Answer: B) 100 Explanation: Let the Efficiency of pavan be E(P) Let the Efficiency of sravan be E(S) Here Work W = LCM(25,20) = 100 Now, E(P+2S) = 100/25 = 4 ....(1) E(2P+S) = 100/20 = 5 ....(2) Hence, from (1) & (2) we get E(S) = 1 => Number of days Savan alone work to complete the work  = 100/1 = 100 days.

Answer: C) Hyderabad Explanation:

Answer: D) 7:3 Explanation: Ratio of Milk and water in a vessel A is 4 : 1   Ratio of Milk and water in a vessel B is 3 : 2   Ratio of only milk in vessel A = 4 : 5   Ratio of only milk in vessel B = 3 : 5   Let 'x' be the quantity of milk in vessel C   Now as equal quantities are taken out from both vessels A & B   => 4/5     :     3/5               x   3/5-x          x - 4/5   => 35-xx-45 = 11 (equal quantities)   => x = 7/10   Therefore, quantity of milk in vessel C  = 7   => Water quantity = 10 - 7 = 3   Hence the ratio of milk & water in vessel 3 is 7 : 3

Answer: B) 2400 Explanation: Given (49.001)2  = ? => =~ 49 x 49 =~ 2401 =~ 2400

Answer: D) Karnataka Bank Explanation:

Answer: A) 20720 Explanation: Let N be the required number.   => 60100x27x34xN=2664   => N = 2664x2x7x5/9    => N = 20720.

Answer: C) 20% Explanation: Given       125% ---- 3400 => 100% ---- ? => ? = 3400x100/125 = 2720 => Cost price of the article = Rs. 2720 Profit when article sold at Rs. 3265 = 3265 - 2720 = 545 Hence, Profit% = Gain x 100/cost price => P% = 545 x 100/2720 => P% = 20%

Answer: D) 10 days Explanation: Ratio of efficiencies of Priya and Sai is Sai : Priya = 160 : 100 = 8 : 5 Given Priya completes the work in 16 days Let number of days Sai completes the work be 'd' => 5×16 = 8×d d = 10 days. Therefore, number of days Sai completes the work is 10 days.