If ABC is an equilateral triangle and P, Q, R respectively denote the middle points of AB, BC, CA then.

In ∆ABC, ∠A=90⁰ , AD is the bisector of ∠A meeting BC at D, and DE ⊥ AC at E. if AB = 10 cm and AC = 15 cm, then the length of DE, in cm, is:

ABCD is a cyclic quadrilateral. Diagonals BD and AC intersect each other at E. If <BEC = 128° and <ECD = 25°, then what is the measure of <BAC?

ABCD is a cyclic quadrilateral. AB and DC when produced meet at P, If PA 8 cm, PB = 6, PC = 4 cm, then the length (in cm) of PD is

The perimeters of ΔABC and ΔDEF are 43.2 cm and 28.8 cm, respectively, and ΔABC ~ ΔDEF. If DE = 12 cm, then the length of AB is:

If△ABC ∼ △EDF such that AB = 6 cm, DF = 16 cm and DE = 8 cm, then the length of BC is:

ΔABC ~ ΔPQR. The perimeters of ΔABC and ΔPQR are 72 cm and 43.2 cm, respectively. What is the ratio of the are area of ΔABC to the area of ΔPQR?