Quantitative Aptitude Practice Question and Answer

Q: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 2154 0

  • 1
    205
    Correct
    Wrong
  • 2
    194
    Correct
    Wrong
  • 3
    209
    Correct
    Wrong
  • 4
    159
    Correct
    Wrong
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Answer : 3. "209"
Explanation :

Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16× C34) + C26×C24  + (C36× C14) + (C46)   = (24+90+80+15)  = 209.

Q: A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ? 2153 0

  • 1
    14.69 cm
    Correct
    Wrong
  • 2
    29.39 cm
    Correct
    Wrong
  • 3
    18.65 cm
    Correct
    Wrong
  • 4
    22.21 cm
    Correct
    Wrong
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Answer : 2. "29.39 cm"
Explanation :

Answer: B) 29.39 cm Explanation: Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms.   As speed is same, area of cross sections should be same.    Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12  i.e πR2 = 6πR12    Here R = R and R1 = 12/2 = 6    ⇒R2 = 6×6×6    R = 14.696    => D = X = 14.696 * 2 = 29.3938 cm.

Q: The Value of  logtan10+logtan20+⋯⋯+logtan890 is 2152 1

  • 1
    -1
    Correct
    Wrong
  • 2
    0
    Correct
    Wrong
  • 3
    1/2
    Correct
    Wrong
  • 4
    1
    Correct
    Wrong
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Answer : 2. "0"
Explanation :

Answer: B) 0 Explanation: = log tan10+log tan890 + log tan20+ log tan880+⋯⋯+log tan450     = log [tan10 × tan890] + log [tan20 × tan880 ] +⋯⋯+log1     ∵ tan(90-θ)=cotθ and tan 450=1     = log 1 + log 1 +.....+log 1    = 0.

Q: A 400-metre-long train is running at the speed of 60 km/hour. A man is running in the opposite direction of train at the speed of 12 km/hour. In how much time the train will cross this man? 2150 1

  • 1
    50 second
    Correct
    Wrong
  • 2
    30 second
    Correct
    Wrong
  • 3
    20 second
    Correct
    Wrong
  • 4
    40 second
    Correct
    Wrong
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Answer : 3. "20 second"

Q: Find the Odd One Out? 3, 4, 14, 48, 576, 27648 2145 0

  • 1
    4
    Correct
    Wrong
  • 2
    14
    Correct
    Wrong
  • 3
    48
    Correct
    Wrong
  • 4
    27648
    Correct
    Wrong
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Answer : 2. "14"
Explanation :

Answer: B) 14 Explanation: Given Number series is :   3   4   14   48   576   27648   It follows a pattern that,   3   4   4 x 3 = 12   but not 14   12 x 4 = 48   48 x 12 = 576   576 x 48 = 27648       Hence, the odd one in the given Number Series is 14.

Q: Express 3/8 and 1/10 as a Decimals? 2145 0

  • 1
    1.375 & 1
    Correct
    Wrong
  • 2
    0.375 & 1
    Correct
    Wrong
  • 3
    13.75 & 1.1
    Correct
    Wrong
  • 4
    0.375 & 0.1
    Correct
    Wrong
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Answer : 4. "0.375 & 0.1"
Explanation :

Answer: D) 0.375 & 0.1 Explanation: 3/8 as a Decimal : In this we should convert the denominator into 10, 100, 1000, 10000, 100000,... to make it simple. Now to make 8 into 1000, we multiply numerator and denominator with 125 => 3 x 1258 x 125 = 3751000 = 0.375   1/10 as a Decimal : 1 divided into 10 parts of each 0.1.   Therefore, 3/8 = 0.375 and 1/10 = 0.1 in decimals.

Q: If y/(x - z) = (y + x)/z = x/y then find z : y : x ? 2144 0

  • 1
    1:2:3
    Correct
    Wrong
  • 2
    3:2:4
    Correct
    Wrong
  • 3
    4:3:2
    Correct
    Wrong
  • 4
    2:3:4
    Correct
    Wrong
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Answer : 2. "3:2:4"
Explanation :

Answer: B) 3:2:4 Explanation: Given, y/(x - z) = (y + x)/z = x/yyz = xy + x2 - yz - xz ....(1)Also xy = yx-z ⇒x2 -xz = y2 ....(2)Using (1) and (2), we get yz = xy - yz + y22yz = xy + y22z = x + y Only option (B) satisfies the equation.

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Answer : 2. "20%"
Explanation :

Answer: B) 20% Explanation: Let the Cost of Production of the article = 100 Then, Labour Cost = 20 Raw Material = 10 Other Expenditure = 100 - 10 – 20 = 70 Selling Price of the article  = 120 After increasing Labour and Raw material cost by 40% & 20% respectively, New Labour cost = 28 New Raw material cost = 12 New Cost of Production = 70 + 28 + 12 = 110 Then, New SP = 110% of 120 = 120 x 110/100 = 132 => New Gain = 132 - 110 = 22 => New Profit % = 22 x 100/110 = 20%

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