Quantitative Aptitude Practice Question and Answer
8Q: 10 25 45 54 60 75 85 Find the Odd Number? 2227 05b5cc6bce4d2b4197774d897
5b5cc6bce4d2b4197774d897- 154true
- 210false
- 345false
- 485false
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Answer : 1. "54"
Explanation :
Answer: A) 54 Explanation: In given Series, all the numbers except 54 are multiples of 5.
Q: Two stations A and B are 200 km apart on a straight track. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? 2227 05b5cc764e4d2b4197774fdad
5b5cc764e4d2b4197774fdad- 112 a.m.false
- 21 p.m.false
- 311 a.m.false
- 412 p.m.true
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Answer : 4. "12 p.m."
Explanation :
Answer: D) 12 p.m. Explanation: Assume both trains meet after 'p' hours after 7 a.m.Distance covered by train starting from A in 'p' hours = 20p kmDistance covered by train starting from B in (p-1) hours = 25(p-1)Total distance = 200=> 20x + 25(x-1) = 200=> 45x = 225=> p= 5Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.
Q: The ratio of earnings of A and B is 4:5. If the earnings of A increase by 20% and the earnings of B decrease by 20%, the new ratio of their earnings becomes 6:5. What are A's earnings? 2227 05b5cc7c9e4d2b41977750ed6
5b5cc7c9e4d2b41977750ed6- 1Rs.22,000false
- 2Rs.27,500false
- 3Rs. 26,400false
- 4Cannot be determinedtrue
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Answer : 4. "Cannot be determined"
Explanation :
Answer: D) Cannot be determined Explanation:
Q: A person travels from K to L a speed of 50 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ? 2227 05b5cc6d8e4d2b4197774e764
5b5cc6d8e4d2b4197774e764- 155 kmphfalse
- 258 kmphfalse
- 360 kmphtrue
- 466 kmphfalse
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Answer : 3. "60 kmph"
Explanation :
Answer: C) 60 kmph Explanation: Speed on return trip = 150% of 50 = 75 km/hr. Average speed = (2 x 50 x 75)/(50 + 75) = 60 km/hr.
Q: A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red. 2226 05b5cc7d0e4d2b4197775121d
5b5cc7d0e4d2b4197775121d- 123/42false
- 219/42true
- 37/32false
- 416/39false
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Answer : 2. "19/42"
Explanation :
Answer: B) 19/42 Explanation: A red ball can be drawn in two mutually exclusive ways (i) Selecting bag I and then drawing a red ball from it. (ii) Selecting bag II and then drawing a red ball from it. Let E1, E2 and A denote the events defined as follows: E1 = selecting bag I, E2 = selecting bag II A = drawing a red ball Since one of the two bags is selected randomly, therefore P(E1) = 1/2 and P(E2) = 1/2 Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7 PAE2 = Probability of drawing a red ball when the second bag has been selected = 2/6 Using the law of total probability, we have P(red ball) = P(A) = PE1×PAE1+PE2×PAE2 = 12×47+12×26=1942
Q: If the C.I. on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the S.I. on the same sum at the same rate for the same period of time is ? 2224 05b5cc6e0e4d2b4197774eb2a
5b5cc6e0e4d2b4197774eb2a- 1Rs. 580false
- 2Rs. 480true
- 3Rs. 550false
- 4Rs. 470false
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Answer : 2. "Rs. 480"
Explanation :
Answer: B) Rs. 480 Explanation: Let the sum be Rs. P. Then, P1+252x1002-P= 510 P[982- 1] = 510. Sum = Rs. 1920 So, S.I. = (1920 x 25 x 2) / (2 x 100) = Rs. 480
Q: There are 5 consecutive odd numbers. If the difference between square of the average of first two odd number and the of the average last two odd numbers is 396, what is the smallest odd number? 2223 05b5cc6aee4d2b4197774d165
5b5cc6aee4d2b4197774d165- 129true
- 227false
- 331false
- 433false
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Answer : 1. "29"
Explanation :
Answer: A) 29 Explanation: Let the five consecutive odd numbers be x-4, x-2, x, x+2, x+4 According to the question, Difference between square of the average of first two odd number and the of the average last two odd numbers is 396 i.e, x+3 and x-3 ⇒x + 32 - x - 32 = 396⇒ x2 + 9 + 6x - x2 + 6x - 9 = 396⇒ 12x = 396⇒ x = 33 Hence, the smallest odd number is 33 - 4 = 29.
Q: How many digits will be there to the right of the decimal point in the product of 85.44 and .08455 ? 2221 05b5cc723e4d2b4197774f69f
5b5cc723e4d2b4197774f69f- 17false
- 25false
- 34false
- 46true
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Answer : 4. "6"
Explanation :
Answer: D) 6 Explanation: Sum of decimal places = 7. Since the last digit to the extreme right will be zero (since 4 x 5 = 20), so there will be 6 significant digits to the right of the decimal point.