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Q: In a family, the average age of father and son, father and mother, and mother and son are 25, 40 and 24 years. Age of son is- 1858 0

Answer : 1. "9 years"

Q: Ten years back A’s age was half of B’s age. If their present age ratio 3:4. What is the sum of their present age? 1845 0

Answer : 3. "35"

Q:
In the following questions two equations numbered I and II are given. You have to solve both the equations and ____
I.\(x^2 -218 = 106\)
II.\(y^2 - 37y + 342 = 0\)
Give answer
(A) x > y
(B) x ≥ y
(C) x < y
(D) x ≤ y
(E) x=y or the relationship cannot be established
1807 0

Answer : 4. "D"

Q: 15 years back ratio of the age of father and son was 6:1. 5 years after it will be 2:1. What is father’s present age? 1793 0

Answer : 1. "45"

Q:
The average weight of P and his three friends is 55 kg. If P is 4 kg more than the average weight of his three friends, what is P's weight (in kg)?
1791 0

Answer : 1. "58"

Q: A man’s age before 2 years was 6 times of his son’s age. After 18 years, his age will be two times of his son’s age. Their respective ages are- 1778 0

Answer : 2. "32 years, 7 years"

Q:
The base of a triangle is 15 cm and height is 12 cm. The height of another triangle of double the area having the base 20 cm is
1769 0

Answer : 2. "18 cm"
Explanation :
Area of first triangle =1/21215=90
and second triangle Area will be 180 according to question that we can say
180=1/2h20
h=18 cm ans

Q:
A certain sum is deposited for 4 years at a rate of 10% per annum on compound interest compounded annually. The difference between ihe interest at the end of 2 years and that at the end of 4 years is ₹5,082. Find the sum (in ₹).
1664 0

Q: In a family, the average age of father and son, father and mother, and mother and son are 25, 40 and 24 years. Age of son is- 1858 05d0ca6f90cbb1019f5248230

Answer : 1. "9 years"

Q: Ten years back A’s age was half of B’s age. If their present age ratio 3:4. What is the sum of their present age? 1845 05d0ca32e23ee2e06e9eae230

Answer : 3. "35"

Q: In the following questions two equations numbered I and II are given. You have to solve both the equations and ____I.\(x^2 -218 = 106\)II.\(y^2 - 37y + 342 = 0\)Give answer(A) x > y(B) x ≥ y(C) x < y(D) x ≤ y(E) x=y or the relationship cannot be established 1807 05d85f494d0d7a00e4ecb7a62

Answer : 4. "D"

Q: 15 years back ratio of the age of father and son was 6:1. 5 years after it will be 2:1. What is father’s present age? 1793 05d0ca65223ee2e06e9eae23b

Answer : 1. "45"

Q: The average weight of P and his three friends is 55 kg. If P is 4 kg more than the average weight of his three friends, what is P's weight (in kg)? 1791 0646cab9547aa1736035f5889

Answer : 1. "58"

Q: A man’s age before 2 years was 6 times of his son’s age. After 18 years, his age will be two times of his son’s age. Their respective ages are- 1778 05d0cac3b0cbb1019f5248247

Answer : 2. "32 years, 7 years"

Q: The base of a triangle is 15 cm and height is 12 cm. The height of another triangle of double the area having the base 20 cm is 1769 05d7096b19004b376a58bc3c9

Answer : 2. "18 cm" Explanation :Area of first triangle =1/2*12*15=90and second triangle Area will be 180 according to question that we can say180=1/2*h*20h=18 cm ans

Q: A certain sum is deposited for 4 years at a rate of 10% per annum on compound interest compounded annually. The difference between ihe interest at the end of 2 years and that at the end of 4 years is ₹5,082. Find the sum (in ₹). 1664 0646caa5bcdae930acb925b98

Answer : 1. "20,000"

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Q: In a family, the average age of father and son, father and mother, and mother and son are 25, 40 and 24 years. Age of son is- 1858 0

Q: Ten years back A’s age was half of B’s age. If their present age ratio 3:4. What is the sum of their present age? 1845 0

Q:
In the following questions two equations numbered I and II are given. You have to solve both the equations and ____
I.\(x^2 -218 = 106\)
II.\(y^2 - 37y + 342 = 0\)
Give answer
(A) x > y
(B) x ≥ y
(C) x < y
(D) x ≤ y
(E) x=y or the relationship cannot be established
1807 0

Q: 15 years back ratio of the age of father and son was 6:1. 5 years after it will be 2:1. What is father’s present age? 1793 0

Q:
The average weight of P and his three friends is 55 kg. If P is 4 kg more than the average weight of his three friends, what is P's weight (in kg)?
1791 0

Q: A man’s age before 2 years was 6 times of his son’s age. After 18 years, his age will be two times of his son’s age. Their respective ages are- 1778 0

Q:
The base of a triangle is 15 cm and height is 12 cm. The height of another triangle of double the area having the base 20 cm is
1769 0

Answer : 2. "18 cm"
Explanation :
Area of first triangle =1/21215=90
and second triangle Area will be 180 according to question that we can say
180=1/2h20
h=18 cm ans

Q:
A certain sum is deposited for 4 years at a rate of 10% per annum on compound interest compounded annually. The difference between ihe interest at the end of 2 years and that at the end of 4 years is ₹5,082. Find the sum (in ₹).
1664 0