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Q:
When (6767 +67) is divided by 68, the remainder is-
1130 0

Answer : 3. "66"
Explanation :
(6767+ 67) = 67(6766 + 166)
As 66 is an even number
We know 6766 is an even number
We know (6766 + 1) is perfectly divisible by (67 + 1)
i.e. 68
We know The remainder = 66
(6767+ 67) = 67(6766 + 166)

Q:
The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is –
939 0

Answer : 4. "28"
Explanation :
Let the consecutive odd numbers be x and (x+2)
We know that x2 + (x + 2)2 = 394
We know x2 + x2 + 4x + 4 = 394
We know 2 x2 +4x – 390 = 0
We know x2 + 2x – 195 = 0
We know (x +15) (x-13) = 0
We know x = 13
We know Required sum = 13 +15 =28

Q:
√6+√6+√6+… is equal to –
888 0

Answer : 4. "3"
Explanation :
Let √6+√6+√6+…. be x.
We know x =√6+x
We know x2 = 6+x
We know x2 - x – 6 = 0
We know (x-3) (x+2) = 0
We know x = 3

Q:
The value of (81)3.6 * (9)2.7/ (81)4.2 * (3) is __
1134 0

Answer : 3. "9"
Explanation :
(81)3.6 * (9)2.7/(81)4.2 * (3) = (3)14.4 * (3)5.4/(3)16.8 * (3)
= 314.4+5.4-16.8-1
= 32
= 9

Q:
The product of 2 numbers is 1575 and their quotient is 9/7. Then the sum of the numbers is –
846 0

Answer : 3. "80"
Explanation :
Let the numbers be x and y .
We know xy = 1575
And x/y = 9/7
We know xy/x/y = 1575/9/7
We know y2 = 1225
We know y = 35 and x = 45
We know The sum of the numbers = 45+35
= 80

Q:
P, Q and R enter into a partnership. P invests Rs. 8000 for the whole year, Q puts in Rs. 12000 at the first and increasing to Rs. 16000 at the end of 4 months, whilst R puts in at first Rs. 16000 but withdraw Rs. 4000 at the end of 9 months. Find the profit of P at the end of year, if the total profit is Rs. 22600.
1039 0

Answer : 1. "Rs. 4800"

Q:
Virat starts a business with Rs.6,500 and after 8 months Sohan joins Virat as his partner. After 4 years the profit is divided in the ratio of 13 : 12. What is Sohan contribution in the capital?
975 0

Answer : 2. "Rs. 7200"

Q:
Two friends Pankaj and Raju entered into a partnership by investing an amount of Rs 6000 and Rs 9000 respectively and ratio of their period of investment is 2: 3. Find the profit share of Pankaj if profit share of Raju is Rs 45,000.
926 0

Q: When (6767 +67) is divided by 68, the remainder is- 1130 06303364629cb46304423ee34

Answer : 3. "66" Explanation :(6767+ 67) = 67(6766 + 166)As 66 is an even numberWe know 6766 is an even numberWe know (6766 + 1) is perfectly divisible by (67 + 1)i.e. 68We know The remainder = 66(6767+ 67) = 67(6766 + 166)

Q: The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is – 939 06303357ffef7996822e8f226

Answer : 4. "28" Explanation :Let the consecutive odd numbers be x and (x+2)We know that x2 + (x + 2)2 = 394We know x2 + x2 + 4x + 4 = 394We know 2 x2 +4x – 390 = 0We know x2 + 2x – 195 = 0We know (x +15) (x-13) = 0We know x = 13We know Required sum = 13 +15 =28

Q: √6+√6+√6+… is equal to – 888 0630334cec3bfb21b4ac22a32

Answer : 4. "3" Explanation :Let √6+√6+√6+…. be x.We know x =√6+xWe know x2 = 6+xWe know x2 - x – 6 = 0We know (x-3) (x+2) = 0We know x = 3

Q: The value of (81)3.6 * (9)2.7/ (81)4.2 * (3) is __ 1134 063033460c3bfb21b4ac229c4

Answer : 3. "9" Explanation :(81)3.6 * (9)2.7/(81)4.2 * (3) = (3)14.4 * (3)5.4/(3)16.8 * (3)= 314.4+5.4-16.8-1= 32= 9

Q: The product of 2 numbers is 1575 and their quotient is 9/7. Then the sum of the numbers is – 846 0630333c0c3bfb21b4ac2185c

Answer : 3. "80" Explanation :Let the numbers be x and y .We know xy = 1575And x/y = 9/7We know xy/x/y = 1575/9/7We know y2 = 1225We know y = 35 and x = 45We know The sum of the numbers = 45+35= 80

Answer : 1. "Rs. 4800"

Q: Virat starts a business with Rs.6,500 and after 8 months Sohan joins Virat as his partner. After 4 years the profit is divided in the ratio of 13 : 12. What is Sohan contribution in the capital? 975 062ff92f1a6d1894ab156f418

Answer : 2. "Rs. 7200"

Q: Two friends Pankaj and Raju entered into a partnership by investing an amount of Rs 6000 and Rs 9000 respectively and ratio of their period of investment is 2: 3. Find the profit share of Pankaj if profit share of Raju is Rs 45,000. 926 062ff9271fef7996822de2641

Answer : 2. "Rs 20,000"

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Q:
When (6767 +67) is divided by 68, the remainder is-
1130 0

Answer : 3. "66"
Explanation :
(6767+ 67) = 67(6766 + 166)
As 66 is an even number
We know 6766 is an even number
We know (6766 + 1) is perfectly divisible by (67 + 1)
i.e. 68
We know The remainder = 66
(6767+ 67) = 67(6766 + 166)

Q:
The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is –
939 0

Answer : 4. "28"
Explanation :
Let the consecutive odd numbers be x and (x+2)
We know that x2 + (x + 2)2 = 394
We know x2 + x2 + 4x + 4 = 394
We know 2 x2 +4x – 390 = 0
We know x2 + 2x – 195 = 0
We know (x +15) (x-13) = 0
We know x = 13
We know Required sum = 13 +15 =28

Q:
√6+√6+√6+… is equal to –
888 0

Answer : 4. "3"
Explanation :
Let √6+√6+√6+…. be x.
We know x =√6+x
We know x2 = 6+x
We know x2 - x – 6 = 0
We know (x-3) (x+2) = 0
We know x = 3

Q:
The value of (81)3.6 * (9)2.7/ (81)4.2 * (3) is __
1134 0

Answer : 3. "9"
Explanation :
(81)3.6 * (9)2.7/(81)4.2 * (3) = (3)14.4 * (3)5.4/(3)16.8 * (3)
= 314.4+5.4-16.8-1
= 32
= 9

Q:
The product of 2 numbers is 1575 and their quotient is 9/7. Then the sum of the numbers is –
846 0

Answer : 3. "80"
Explanation :
Let the numbers be x and y .
We know xy = 1575
And x/y = 9/7
We know xy/x/y = 1575/9/7
We know y2 = 1225
We know y = 35 and x = 45
We know The sum of the numbers = 45+35
= 80

Q:
Virat starts a business with Rs.6,500 and after 8 months Sohan joins Virat as his partner. After 4 years the profit is divided in the ratio of 13 : 12. What is Sohan contribution in the capital?
975 0

Q:
Two friends Pankaj and Raju entered into a partnership by investing an amount of Rs 6000 and Rs 9000 respectively and ratio of their period of investment is 2: 3. Find the profit share of Pankaj if profit share of Raju is Rs 45,000.
926 0