Bank Exams Practice Question and Answer

Q: In a certain code DOWN is written as '5@9#' and NAME is written as '#6%3'. How is MODE written in that code ? 3587 0

  • 1
    6@53
    Correct
    Wrong
  • 2
    %@53
    Correct
    Wrong
  • 3
    53%#
    Correct
    Wrong
  • 4
    %#35
    Correct
    Wrong
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Answer : 2. "%@53"
Explanation :

Answer: B) %@53 Explanation: From the given information : D O W N A M E == 5 @ 9 # 6 % 3 MODE = %@53

Q: A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ? 3587 0

  • 1
    45
    Correct
    Wrong
  • 2
    24
    Correct
    Wrong
  • 3
    42
    Correct
    Wrong
  • 4
    54
    Correct
    Wrong
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Answer : 4. "54"
Explanation :

Answer: D) 54 Explanation: By trial and error method from the given options, as 54 - 45 =  (1/11) x (45+54)  = 99/11  = 9 Hence this satisfies the given conditions. Then the woman's husband age is 54.

Q: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ? 3584 0

  • 1
    1900
    Correct
    Wrong
  • 2
    2100
    Correct
    Wrong
  • 3
    1700
    Correct
    Wrong
  • 4
    2000
    Correct
    Wrong
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Answer : 1. "1900"
Explanation :

Answer: A) 1900 Explanation: Given 2000 ---- 54 days The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days. i.e, 2000 ----- 39 days == m ---- 20 days => m x 20 = 2000 x 39 m = 3900 So total men for 20 days is 3900 => 2000 old and 1900 new reinforcement. Hence, reinforcement = 1900.

Q: How many 7 digit numbers can be formed using the digits 1, 2, 0, 2, 4, 2, 4? 3583 0

  • 1
    120
    Correct
    Wrong
  • 2
    360
    Correct
    Wrong
  • 3
    240
    Correct
    Wrong
  • 4
    424
    Correct
    Wrong
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Answer : 2. "360"
Explanation :

Answer: B) 360 Explanation: There are 7 digits 1, 2, 0, 2, 4, 2, 4 in which 2 occurs 3 times, 4 occurs 2 times.    Number of 7 digit numbers = 7!3!×2! = 420   But out of these 420 numbers, there are some numbers which begin with '0' and they are not 7-digit numbers. The number of such numbers beginning with '0'.   =6!3!×2! = 60   Hence the required number of 7 digits numbers = 420 - 60 = 360

Q: The intersection of a column and a row 3582 0

  • 1
    Cell
    Correct
    Wrong
  • 2
    Menu
    Correct
    Wrong
  • 3
    Key
    Correct
    Wrong
  • 4
    Field
    Correct
    Wrong
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Answer : 1. "Cell"
Explanation :

Answer: A) Cell Explanation: The intersection of a column and a row in a spread sheet is called as a cell or a bon.

Q: Programs stored in ROM are called 3580 1

  • 1
    Hardware
    Correct
    Wrong
  • 2
    Firmware
    Correct
    Wrong
  • 3
    Freeware
    Correct
    Wrong
  • 4
    Software
    Correct
    Wrong
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Answer : 2. "Firmware"
Explanation :

Answer: B) Firmware Explanation: The programs which are as permanent as hardware and stored in ROM are known as Firmware.   Data stored in ROM can only be modified slowly, with difficulty, or not at all, so it is mainly used to store firmware (software that is closely tied to specific hardware, and unlikely to need frequent updates) or application software in plug-in cartridges.

Q: When combining with nonmetallic atoms, metallic atoms generally will 3580 0

  • 1
    Lose electrons and forms cations
    Correct
    Wrong
  • 2
    Gain electrons and forms anions
    Correct
    Wrong
  • 3
    Lose electrons and forms anions
    Correct
    Wrong
  • 4
    Gain electrons and forms cations
    Correct
    Wrong
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Answer : 1. "Lose electrons and forms cations"
Explanation :

Answer: A) Lose electrons and forms cations Explanation: When combining with nonmetallic atoms, metallic atoms generally will Lose electrons and forms cations.   As the ionization energy of te metals are very low, so they can easily lose electrons and form positively charged ion called cations.

Q: A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ? 3574 0

  • 1
    4/3 hrs
    Correct
    Wrong
  • 2
    2/3 hrs
    Correct
    Wrong
  • 3
    3/2 hrs
    Correct
    Wrong
  • 4
    1/4 hrs
    Correct
    Wrong
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Answer : 2. "2/3 hrs"
Explanation :

Answer: B) 2/3 hrs Explanation: Let the original speed and time is S and Tthen distance = S x TNow the speed changes to 2/3S and T is T+20As the distance is sameS x T = 2/3Sx(T+20)solving this we get t = 40 minutes =40/60 = 2/3 hour

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