Quantitative Aptitude Practice Question and Answer
8Q: Nine different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, how many such words can be formed which have at least one letter repeated ? 2155 05b5cc6c6e4d2b4197774de0e
5b5cc6c6e4d2b4197774de0e- 143929true
- 259049false
- 315120false
- 40false
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Answer : 1. "43929"
Explanation :
Answer: A) 43929 Explanation: Number of words with 5 letters from given 9 alphabets formed = 95 Number of words with 5 letters from given 9 alphabets formed such that no letter is repeated is = 9P5 Number of words can be formed which have at least one letter repeated = 95 - 9P5 = 59049 - 15120 = 43929
Q: The price of pulses has increased by 25%. The percentage of reduction that a family should effect in the use of pulses so as not to increase the expenditure on this account is ? 2154 05b5cc75ce4d2b4197774fc3e
5b5cc75ce4d2b4197774fc3e- 116%false
- 220%true
- 384%false
- 472%false
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Answer : 2. "20%"
Explanation :
Answer: B) 20% Explanation: Reduction in consumption= P100+P X 100%= 25100+25 X 100%= 20%
Q: Pavan and Sravan are two persons. If Pavan works with his actual efficiency and Sravan twice of his actual efficiency then it takes 25 days to complete the work. But If Pavan works twice of his actual efficiency and Sravan with his normal efficiency then the work is completed in 20 days. How many days would it take if Sravan alone works with his actual efficiency (in Days)? 2151 05b5cc6c7e4d2b4197774ded2
5b5cc6c7e4d2b4197774ded2- 150false
- 2100true
- 370false
- 435false
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Answer : 2. "100"
Explanation :
Answer: B) 100 Explanation: Let the Efficiency of pavan be E(P) Let the Efficiency of sravan be E(S) Here Work W = LCM(25,20) = 100 Now, E(P+2S) = 100/25 = 4 ....(1) E(2P+S) = 100/20 = 5 ....(2) Hence, from (1) & (2) we get E(S) = 1 => Number of days Savan alone work to complete the work = 100/1 = 100 days.
Q: Ramesh spent Rs. 38460 on the renovation of his home, Rs. 24468 on buying furniture and remaining 28% of the total amount he had as cash with him. What was the total amount ? 2147 05b5cc6c0e4d2b4197774db00
5b5cc6c0e4d2b4197774db00- 187400true
- 292520false
- 388470false
- 490150false
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Answer : 1. "87400"
Explanation :
Answer: A) 87400 Explanation: Let X be the total amount with Ramesh Given 28% of X = Cash remaining => Amount spent = 72% of X = 38460 + 24468 = 62928 => 72% of X = 62928 => X = ? => X = 87400
Q: Simplify 39.96% of 649.85 ÷13.07 = 45.14 - ? 2146 05b5cc690e4d2b4197774c45a
5b5cc690e4d2b4197774c45a- 125true
- 226false
- 327false
- 428false
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Answer : 1. "25"
Explanation :
Answer: A) 25 Explanation: This can be easily simplified by Approximation process Given 39.96% of 649.85 ÷13.07 = 45.14 - ? can be written as 40% of 650 ÷13 = 45 - ? 40 x 65010013 = 45 - ?? = 45 - 20? = 25.
Q: There are 5 consecutive odd numbers. If the difference between square of the average of first two odd number and the of the average last two odd numbers is 396, what is the smallest odd number? 2146 05b5cc6aee4d2b4197774d165
5b5cc6aee4d2b4197774d165- 129true
- 227false
- 331false
- 433false
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Answer : 1. "29"
Explanation :
Answer: A) 29 Explanation: Let the five consecutive odd numbers be x-4, x-2, x, x+2, x+4 According to the question, Difference between square of the average of first two odd number and the of the average last two odd numbers is 396 i.e, x+3 and x-3 ⇒x + 32 - x - 32 = 396⇒ x2 + 9 + 6x - x2 + 6x - 9 = 396⇒ 12x = 396⇒ x = 33 Hence, the smallest odd number is 33 - 4 = 29.
Q: Out of sixty students, there are 14 who are taking Economics and 29 who are taking Calculus. What is the probability that a randomly chosen student from this group is taking only the Calculus class ? 2145 05b5cc745e4d2b4197774fa1d
5b5cc745e4d2b4197774fa1d- 18/15false
- 27/15true
- 31/15false
- 44/15false
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Answer : 2. "7/15"
Explanation :
Answer: B) 7/15 Explanation: Given total students in the class = 60Students who are taking Economics = 24 andStudents who are taking Calculus = 32Students who are taking both subjects = 60-(24 + 32) = 60 - 56 = 4Students who are taking calculus only = 32 - 4 = 28probability that a randomly chosen student from this group is taking only the Calculus class = 28/60 = 7/15.
Q: A motorboat takes half time to cover a certain distance downstream than upstream. What is the ratio between rate of current and rate of boat in still water? 2143 05b5cc6afe4d2b4197774d1e7
5b5cc6afe4d2b4197774d1e7- 11 : 3true
- 23 : 2false
- 32 : 3false
- 43 : 1false
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Answer : 1. "1 : 3"
Explanation :
Answer: A) 1 : 3 Explanation: Let the speed of the boat in still water is 'w' Speed of the current is 'c' Let the distance between two places is 'd' According to the question, motorboat takes half time to cover a certain distance downstream than upstream. dw+c = 12dw-c => 2w - 2c = w + c => w = 3c => c : w = 1 : 3 Hence, the ratio between rate of current(c) and rate of boat in still water(w) = 1 : 3