The number of sides in two regular polygons are in the ratio of 5 : 4. The difference between their Interior angles of the polygon is 6⁰ . Then the number of sides are 

PQRS is square whose side is 20 cm. By joining opposite vertices of PQRS are get four triangles. What is the sum of the perimeters of the four triangles?

ABCD is a cyclic quadrilateral and AD is a diameter. If ∠DAC=55° then value of ∠ABC is

In an isosceles triangles ABC, AB=AC the median drawn on the same arms are perpendicular to each other find AB/BC?

Find the area of the circle formed in an equilateral triangle of side 42 cm. Using (π=22/7)

What is the area (in cm²) of the circumcircle of a triangle whose sides are 6 cm, 8 cm and 10 cm respectively?

ABC is an isosceles triangle with AB = AC. The side BA is produced to D such that AB = AD. If ∠ABC = 30°, then ∠BCD is equal to 

ABC is an isosceles triangle with AB = AC, A circle through B touching AC at the middle point of Q, intersects AB at P. Then AP : AB is :