Quantitative Aptitude Practice Question and Answer
8Q: A person travels from K to L a speed of 50 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ? 2072 05b5cc6d8e4d2b4197774e764
5b5cc6d8e4d2b4197774e764- 155 kmphfalse
- 258 kmphfalse
- 360 kmphtrue
- 466 kmphfalse
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Answer : 3. "60 kmph"
Explanation :
Answer: C) 60 kmph Explanation: Speed on return trip = 150% of 50 = 75 km/hr. Average speed = (2 x 50 x 75)/(50 + 75) = 60 km/hr.
Q: Find the next number in the given number series? 11, 5.5, 10, 6.5, 9, ? 2071 05b5cc61ee4d2b4197774b753
5b5cc61ee4d2b4197774b753- 16.5false
- 27.5true
- 38.5false
- 410.5false
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Answer : 2. "7.5"
Explanation :
Answer: B) 7.5 Explanation: The given number series follows a pattern that 11 11 - 5.5 = 5.5 5.5 + 4.5 = 10 10 - 3.5 = 6.5 6.5 + 2.5 = 9 9 - 1.5 = 7.5 Hence, the next number in the given number series is 7.5.
Q: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 2068 05b5cc723e4d2b4197774f67c
5b5cc723e4d2b4197774f67c- 160%false
- 250%false
- 370%true
- 445%false
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Answer : 3. "70%"
Explanation :
Answer: C) 70% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420. New C.P. = 125% of Rs. 100 = Rs. 125New S.P. = Rs. 420. Profit = Rs. (420 - 125) = Rs. 295 Required percentage = (295/420) * 100 = 70%(approx)
Q: Two stations A and B are 200 km apart on a straight track. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? 2067 05b5cc764e4d2b4197774fdad
5b5cc764e4d2b4197774fdad- 112 a.m.false
- 21 p.m.false
- 311 a.m.false
- 412 p.m.true
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Answer : 4. "12 p.m."
Explanation :
Answer: D) 12 p.m. Explanation: Assume both trains meet after 'p' hours after 7 a.m.Distance covered by train starting from A in 'p' hours = 20p kmDistance covered by train starting from B in (p-1) hours = 25(p-1)Total distance = 200=> 20x + 25(x-1) = 200=> 45x = 225=> p= 5Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.
Q: Namitha sold a powerbank which is at the cost of Rs. 1950 at a loss of 25%. Find at what cost will she have to sell it to get a profit of 25%? 2065 05b5cc6b1e4d2b4197774d341
5b5cc6b1e4d2b4197774d341- 1Rs. 3680false
- 2Rs. 3560false
- 3Rs. 3320false
- 4Rs. 3250true
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Answer : 4. "Rs. 3250"
Explanation :
Answer: D) Rs. 3250 Explanation: Let the Cost price of the powerbank = Rs. P But given that by selling it at Rs. 1950, it gives a loss of 25% => P x 75100 = 1950=>P = 1950 x 10075 = Rs. 2600Now, to get a profit of 25% Selling Price = 2600 x 125100 = Rs. 3250.
Q: A Committee of 5 persons is to be formed from a group of 6 gentlemen and 4 ladies. In how many ways can this be done if the committee is to be included atleast one lady? 2065 05b5cc7d1e4d2b41977751286
5b5cc7d1e4d2b41977751286- 1123false
- 2113false
- 3246true
- 4945false
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Answer : 3. "246"
Explanation :
Answer: C) 246 Explanation: A Committee of 5 persons is to be formed from 6 gentlemen and 4 ladies by taking. (i) 1 lady out of 4 and 4 gentlemen out of 6 (ii) 2 ladies out of 4 and 3 gentlemen out of 6 (iii) 3 ladies out of 4 and 2 gentlemen out of 6 (iv) 4 ladies out of 4 and 1 gentlemen out of 6 In case I the number of ways = C14×C46 = 4 x 15 = 60 In case II the number of ways = C24×C36 = 6 x 20 = 120 In case III the number of ways = C34×C26 = 4 x 15 = 60 In case IV the number of ways = C44×C16 = 1 x 6 = 6 Hence, the required number of ways = 60 + 120 + 60 + 6 = 246
Q: At what time, between 3 o’clock and 4 o’clock, both the hour hand and minute hand coincide each other ? 2064 05b5cc6d8e4d2b4197774e74b
5b5cc6d8e4d2b4197774e74b- 13:16 7/11false
- 23:16 11/4false
- 33:30false
- 43:16 4/11true
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Answer : 4. "3:16 4/11"
Explanation :
Answer: D) 3:16 4/11 Explanation: Coincide means 00 angle. This can be calculated using the formulafor time A to B means [11m/2 - 30 (A)] Here m gives minutes after A the both hands coincides. Here A = 3, B = 4 0 =11m/2 –30 × 311m = 90 × 2 = 180m= 180/11 = 16 4/11 So time = 3 : 16 4/11
Q: How many days in 4 years? 2057 05b5cc6aee4d2b4197774d1a1
5b5cc6aee4d2b4197774d1a1- 11460true
- 21461false
- 31462false
- 41459false
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Answer : 1. "1460"
Explanation :
Answer: A) 1460 Explanation: Days in 4 years => Let the first year is Normal year i.e, its not Leap year. A Leap Years occurs once for every 4 years. 4 years => 365 + 365 + 365 + 366(Leap year) 4 years => 730 + 731 = 1461 Therefore, Number of Days in 4 Years = 1461 Days.

