Bank Exams Practice Question and Answer
8Q: A train covered k km at 40 kmph and another 2k km at 20 kmph. Find the average speed of the train in covering the entire 3k km ? 1592 05b5cc6dce4d2b4197774e965
5b5cc6dce4d2b4197774e965- 128 kmphfalse
- 224 kmphtrue
- 326 kmphfalse
- 432 kmphfalse
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Answer : 2. "24 kmph"
Explanation :
Answer: B) 24 kmph Explanation: Total time taken = k/40 + 2k/20 hours = 5k/40 = k/8 hours Average speed = 3k/(k/8) = 24 kmph.
Q: What is the sum of all 3 digits number that can be formed using digits 0,1,2,3,4,5 with no repitition ? 1592 05b5cc709e4d2b4197774f2a3
5b5cc709e4d2b4197774f2a3- 128450false
- 226340false
- 332640true
- 436450false
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Answer : 3. "32640"
Explanation :
Answer: C) 32640 Explanation: We know that zero can't be in hundreds place. But let's assume that our number could start with zero. The formula to find sum of all numbers in a permutation is 111 x no of ways numbers can be formed for a number at given position x sum of all given digits No of 1 s depends on number of digits So,the answer us 111 x 20 x (0+1+2+3+4+5) = 33300 We got 20 as follows. If we have 0 in units place we can form a number in 4*5 ways. This is for all numbers. So we have substituted 20 in formula. Now, this is not the final answer because we have included 0 in hundreds place. so we have to remove the sum of all numbers that starts with 0. This is nothing but the sum of all 2 digits numbers formed by 1 2 3 4 5. Because 0 at first place makes it a 2 digit number. So the sum for this is 11 x 4 x (1+2+3+4+5). =660 Hope u understood why we use 4. Each number can be formed in 4x1 ways So, the final answer is 33300-660 = 32640
Q: What is the bond order of N2+? 1591 05b5cc69be4d2b4197774c7f3
5b5cc69be4d2b4197774c7f3- 13false
- 21.5false
- 32.5true
- 42false
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Answer : 3. "2.5"
Explanation :
Answer: C) 2.5 Explanation: Bond Order = 1/2[ Nb - Na] where Nb = Number of electrons in bonding molecular orbitals. Na = Number of Electrons in antibonding molecular orbitals Bond Order of N2⁺: Total number of electrons: 13 Electronic Configuration= :σ1s² σ*1s² σ2s² σ*2s² π 2py² [π2pz² σ2px1 ] Bond Order = [9-4]/2 = 5/2 = 2.5.
Q: Crack the Relation Logical Puzzle ? 1591 05b5cc6cee4d2b4197774e29d
5b5cc6cee4d2b4197774e29d- 1Sonfalse
- 2Himselffalse
- 3Fathertrue
- 4Unclefalse
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Answer : 3. "Father"
Explanation :
Answer: C) Father Explanation: Man's Father is Madhu's Father's Son => Madhu itself. So the Man in the photograph is Madhu's son.
Q: Why is india called bharat? 1591 05b5cc658e4d2b4197774bde7
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Answer :
Explanation :
The name Bharat is derived from the legendary king Bharat who was ancestor of kauravas and pandavas, son of King Dushyanta and Shakuntala. The name India is derived from the river Sindhu which flows in the north west of the country. The Greeks used to call us Indoi meaning the people of the Indus.
Q: What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high ? 1590 05b5cc6e5e4d2b4197774ed1f
5b5cc6e5e4d2b4197774ed1f- 113 mtrue
- 214 mfalse
- 315 mfalse
- 416 mfalse
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Answer : 1. "13 m"
Explanation :
Answer: A) 13 m Explanation: The length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is => d2 = 122 + 42 + 32 = 13mts.
Q: When all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed ? 1590 05b5cc736e4d2b4197774f88d
5b5cc736e4d2b4197774f88d- 122false
- 236true
- 332false
- 426false
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Answer : 2. "36"
Explanation :
Answer: B) 36 Explanation: Total number of students = 54 x 30When arranged in rows of 45, number of rows formed are, 54x3045 = 36.
Q: The breadth of a rectangular field is 75% of its length. If perimeter of the field is 1050 m, what will be th area of field ? 1589 05b5cc6c8e4d2b4197774df0a
5b5cc6c8e4d2b4197774df0a- 165700 sq.mfalse
- 254500 sq.mfalse
- 378700 sq.mfalse
- 467500 sq.mtrue
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Answer : 4. "67500 sq.m"
Explanation :
Answer: D) 67500 sq.m Explanation: Let the length be 'l' and breadth be 'b'. b = l × 3/4__________(a) 2(l+b) = 1050 l+b = 525___________(b) From equations (a) and (b), l = 300m, b = 225 m Area = l × b = 300 × 225 = 67500 sq.m.

