Bank Exams Practice Question and Answer
8Q: If 6 engines consume 24 metric tonnes of coal, when each is working 8 hours day, how much coal will be required for 9 engines, each running 13hours a day, it being given that 2 engines of former type consume as much as 3 engines of latter type ? 3595 05b5cc723e4d2b4197774f672
5b5cc723e4d2b4197774f672- 145 metric tonnestrue
- 247 metric tonnesfalse
- 355 metric tonnesfalse
- 434 metric tonnesfalse
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Answer : 1. "45 metric tonnes"
Explanation :
Answer: A) 45 metric tonnes Explanation: 2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton i.e. 3 engines of latter type consumes 1 ton for one hour Hence 9 engines consumes 3 tons for one hour For 15 hours it is 15 x 3 = 45 metric tonnes.
Q: Solve the Riddle :: Three men were on a boat that was stuck one mile from the shore. One was afraid of Sharks. The other couldn't Swim. And the last one didn't have a life jacket. However, they reached the shore without any problems. How did they do it? 3593 05b5cc69fe4d2b4197774c9dc
5b5cc69fe4d2b4197774c9dc- Show AnswerHide Answer
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Answer :
Explanation :
They walked and did this. It was never specified that the boat was at sea. Since this logic is observed by them to tackle situation.
Q: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ? 3590 05b5cc74fe4d2b4197774fb35
5b5cc74fe4d2b4197774fb35- 1145false
- 2165false
- 3175true
- 4135false
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Answer : 3. "175"
Explanation :
Answer: C) 175 Explanation: Given that, working days = 5 working hours = 8 A man get rupess per hour is Rs.2.40 So in one day the man get total rupees is 2.40 x 8 = 19.2 So in 5 days week the man get total rupees is 19.2 x 5 = 96 So in 4 week the man get total rupees is 96 x 4 = 384 So the man worked for = 160hours in 4 weeks But given that the man earned Rs.432 Hence remaning money is (432-384 = 48)which is earn by doing overtime work Overtime hours = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.
Q: Find the odd one out of the following options. 3589 05b5cc6d6e4d2b4197774e679
5b5cc6d6e4d2b4197774e679- 1Sapphirefalse
- 2Rubyfalse
- 3Topazfalse
- 4Granitetrue
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Answer : 4. "Granite"
Explanation :
Answer: D) Granite Explanation: Except Granite all other options belong to the group of precious stones.
Q: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3589 05b5cc6e5e4d2b4197774ed42
5b5cc6e5e4d2b4197774ed42- 1127.5 mtrue
- 2254 mfalse
- 3184 mfalse
- 4212 mfalse
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Answer : 1. "127.5 m"
Explanation :
Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.
Q: If NAMO = 172 and OM = 56 then, SHIVAY = ? 3588 05b5cc6cee4d2b4197774e237
5b5cc6cee4d2b4197774e237- 1606false
- 2415false
- 3504true
- 4404false
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Answer : 3. "504"
Explanation :
Answer: C) 504 Explanation: (COUNTING OF LETTERS) NAMO = 14 + 1 + 13 + 15 = 43 x 4 = 172, OM = 15 + 13 = 28 x 2 = 56, SHIVAY = 19 + 8 + 9 + 22 + 1 + 25 = 84 x 6 = 504
Q: Each consonant in the word TIRADES is replaced by the previous letter in the English alphabet and each vowel is replaced by the next letter in the English alphabet and the new letters are arranged alphabetically. Which of the following will be the fourth from the right end ? 3582 05b5cc736e4d2b4197774f888
5b5cc736e4d2b4197774f888- 1Sfalse
- 2Qfalse
- 3Jtrue
- 4Ufalse
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Answer : 3. "J"
Explanation :
Answer: C) J Explanation: Given word is TIRADESNow the consonants T, R, D, S are replaced by S, Q, C, RAnd Vowels are I, A, E are replaced by J, B and FThey are arranged alphabeticallyNew word is BCFJQRS The fourth letter from the right end is J.
Q: A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ? 3578 05b5cc731e4d2b4197774f7b5
5b5cc731e4d2b4197774f7b5- 11:3false
- 22:1false
- 33:2true
- 42:3false
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Answer : 3. "3:2"
Explanation :
Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.