Bank Exams Practice Question and Answer
8Q: What gets wetter and wetter the more it dries? 2666 05b5cc6a8e4d2b4197774cec0
5b5cc6a8e4d2b4197774cec0- 1Soapfalse
- 2Toweltrue
- 3Clothesfalse
- 4Spongefalse
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Answer : 2. "Towel"
Explanation :
Answer: B) Towel Explanation: Towel gets wetter and wetter the more it dries because we use that towel which is dried after used.
Q: I can Honk without using a Horn. Who am I? 2666 05b5cc6abe4d2b4197774cf9e
5b5cc6abe4d2b4197774cf9e- 1Goosetrue
- 2Cranefalse
- 3Penguinfalse
- 4Hummingfalse
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Answer : 1. "Goose"
Explanation :
Answer: A) Goose Explanation: Goose can Honk without using a Horn. Geese are waterfowl of the family Anatidae.
Q: K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ? 2662 05b5cc741e4d2b4197774f9e5
5b5cc741e4d2b4197774f9e5- 112 pmtrue
- 21 pmfalse
- 311 amfalse
- 411:30 amfalse
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Answer : 1. "12 pm"
Explanation :
Answer: A) 12 pm Explanation: let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon.
Q: A man saves Rs. 200 in each of the first three months of his service. In each of the subsequent months his saving increases by Rs. 40 more than the saving of immediately previous month. His total saving from the start of service will be Rs. 11040 after ? 2660 05b5cc71ee4d2b4197774f5b8
5b5cc71ee4d2b4197774f5b8- 119 monthsfalse
- 221 monthstrue
- 318 monthsfalse
- 420 monthsfalse
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Answer : 2. "21 months"
Explanation :
Answer: B) 21 months Explanation: Total savings = 200 + 200 + 200 + 240 + 280 + ... to n months = 11040 = 120 + 80 + 160 + 40 + 200 + 240 + ....n terms= 40 + 80 + 120 + 160 + 200 + 240 + ...n terms= n/2[2a + (n-1)d] + 80 + 40 = 11040= n/2[240 + (n-1)40] = 10920= n[6+n-1] = 546= n[n+5] = 546n = 21
Q: The average age of A and B, 2 years ago was 26. If the age of A, 5 years hence is 40 yrs, and B is 5 years younger to C, then find the difference between the age of A and C? 2660 05b5cc6bbe4d2b4197774d86d
5b5cc6bbe4d2b4197774d86d- 111 yrsfalse
- 29 yrstrue
- 37 yrsfalse
- 413 yrsfalse
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Answer : 2. "9 yrs"
Explanation :
Answer: B) 9 yrs Explanation: Let the present ages of A and B be 'x' and 'y' respectively From the given data, [(x-2) + (y-2)]/2 = 26 => x+y = 56 But given the age of A, 5 years hence is 40 yrs => present age of A = 40 - 5 = 35 yrs => x = 35 => y = 56 - 35 = 21 => Age of B = 21 yrs Given B is 5 years younger to C, => Age of C = 21 + 5 = 26 yrs => Required Difference between ages of A and C = 35 - 26 = 9 yrs.
Q: What is the next number in this series ? 4, 6, 12, 18, 30, 42, 60, ? 2657 05b5cc70be4d2b4197774f2f0
5b5cc70be4d2b4197774f2f0- 171false
- 272true
- 373false
- 469false
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Answer : 2. "72"
Explanation :
Answer: B) 72 Explanation: With close observation, you will note that each number in the list is in the middle of two prime numbers. Thus: 4 is in the middle of 3 and 5, 6 is in the middle of 5 and 7, 12 is in the middle of 11 and 13, 18 is in the middle of 17 and 19, 30 is in the middle of 29 and 31. 42 is in the middle of 41 and 43, 60 is in the middle of 59 and 61. Therefore, the next number would be the one that is in the middle of the next two prime numbers, which is 72 (which is in the middle of 71 and 73).
Q: If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is: 2657 05b5cc6e7e4d2b4197774ed7e
5b5cc6e7e4d2b4197774ed7e- 1Rs. 408false
- 2Rs. 204true
- 3Rs. 412false
- 4Rs. 220false
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Answer : 2. "Rs. 204"
Explanation :
Answer: B) Rs. 204 Explanation: Given ratio = 1/2:2/3:3/4 = 6:8:9 1st part = 782 x 6/23 = Rs. 204.
Q: If x = √8 - √7, y = √6 - √5 and z = √10 - 3, which of the following is true ? 2656 05b5cc6dbe4d2b4197774e955
5b5cc6dbe4d2b4197774e955- 1x > y < zfalse
- 2x < y < zfalse
- 3x > y > zfalse
- 4z < x < ytrue
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Answer : 4. "z < x < y"
Explanation :
Answer: D) z < x < y Explanation: x = √8 - √7 = 1/(√8 + √7) and y = √6 - √5 = 1/(√6 + √5) and z = √10 - 3 = 1/(√10 + 3) As (√8 + √7) > (√6 + √5), (√8 - √7) < (√6 - √5) As (√10 + 3) > (√8 + √7) > (√6 + √5) z < x < y.

