the selling price of P2 = 1,00,000 => Cost price of P2 = 75,000 Hence, the profit percentage on P2 = GainCPx 100 = 2500075000x100 = 1003= 33.33%
Q: A man can row upstream at 16 km/hr and downstream at 24 km/hr. Find the speed of the current. 2069 05b5cc6bde4d2b4197774d942
5b5cc6bde4d2b4197774d942- 14 kmphtrue
- 26 kmphfalse
- 35 kmphfalse
- 43 kmphfalse
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Answer : 1. "4 kmph"
Explanation :
Answer: A) 4 kmph Explanation: Speed of the current = 24-16/2 = 8/2 = 4 km/hr.
Q: The letters of the word PROMISE are to be arranged so that three vowels should not come together. Find the number of ways of arrangements? 2066 05b5cc6ade4d2b4197774d0f9
5b5cc6ade4d2b4197774d0f9- 14320true
- 24694false
- 34957false
- 44871false
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Answer : 1. "4320"
Explanation :
Answer: A) 4320 Explanation: Given Word is PROMISE. Number of letters in the word PROMISE = 7 Number of ways 7 letters can be arranged = 7! ways Number of Vowels in word PROMISE = 3 (O, I, E) Number of ways the vowels can be arranged that 3 Vowels come together = 5! x 3! ways Now, the number of ways of arrangements so that three vowels should not come together = 7! - (5! x 3!) ways = 5040 - 720 = 4320.