Bank Exams Practice Question and Answer
8Q: 813 967 429 295 648 If the positions of the second and third digits in each of the numbers are interchanged , which of the following will be the sum of the sum of the three digits of the highest number? 1355 05b5cc7c7e4d2b41977750dbe
5b5cc7c7e4d2b41977750dbe- 112false
- 215false
- 316false
- 422true
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Answer : 4. "22"
Explanation :
Answer: D) 22 Explanation:
Q: The term biodiversity refers to 1354 05b5cc662e4d2b4197774beac
5b5cc662e4d2b4197774beac- 1Range of genetic variation within a populationfalse
- 2Total number of different species within a habitatfalse
- 3Both A & Btrue
- 4None of the abovefalse
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Answer : 3. "Both A & B"
Explanation :
Answer: C) Both A & B Explanation: The term biodiversity refers to the variety of life on Earth at all its levels, from genes to ecosystems, and the ecological and evolutionary processes that sustain it.
Q: What should come in place of question mark (?) in the following number series? 38, 195, ?, 4905, 24530, 122655 1354 05b5cc6c4e4d2b4197774dcd2
5b5cc6c4e4d2b4197774dcd2- 1980true
- 2885false
- 3824false
- 41021false
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Answer : 1. "980"
Explanation :
Answer: A) 980 Explanation: The given series follows the pattern that, ×5+5, ×5+5, ×5+5, ×5+5, ×5+5 38 x 5 + 5 = 195 195 x 5 + 5 = 980 980 x 5 + 5 = 4905 4905 x 5 + 5 = 24530 24530 x 5 + 5 = 122655 So the missing number is 980 .
Q: _______has conferred the 'Best Performance Award' for 2015-16 and 2016-17 to Karnataka VIKAS GRAMEEN Bank (KVGB) for its work in the field of credit-linking joint liability groups (JLGs). 1354 05b5cc6cbe4d2b4197774e0ae
5b5cc6cbe4d2b4197774e0ae- 1B) for its work in the field of credit-linking joint liability groups (JLGs). A)false
- 2for its work in the field of credit-linking joint liability groups (JLGs). A) RBI B) RRBfalse
- 3NABARDtrue
- 4SBIfalse
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Answer : 3. "NABARD"
Explanation :
Answer: C) NABARD Explanation:
Q: Read each part of the sentence to find out if there is any error in it. The error, if any, will be in one part of the sentence. The number of that part is the answer. A part of Special development fund is(1) / expected to be released(2) / next month and the provisional(3) / for remaining amount in the new budget(4) 1354 05b5cc6cce4d2b4197774e129
5b5cc6cce4d2b4197774e129- 1(1)false
- 2(2)false
- 3(3)true
- 4(4)false
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Answer : 3. "(3)"
Explanation :
Answer: C) (3) Explanation: 'provision' should replace 'provisional'. A noun is required here and provisional is an adjective. Provision means supplies whereas provisional means temporary or contingent.
Q: What is my PIN number ? 1354 05b5cc6d1e4d2b4197774e39c
5b5cc6d1e4d2b4197774e39c- 193714false
- 242789false
- 336671false
- 493747true
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Answer : 4. "93747"
Explanation :
Answer: D) 93747 Explanation: From the hints, Only two options for 1st and 2nd digits => 4,2 and 9,3 since it is single digits Sum of second and third digit = 10 If 2 => 3rd digit = 8 If 3 => 3rd digit = 7 4th digit = 2nd digit + 1 => (2+1 =3) or (3+1 = 4) Sum of all digits = 30 Let 5th digit be x => 1st possibility = 4 + 2 + 8 + 3 + x = 30 => x = 13 (Not possible since it has 2 digits) => 2nd possibility = 9 + 3 + 7 + 4 + x = 30 => x = 7 Therefore, the PIN is 93747
Q: What least number must be substracted from 627349 so that the remaining number is divisible by 15 ? 1354 05b5cc754e4d2b4197774fb9a
5b5cc754e4d2b4197774fb9a- 11false
- 22false
- 33false
- 44true
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Answer : 4. "4"
Explanation :
Answer: D) 4 Explanation: On dividing 627349 by 15, we get remainder = 4.Therefore, the obtained remainder is the least number to be subtracted from the given number so that the the mnumber is divisible by 15.Here 4 is the least number to be subtracted from 627349 so that it is divisible by 15.
Q: The average of marks in 3 subjects is 224. The first subject marks is twice the second and the second subject marks is twice the third. Find the second subject marks ? 1353 05b5cc6cce4d2b4197774e17c
5b5cc6cce4d2b4197774e17c- 1384false
- 296false
- 3192true
- 4206false
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Answer : 3. "192"
Explanation :
Answer: C) 192 Explanation: Let the third subject marks be 'x'=> Second subject marks = 2x=> Third subject marks = 4xGiven avg = 224x + 2x + 4x = 224 x 3=> 7x = 224 x 3=> x = 96Hence, Second subject marks = 2x = 2 x 96 = 192.