Practice Question and Answer
8 Q: The folk instrument used by Bhopa in 'Phad of Paabuji' is
7592 062a08fbd03a63656a29c314c
62a08fbd03a63656a29c314c- 1Ravan Hatthatrue
- 2Kundifalse
- 3Manjeerafalse
- 4Pungifalse
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Answer : 1. "Ravan Hattha "
Explanation :
1. The folk instrument used by Bhopa in 'Pabuji Ki Phad' is Ravanahatha. It is a type of musical instrument made of a coconut bowl. There is a hole at the bottom of this bowl and there is a wooden stick in this hole. Bhopa sings 'Pabuji ki Phad' by playing this stick.
2. 'Pabuji Ki Phad' narrates the life and bravery of Pabuji, the folk deity of Rajasthan. It is a type of folk painting which is made of cloth. 'Pabuji Ki Phad' is sung by Bhopa. Bhopa plays Ravanahatha while singing 'Pabuji Ki Phad'.
Q: Complete the following alphabet series?
BAZ, DBY, FCX, ?
7591 06050692fa01bc44789a4c960
6050692fa01bc44789a4c960BAZ, DBY, FCX, ?
- 1FXWfalse
- 2EFXfalse
- 3FEYfalse
- 4HDWtrue
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Answer : 4. "HDW"
Q: Which of the following countries has the highest coal content?
7590 15e37e2c1ae5acc1dfb09478f
5e37e2c1ae5acc1dfb09478f- 1Australiafalse
- 2Chinatrue
- 3New zelandfalse
- 4Brazilfalse
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Answer : 2. "China"
Explanation :
The three largest coal producers – China, India and Indonesia – all produced record amounts in 2022. In March 2023, both China and India set new monthly records, with China surpassing 400 million tonnes for the second time ever and India surpassing 100 million tonnes for the first time.
Q: A, B and C together earn Rs. 2700 in 18 days. A and C together earn Rs. 940 in 10 days. B and C together earn Rs. 1520 in 20 days. Find the daily earning of C.
7587 05f59f4a0b772fe2f8b23903f
5f59f4a0b772fe2f8b23903f- 1Rs. 10false
- 2Rs. 40false
- 3Rs. 20true
- 4Rs. 15false
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Answer : 3. "Rs. 20"
Q: In a certain code language 'how many goals scored' is written as '5397'; 'many more matches' is written as '982'; and 'he scored five' is written as '163'. How is 'goals' written in that code language ? 7585 05b5cc758e4d2b4197774fc05
5b5cc758e4d2b4197774fc05- 15false
- 27false
- 33false
- 4Data is not sufficienttrue
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Answer : 4. "Data is not sufficient"
Explanation :
Answer: D) Data is not sufficient Explanation: From the given data,how many goals scored = 5397....(1)many more matches = 982.....(2)he scored five = 163.....(3)from (1)&(2), many = 9 ....(4)from (1)&(3), scored = 3 ....(5)Using (4)&(5)in(1), we get goals = 5 or 7.
Q: The computer’s processor consists of following parts
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5d42b9c357579c3e8f50ade5- 1CPU and Main memoryfalse
- 2Hard disc and Floppy discfalse
- 3Main Memory and Storagetrue
- 4Operating system and Applicationsfalse
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Answer : 3. "Main Memory and Storage"
Q: For x∈N, x>1, and p=logxx+1, q=logx+1x+2 then which one of the following is correct? 7578 25b5cc7d0e4d2b419777511ff
5b5cc7d0e4d2b419777511ff- 1p < qfalse
- 2p = qfalse
- 3p > qtrue
- 4can't be determinedfalse
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Answer : 3. "p > q"
Explanation :
Answer: C) p > q Explanation: kl>k+1l+1 for (k,l) > 0 and k > l Let k = x+1 and l = x Therefore, x+1x>(x+1)+1(x)+1 (x + 1) > x Therefore, log(x+1)log(x)>log(x+2)log(x+1) ⇒logxx+1 >logx+1x+2
Q: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples ? 7564 05b5cc6e3e4d2b4197774ec98
5b5cc6e3e4d2b4197774ec98- 16/7false
- 219/21false
- 37/31false
- 45/21true
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Answer : 4. "5/21"
Explanation :
Answer: D) 5/21 Explanation: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁) As remaining person can be any one among three couples left. Required probability = (⁵C₂ x ⁶C₁)/¹⁰C₅= (10 x 6)/252 = 5/21

