Bank Exams Practice Question and Answer
8Q: How many 6-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that the digits should not repeat and the second last digit is even ? 2540 05b5cc731e4d2b4197774f7bf
5b5cc731e4d2b4197774f7bf- 1521false
- 2720true
- 3420false
- 4225false
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Answer : 2. "720"
Explanation :
Answer: B) 720 Explanation: Let last digit is 2when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways.so for last digit = 2, total numbers=240 Similarly for 4 and 6When last digit = 4, total no. of ways =240and last digit = 6, total no. of ways =240so total of 720 even numbers are possible.
Q: Which memory management technique involves dividing the memory into fixed sized blocks ? 1743 25b5cc731e4d2b4197774f7ba
5b5cc731e4d2b4197774f7ba- 1Pagingtrue
- 2Scalingfalse
- 3Whipingfalse
- 4Trackingfalse
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Answer : 1. "Paging"
Explanation :
Answer: A) Paging Explanation: Paging is a memory management technique in which process address space is broken into blocks of the same size called pages.
Q: A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ? 3430 05b5cc731e4d2b4197774f7b5
5b5cc731e4d2b4197774f7b5- 11:3false
- 22:1false
- 33:2true
- 42:3false
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Answer : 3. "3:2"
Explanation :
Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.
Q: Each of the following series of statements is followed by four sets. Identify the set that is logically consistent.(a) The gap between the average starting salaries of teachers and those of other professionals has shrunk in recent years.(b) The average age of first year teachers is same as it was in 1975.(c) Starting teachers are no longer underpaid.(d) The extent of a persons formal education is a measure by which to determine his level of salary.(e) Over the last few years, the average starting salaries of other professionals have increased by 20% 2154 05b5cc731e4d2b4197774f7b0
5b5cc731e4d2b4197774f7b0- 1e,b,dfalse
- 2e,d,bfalse
- 3a,c,bfalse
- 4a,e,ctrue
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Answer : 4. "a,e,c"
Explanation :
Answer: D) a,e,c Explanation: The statements a,e,c are logically sequenced.
Q: A wholesale dealer allows a discount of 20 % on the marked price to the retailer. The retailer sells at 5% below the marked price. If the customer pays Rs.19 for an article, what profit is made by the retailer on it ? 1678 05b5cc72ce4d2b4197774f7ab
5b5cc72ce4d2b4197774f7ab- 1Rs. 4false
- 2Rs. 3true
- 3Rs. 5false
- 4Rs. 1false
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Answer : 2. "Rs. 3"
Explanation :
Answer: B) Rs. 3 Explanation: Let wholesaler dealers marked price = 100%, Retailer's C.P = 80% And the retailer sells at 5% less than the marked price => S.P = 95%If S.P of 95% of the retailer costs Rs.19 to customer,so its C.P of 80% will cost 80 x 19/95 = 16 Profit made by the retailer = 19-16 = Rs.3
Q: Total number of students in 3 classes of a school is 333 . The number of students in class 1 and 2 are in 3:5 ratio and 2 and 3 class are 7:11 ratio . What is the strength of class that has highest number of students ? 2631 05b5cc72ce4d2b4197774f7a6
5b5cc72ce4d2b4197774f7a6- 1125false
- 2155false
- 3135false
- 4165true
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Answer : 4. "165"
Explanation :
Answer: D) 165 Explanation: Ratio C1:C2 = 3:5 and C2:C3 = 7:11So C1:C2:C3 = 21 : 35 : 55Let the strength of three classes are 21x, 35x and 55x respectively, then Given that 21x + 35x + 55x = 333=> 111x = 333 or x=3So strength of the class with highest number of students =55x = 55x3 = 165.
Q: The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ? 2300 15b5cc72ce4d2b4197774f79c
5b5cc72ce4d2b4197774f79c- 142.2 mtsfalse
- 233.45 mtsfalse
- 366.6 mtstrue
- 458.78 mtsfalse
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Answer : 3. "66.6 mts"
Explanation :
Answer: C) 66.6 mts Explanation: From above diagramAC represents the hill and DE represents the tower Given that AC = 100 m angleXAD = angleADB = 30° (∵ AX || BD ) angleXAE = angleAEC = 60° (∵ AX || CE) Let DE = h Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1) tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)∵ BD = CE and Substitute the value of CE from equation 1 100/√3 = 100−h(√3) => h = 66.66 mts The height of the tower = 66.66 mts.
Q: 5/9 of the part of the population in a village are females. If 30 % of the females are married. The percentage of unmarried males in the total males is ? 1894 05b5cc72ce4d2b4197774f7a1
5b5cc72ce4d2b4197774f7a1- 162.5 %true
- 2125 %false
- 384.32 %false
- 446.87 %false
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Answer : 1. "62.5 %"
Explanation :
Answer: A) 62.5 % Explanation: Let total population = p number of females = 5p/9number of males =(p-5p/9) = 4p/9married females = 30% of 5p/9 = 30x5p/100x9 = p/6married males = p/6unmarried males =(4p/9-p/6) = 5p/18Percentage of unmarried males in the total males = {(5p/18)/4p/9}x100 = (5p/18)x(9/4p) = 125/2 % = 62.5%