Quantitative Aptitude Practice Question and Answer
8Q: It costs Rs. p each to send the first thousand messsages and Rs. q to send each subsequent one . If r is greater than 1,000, how many Rupees will it cost to send r messages ? 1764 05b5cc6cfe4d2b4197774e2ef
5b5cc6cfe4d2b4197774e2ef- 11000 (r - p) + pqfalse
- 21000 p + qrfalse
- 31000 (r - q) + prfalse
- 41000(p - q) + qrtrue
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "1000(p - q) + qr"
Explanation :
Answer: D) 1000(p - q) + qr Explanation: We need to find the total cost to send r messsages, r > 1000. The first 1000 messsages will cost Rs.p each (Or) The total cost of first 1000 messsages = Rs.1000p The remaining (r - 1000) messsages will cost Rs.q each (Or) The cost of the (r - 1000) = Rs.(r - 1000)y Therefore, total cost = 1000p + rq - 1000q = 1000(p - q) + qr
Q: A boat travels 72 km downstream in 8 hours and 84 km upstream in 12 hours. Find the speed of the boat in still water and the speed of the water current ? 1762 05b5cc71ee4d2b4197774f581
5b5cc71ee4d2b4197774f581- 19 and 3 kmphfalse
- 26 and 7 kmphfalse
- 38 and 1 kmphtrue
- 47 and 2 kmphfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "8 and 1 kmph"
Explanation :
Answer: C) 8 and 1 kmph Explanation: Downstream speed = 72km/8hrs = 9 kmphupstream speed = 84km/12hrs = 7 kmphspeed of boat = avg of downstream and upstream speedsspeed of boat = (9+7)/2kmph = 8 kmph.current speed = half of the difference of downstream and upstream speedscurrend speed = (9-7)/2kmph = 1 kmph
Q: An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ? 1758 05b5cc73de4d2b4197774f911
5b5cc73de4d2b4197774f911- 121.4 and 42.8false
- 225.2 and 50.4false
- 331.4208 and 62.8416true
- 433.12 and 66.24false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "31.4208 and 62.8416"
Explanation :
Answer: C) 31.4208 and 62.8416 Explanation: Birds speeds in mtrs/sec is 'x' and '2x' .While flying from Engine to end, relative speed = (x+10) m/secfrom end to engine, flying speed = (2x - 10) mtr/secso 1000/(x+10) + 1000/(2x-10) = 187.5 secssolving it, we getso x = 8.728 m/sec and 2x= 17.456 m/sec x = 31.4208 km/hr and 2x = 62.8416 km/hr.
Q: A quantity of tea is sold at Rs. 5.75 per kilogram. The total gain by selling the tea at this rate is Rs. 60. Find the quantity of tea being sold if a profit of 15% is made on the deal ? 1757 05b5cc70ee4d2b4197774f332
5b5cc70ee4d2b4197774f332- 172 kgsfalse
- 280 kgstrue
- 376 kgsfalse
- 484 kgsfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "80 kgs"
Explanation :
Answer: B) 80 kgs Explanation: Say total cost price of tea is x.Then total profit at a rate of 15% is = (15x/100)According to question,15x/100 = 60so x = 400C.p of the tea is Rs. 400.so total selling price will be = (400+60) = Rs.460so the quantity of the tea will be = (460/5.75) = 80kg.
Q: Two numbers are in the ratio 3 : 7. If 6 be added to each of them, then they are in the ratio 5 : 9. Find the numbers ? 1756 05b5cc6c0e4d2b4197774dab7
5b5cc6c0e4d2b4197774dab7- 111 & 17false
- 27 & 17false
- 39 & 21true
- 413 & 23false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "9 & 21"
Explanation :
Answer: C) 9 & 21 Explanation: Let the two numbers be x and y Given x : y = 3 : 7 .....(1) Now, x+6 : y+6 = 5 : 9 .....(2) From (1), x = 3y/7 From (2), 5y - 9x = 24 => 5y - 9(3y/7) = 24 => y = 21 => From(1), x = 9 Hence, the two numbers be 9 and 21
Q: Two stations A and B are 200 km apart on a straight track. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? 1754 05b5cc764e4d2b4197774fdad
5b5cc764e4d2b4197774fdad- 112 a.m.false
- 21 p.m.false
- 311 a.m.false
- 412 p.m.true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "12 p.m."
Explanation :
Answer: D) 12 p.m. Explanation: Assume both trains meet after 'p' hours after 7 a.m.Distance covered by train starting from A in 'p' hours = 20p kmDistance covered by train starting from B in (p-1) hours = 25(p-1)Total distance = 200=> 20x + 25(x-1) = 200=> 45x = 225=> p= 5Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.
Q: A problem is given to three students whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the probability that the problem will be solved? 1754 05b5cc7d0e4d2b4197775122c
5b5cc7d0e4d2b4197775122c- 11/4false
- 21/2false
- 33/4true
- 47/12false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "3/4"
Explanation :
Answer: C) 3/4 Explanation: Let A, B, C be the respective events of solving the problem and A , B, C be the respective events of not solving the problem. Then A, B, C are independent event ∴A, B, C are independent events Now, P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4 PA=12, PB=23, PC= 34 ∴ P( none solves the problem) = P(not A) and (not B) and (not C) = PA∩B∩C = PAPBPC ∵ A, B, C are Independent = 12×23×34 = 14 Hence, P(the problem will be solved) = 1 - P(none solves the problem) = 1-14= 3/4
Q: Find the Odd one out of the following Numbers? 1754 05b5cc6a4e4d2b4197774cc4b
5b5cc6a4e4d2b4197774cc4b- 13false
- 219false
- 367false
- 4133true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "133"
Explanation :
Answer: D) 133 Explanation: Here among the given numbers, 3, 19, 67 are prime numbers. And 133 is not a prime number. Hence, the odd number of the given numbers is 133.

