Geometry Questions and answer Practice Question and Answer
8 Q: If ABCDEF is a regular hexagon, then what is the value (in degrees) of ∠ADB?
1476 06009472370bfa73e5e1e143c
6009472370bfa73e5e1e143c- 115false
- 230true
- 345false
- 460false
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Answer : 2. "30"
Q: X and Y are centres of circles of radius 9 cm. and 2 cm respectively XY=17 cm. Z is the centre of a circle of radius r cm which touches the above circles externally. Given that - ∠xzy = 90o the value of r is -
1475 060532a174999e13f2a6d2c2f
60532a174999e13f2a6d2c2f- 113 cmfalse
- 26 cmtrue
- 39 cmfalse
- 48 cmfalse
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Answer : 2. "6 cm"
Q: In the figure below, find the value of AB.
1468 0601a521bc12de45b38e1fd54
601a521bc12de45b38e1fd54- 1$$ {\sqrt{ 120}}$$false
- 2$$ {\sqrt{ 112}}$$true
- 3$$ {\sqrt{ 140}}$$false
- 4$$ {\sqrt{ 129}}$$false
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Answer : 2. "$$ {\sqrt{ 112}}$$"
Q: In ΔABC, ∠C=90° and D is a point on CB such that AD is the bisector of ∠A. If AC=5 cm and BC=12 cm, then what is the length of AD?
1468 06053230ba01bc44789ae7037
6053230ba01bc44789ae7037- 1$$ {10\over 3}{cm}$$false
- 2$$ {5\sqrt{13}\over 6}{ \ cm}$$false
- 3$$ {5\sqrt{13}\over 3}{ \ cm}$$true
- 4$$ {20\over 3} {\ cm}$$false
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Answer : 3. "$$ {5\sqrt{13}\over 3}{ \ cm}$$"
Q: Find the value of ∠OBE=?
1460 05f0ec5c8dcdb5f61f5c484ff
5f0ec5c8dcdb5f61f5c484ff- 1100°false
- 2120°true
- 3115°false
- 4140°false
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Answer : 2. "120°"
Q: The radius of a circle is 14 cm. what is area of another circle having radius 1.5 times the actual circle?
1458 0603f6563e759ac364c912200
603f6563e759ac364c912200- 1$$ {1296{\ cm^{2}}}$$false
- 2$$ {1386 {\ cm^{2}}}$$false
- 3$$ {1352 {\ cm^{2}}}$$false
- 4$$ {1485 {\ cm^{2}}}$$true
- 5$$ {1276 {\ cm^{2}}}$$false
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Answer : 4. "$$ {1485 {\ cm^{2}}}$$"
Q: If the area of a circle, inscribed in a equilateral triangle is 4 π cm2, then what is the area of the triangle?
1457 0605c56e8c5cd4764959facc1
605c56e8c5cd4764959facc1- 1$$ {12\sqrt{3}\ cm^{2}}$$true
- 2$$ {9\sqrt{3}\ cm^{2}}$$false
- 3$$ {8\sqrt{3}\ cm^{2}}$$false
- 4$$ {18\ cm^{2}}$$false
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Answer : 1. "$$ {12\sqrt{3}\ cm^{2}}$$ "
Q: PQRS is square whose side is 20 cm. By joining opposite vertices of PQRS are get four triangles. What is the sum of the perimeters of the four triangles?
1456 0600946dbda57152562aa88d5
600946dbda57152562aa88d5- 1$$ {40{\sqrt{2}}}$$false
- 2$$ {40{\sqrt{2}}}+ 40 $$false
- 3$$ {40{\sqrt{2}}}+ 80 $$false
- 4$$ {80{\sqrt{2}}}+ 80 $$true
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