Quantitative Aptitude Practice Question and Answer
8Q: What should be the maximum value of B in the following equation?8A9 – 6B2 + 4C6 = 723 1896 05b5cc77fe4d2b419777501b0
5b5cc77fe4d2b419777501b0- 14false
- 21false
- 35false
- 47true
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Answer : 4. "7"
Explanation :
Answer: D) 7 Explanation: 1 1 8 A 9 + 4 C 6 - 6 B 2 7 2 3 We may represent the given sum, as shown below:1 + A + C - B = 12 A + C - B = 11 Now,giving the maximum values to A and C, i.e.A = 9 and C = 9, we get B = 7.
Q: Two numbers are in the ratio 3 : 7. If 6 be added to each of them, then they are in the ratio 5 : 9. Find the numbers ? 1894 05b5cc6c0e4d2b4197774dab7
5b5cc6c0e4d2b4197774dab7- 111 & 17false
- 27 & 17false
- 39 & 21true
- 413 & 23false
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Answer : 3. "9 & 21"
Explanation :
Answer: C) 9 & 21 Explanation: Let the two numbers be x and y Given x : y = 3 : 7 .....(1) Now, x+6 : y+6 = 5 : 9 .....(2) From (1), x = 3y/7 From (2), 5y - 9x = 24 => 5y - 9(3y/7) = 24 => y = 21 => From(1), x = 9 Hence, the two numbers be 9 and 21
Q: The calendar for the year 2007 will be the same for the year ? 1893 05b5cc75ce4d2b4197774fc25
5b5cc75ce4d2b4197774fc25- 12014false
- 22019false
- 32021false
- 42018true
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Answer : 4. "2018"
Explanation :
Answer: D) 2018 Explanation: Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day. Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017Odd day : 1 2 1 1 1 2 1 1 1 2 1 Sum = 14 odd days => 0 odd days.Calendar for the year 2018 will be the same as for the year 2007.
Q: A quantity of tea is sold at Rs. 5.75 per kilogram. The total gain by selling the tea at this rate is Rs. 60. Find the quantity of tea being sold if a profit of 15% is made on the deal ? 1891 05b5cc70ee4d2b4197774f332
5b5cc70ee4d2b4197774f332- 172 kgsfalse
- 280 kgstrue
- 376 kgsfalse
- 484 kgsfalse
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Answer : 2. "80 kgs"
Explanation :
Answer: B) 80 kgs Explanation: Say total cost price of tea is x.Then total profit at a rate of 15% is = (15x/100)According to question,15x/100 = 60so x = 400C.p of the tea is Rs. 400.so total selling price will be = (400+60) = Rs.460so the quantity of the tea will be = (460/5.75) = 80kg.
Q: Vishal and Raghu jointly started a business. Vishal invested three times as Raghu did and invested his money for double time as compared to Raghu. Raghu earned Rs. 4000. If the gain is proportional to the money invested and the time for which the money is invested then the total gain was ? 1891 05b5cc6dee4d2b4197774ea8f
5b5cc6dee4d2b4197774ea8f- 1Rs. 28,000true
- 2Rs. 18,000false
- 3Rs. 14,000false
- 4Rs. 8,000false
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Answer : 1. "Rs. 28,000"
Explanation :
Answer: A) Rs. 28,000 Explanation: Investments ratio is = 3:1Time period ratio is = 2:1 As they are proportional to gain ------Gain ratio of Vishal and raghu = 6:1 But given Raghu got Rs. 4000, =? 1 ----- 4000 7 ----- ? => Rs.28,000 The total gain = Rs.28,000
Q: Find the sum of the all the numbers formed by the digits 2,4,6 and 8 without repetition. Number may be of any of the form like 2,24,684,4862 ? 1891 05b5cc701e4d2b4197774f1bc
5b5cc701e4d2b4197774f1bc- 1133345false
- 2147320true
- 313320false
- 4145874false
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Answer : 2. "147320"
Explanation :
Answer: B) 147320 Explanation: Sum of 4 digit numbers = (2+4+6+8) x P33 x (1111) = 20 x 6 x 1111 = 133320 Sum of 3 digit numbers = (2+4+6+8) x P23 x (111) = 20 x 6 x 111 = 13320 Sum of 2 digit numbers = (2+4+6+8) x P13 x (11) = 20 x 3 x 11 = 660 Sum of 1 digit numbers = (2+4+6+8) x P03 x (1) = 20 x 1 x 1 = 20 Adding All , Sum = 147320
Q: A boat travels 72 km downstream in 8 hours and 84 km upstream in 12 hours. Find the speed of the boat in still water and the speed of the water current ? 1888 05b5cc71ee4d2b4197774f581
5b5cc71ee4d2b4197774f581- 19 and 3 kmphfalse
- 26 and 7 kmphfalse
- 38 and 1 kmphtrue
- 47 and 2 kmphfalse
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Answer : 3. "8 and 1 kmph"
Explanation :
Answer: C) 8 and 1 kmph Explanation: Downstream speed = 72km/8hrs = 9 kmphupstream speed = 84km/12hrs = 7 kmphspeed of boat = avg of downstream and upstream speedsspeed of boat = (9+7)/2kmph = 8 kmph.current speed = half of the difference of downstream and upstream speedscurrend speed = (9-7)/2kmph = 1 kmph
Q: If 6 (P's Capital ) = 8 ( Q's Capital ) = 12 ( R's Capital ) , then out of the total profit of Rs 4650 , R will receive ? 1888 05b5cc6fee4d2b4197774f161
5b5cc6fee4d2b4197774f161- 1Rs. 1033.33true
- 2Rs. 1024false
- 3Rs. 1148.14false
- 4Rs. 1245.32false
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Answer : 1. "Rs. 1033.33"
Explanation :
Answer: A) Rs. 1033.33 Explanation: Let P's capital = p, Q's capital = q and R's capital = r.Then 6p = 8q = 12r=> 3p = 4q = 6r=>q = 3p/4r = 3p/6 = p/2P : Q : R = p : 3p/4 : p/2= 4 : 3 : 2R's share = 4650 * (2/9) = 150*6 = Rs. 1033.33.