Answer: B) 14 Explanation: Given Number series is :   3   4   14   48   576   27648   It follows a pattern that,   3   4   4 x 3 = 12   but not 14   12 x 4 = 48   48 x 12 = 576   576 x 48 = 27648       Hence, the odd one in the given Number Series is 14.

Answer: B) 1 Explanation: Let x be the number. Given: x = 296n + 75 [where n is quotient]   --> (378n) +( 372 + 1)   -->37(8n + 2) + 1 Hence, when x divided by 37, 1 is the remainder.

Answer: C) 35 Explanation: 48, 54, 63, 81 and 105 are divisible by 3 but not 35.

Answer: A) 36 days Explanation: Given the ratio of efficiencies of P, Q & R are 3 : 8 : 5 Let the efficiencies of P, Q & R be 3x, 8x and 5x respectively They can do work for 12 days. => Total work = 12 x 16x = 192x   Now, the required time taken by Q to complete the job alone = 162x8x = 24 days.

Answer: D) 15 Explanation: Let 'K' be the total number of sweets.Given total number of students = 112If sweets are distributed among 112 children,Let number of sweets each student gets = 'L' => K/112 = L ....(1)But on that day students absent = 32 => remaining = 112 - 32 = 80Then, each student gets '6' sweets extra. => K/80 = L + 6 ....(2)from (1) K = 112L substitute in (2), we get112L = 80L + 48032L = 480L = 15 Therefore, 15 sweets were each student originally supposed to get.

Answer: C) 4 days Explanation: One day work of 6 boys and 8 girls is given as 6b + 8g = 1/10 -------->(I)   One day work of 26 boys and 48 women is given as 26b + 48w = 1/2 -------->(II)   Divide both sides by 2 in (I) and then multiply both sides by 5 Now we get, 15b + 20g = 1/4. Therefore, 15 boys and 20 girls can do the same work in 4 days.

Answer: C) 91.5 Explanation: We have M1 D1 H1 / W1 = M2 D2 H2 / W2 (Variation rule)(60 x 30 x 8)/ 150 = (35 x D2 x 6) / 200 D2 = (60 x 30 x 8 x 200) / (150 x 35 x 6) => D2 = 91.42 days =~ 91.5 days.

Answer: A) 18 Explanation: (300 – 101)/11 = 199/11 = 18 1/1118 Numbers.