Quantitative Aptitude Practice Question and Answer
8Q: By investing Rs. 1620 in 8% stock, Michael earns Rs. 135. The stock is then quoted at ? 2236 05b5cc723e4d2b4197774f686
5b5cc723e4d2b4197774f686- 1Rs. 145false
- 2Rs. 245.1false
- 3Rs. 96true
- 4Rs. 75false
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Answer : 3. "Rs. 96"
Explanation :
Answer: C) Rs. 96 Explanation: Michel earns Rs. 135 by investing Rs. 1620To earn Rs. 8 how much he have to invest...? = (8 x 1620)/135 = Rs. 96
Q: The calendar for the year 2007 will be the same for the year ? 2234 05b5cc75ce4d2b4197774fc25
5b5cc75ce4d2b4197774fc25- 12014false
- 22019false
- 32021false
- 42018true
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Answer : 4. "2018"
Explanation :
Answer: D) 2018 Explanation: Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day. Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017Odd day : 1 2 1 1 1 2 1 1 1 2 1 Sum = 14 odd days => 0 odd days.Calendar for the year 2018 will be the same as for the year 2007.
Q: In following number series only one number is wrong. Find out that wrong or odd number in the series? 6, 78, 858, 7722, 54055, 270270 2233 05b5cc6bce4d2b4197774d8bb
5b5cc6bce4d2b4197774d8bb- 1270270false
- 254055true
- 37722false
- 4858false
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Answer : 2. "54055"
Explanation :
Answer: B) 54055 Explanation: Here the given series follows a pattern that, multiplying the number with odd numbers in decreasing order starting with 13. That is, 6 × 13 = 78 65 × 11 = 858 858 × 9 = 7722 7722 × 7 = 54054 54054 × 5 = 270270 Hence, the wrong number is 54055
Q: The average of the ages of Sushanth, Krish and Rishi is 43 years and the average of the ages of Sushanth, Rishi and Rohit is 49 years. If Rohit is 54 years old, what is Krish's age ? 2232 05b5cc73de4d2b4197774f948
5b5cc73de4d2b4197774f948- 134 yearsfalse
- 226 yearsfalse
- 324 yearsfalse
- 436 yearstrue
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Answer : 4. "36 years"
Explanation :
Answer: D) 36 years Explanation: Let present ages of Sushanth = w, Krish = x, Rishi = y and Rohit = z , thenw + x + y = 43 x 3 = 129 ---(i) andw + y + z = 49 x 3 = 147 ---(ii)Subtracting (i) from (ii), (w+y+z) - (w+x+y) = 147 - 129 , z - x = 18 ---(iii)Given Rohit's age=z=54, so from (iii), x = 54 - 18 = 36.Therefore, Krish age is 36 years.
Q: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 2231 05b5cc723e4d2b4197774f67c
5b5cc723e4d2b4197774f67c- 160%false
- 250%false
- 370%true
- 445%false
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Answer : 3. "70%"
Explanation :
Answer: C) 70% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420. New C.P. = 125% of Rs. 100 = Rs. 125New S.P. = Rs. 420. Profit = Rs. (420 - 125) = Rs. 295 Required percentage = (295/420) * 100 = 70%(approx)
Q: K can finish the work in 18 days and L can do the same work in 15 days. L worked for 10 days and left the job. In how many days, K alone can finish the remaining work ? 2229 05b5cc774e4d2b4197775002f
5b5cc774e4d2b4197775002f- 15.5 daysfalse
- 26 daystrue
- 34.2 daysfalse
- 45 daysfalse
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Answer : 2. "6 days"
Explanation :
Answer: B) 6 days Explanation: L's 10 days work = 115×10=23 Remaining work = 1-23=13 Now, work is done by K in one day = 1/18 1/3 work is done by K in 18×13 = 6 days
Q: Compound interest on a certain sum of money at 20% per annum for 2 years is Rs.5995. What is the SI on the same money at 8% per annum for 6 years ? 2229 05b5cc6cae4d2b4197774e0a9
5b5cc6cae4d2b4197774e0a9- 1Rs. 5989false
- 2Rs. 6540true
- 3Rs. 7844false
- 4Rs. 6789false
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Answer : 2. "Rs. 6540"
Explanation :
Answer: B) Rs. 6540 Explanation: Given C.I = 5984, R = 20% , T = 2yrs C.I = P1+201002-1 5984 = => P = (5995x25)/11 P = Rs. 13625 Now S.I = PTR/100 SI = (13625 x 8 x 6)/100 = Rs. 6540
Q: If 6 men and 3 boys working together, can do four times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time ? 2228 05b5cc6dae4d2b4197774e8d2
5b5cc6dae4d2b4197774e8d2- 11 : 2true
- 22 : 1false
- 33 : 1false
- 41 : 3false
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Answer : 1. "1 : 2"
Explanation :
Answer: A) 1 : 2 Explanation: 6M + 3B = 4(1M + 1B)6M + 3B = 4M + 4B2M = 1B M/B = 1/2