Which is the largest 3 digit number that is exactly divisible by 15, 25 and 30?

The smallest number which when divided by 18, 24, 38 and 42 leaves the remainder 15, 21,     35 and 39 respectively is :-

Let x be the least number divisible by 13, such that when x is divided by 4, 5, 6, 7, 8 and 12, the remainder in each case is 2. The sum of the digits of x is:

If ' n ' be any natural number , then by which number ( n⁴-n ) is always divisible ? 

$$ {109.07\sqrt{?}}-{61\over 21.02} ×?=47.96\sqrt{?}$$

A number when divided by 893 the remainder is 193. What will be the remainder when it is divided by 47?

Of the three numbers, the sum of the first two is 55, sum of the second and third is 65 and sum of third with thrice of the first is 110. The third number is: 

Direction : What value should come in the place of question mark (?) in the following questions?

3505 × 69.89 ÷ 102 – 1699=?