In the following questions two equations numbered I and II are given. You have to solve both the equations and ____
I.$$\sqrt { 361} x+\sqrt { 16}=0 \ $$
II.$$\sqrt { 441} y+\ { 4}=0 \ $$
Give answer
(A) x> y
(B) x ≥ y
(C) x< y
(D) x ≤ y
(E) x=y or the relationship cannot be established

In the following question two equations numbered I and II are given. You have to solve both the equations and ____
I.$$ {15\over \sqrt {x}}-{2\over \sqrt {x}}=6\sqrt {x}$$
II.$$ {\sqrt {y}\over 4}-{7\sqrt {y}\over \sqrt {12}}={1\over \sqrt {y}}$$
Give answer
(A) x>y
(B) x≥y
(C) x<y
(D) x≤y
(E) x=y or the relationship cannot be established

What are the roots of the quadratic equations?

  $$(x^2 + 3x - 154 = 0)$$

Simplification the following equations

Directions : What will come in the place of the question mark (?) in the following number series?

16, ?, 8, 12, 24, 60