Answer: C) 40 mm Explanation: The ball with which Table Tennis is played is called Ping Pong Ball. According to the International rules, the diameter of the ping pong ball must be not less than 39.5 millimeters and not greater than 40.5  millimeters having a mass of 2.7 grams.

Answer: D) Element Explanation: A substance that cannot be decomposed (broken down) into simpler substances by ordinary chemical means. Examples: gold, iron, carbon, hydrogen, oxygen, nitrogen. Material composed of only one kind of matter throughout (same atoms or same molecules).

Answer: A) 25th and 21st Explanation: Number of students behind Manoj in rank = (31 - 7) = 24. So, Manoj is 25th from the bottom. Number of students behind Satya in rank = (31 - 11) = 20. So, Satya is 21st from the bottom.

Answer: B) only during cell division Explanation: During most of the cell cycle, interphase, the chromosomes are somewhat less condensed and are not visible as individual objects under the light microscope. However during cell division, mitosis, the chromosomes become highly condensed and are then visible as dark distinct bodies within the nuclei of cells. The chromosomes are most easily seen and identified at the metaphase stage of cell division and most of the chromosome images in this gallery are pictures of metaphase chromomosomes. The cell division takes place in mitosis stage.

Answer: B) 3/2 Explanation:  = log 33 + log 23+ log 103log10×3×22        =log33 12+log 23+log 10312log(10×3×22)                 =12log 33+3 log 2+12 log103log10+log3+log22                 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32

Answer: A) India Explanation: Sandalwood is largely found in India and they are government owned and their harvest is controlled.   Naturally grown sandalwood can be easily found in Karnataka, Tamilnadu, Andhra, Kerala, Gujarat, Madhya Pradesh, and U.P. Manipura and in some other states of India.

Answer: D) 10 months Explanation: 7x5: 5xk = 7:10k = 10 months

Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.