Aptitude Practice Question and Answer
8 Q: By reducing the circumference of a circle by 50 percent, by what percentage will its area decrease?
1350 05f97fd0ed8201a50c268dea6
5f97fd0ed8201a50c268dea6- 112.5 %false
- 225 %false
- 375 %true
- 450 %false
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Answer : 3. "75 % "
Q: In a circle of radius 17 cm, two parallel chords of lengths 30 cm. and 16 cm are drawn. If both the chords are on the same side of the center, then the distance between the chords is -
1350 0609a6719f738a51c29ae2b02
609a6719f738a51c29ae2b02- 17 cm.true
- 217 cm.false
- 39 cm.false
- 423 cm.false
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Answer : 1. "7 cm. "
Q: Area of the triangle formed by the graph of the straight lines x - y = 0, x + y = 2 and the x-axis is:
1350 05f02c73697db791f15e27e44
5f02c73697db791f15e27e44- 12 sq unitsfalse
- 24 sq unitsfalse
- 31 sq unittrue
- 4None of thesefalse
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Answer : 3. "1 sq unit "
Q: If $$\sqrt{a}+\sqrt{b}=15 \ and \ (\sqrt{a}-\sqrt{b} )=3$$ then the value of $$\sqrt{ab/4} $$ is
1349 05f1fe73c0540cb2ffb0522c3
5f1fe73c0540cb2ffb0522c3- 1$$27\over 2$$true
- 25false
- 36false
- 47false
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Answer : 1. "$$27\over 2$$"
Q: Find the exact value of the following question:
$$ 3{1\over2} × 3 {1\over 7}+ 5{3\over4}÷{46\over3}=?$$
1349 05e93e7751ca91a3c02dd849d
5e93e7751ca91a3c02dd849d- 1$$ 13{2\over5}$$false
- 2$$ 11{3\over8}$$true
- 313false
- 4None of thesefalse
- 511false
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Answer : 2. "$$ 11{3\over8}$$"
Q: Allowing 20 % and 15 % successive discounts, the selling price of an article becomes ₹ 3,060; then the marked price will be:
1349 05f35356d6137a8134867dc52
5f35356d6137a8134867dc52- 1₹ 4,500true
- 2₹ 4,000false
- 3₹ 4,400false
- 4₹ 5,000false
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Answer : 1. "₹ 4,500 "
Q: Cost of a diamond varies directly as the square of its weight. A diamond broke into four pieces with their weights in the ratio 1 : 2 : 3: 4. If the loss in the total value of the diamond was Rs.7000, the price of the original diamond was
1349 06022732d2dc71d4148a1bc47
6022732d2dc71d4148a1bc47- 1Rs.100000true
- 2Rs.140000false
- 3Rs. 150000false
- 4Rs.175000false
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Answer : 1. "Rs.100000"
Q: In the figure given below, AD bisects ∠BAC. If the area of ΔABD=40 cm2 and AC=3AB, then the area of ΔABC:

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5f59ce72b772fe2f8b222a04
- 1$$ {150 \ cm^{2}}$$false
- 2$$ {100 \ cm^{2}}$$false
- 3$$ {120 \ cm^{2}}$$true
- 4$$ {160 \ cm^{2}}$$false
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