Let x be the least number divisible by 13, such that when x is divided by 4, 5, 6, 7, 8 and 12, the remainder in each case is 2. The sum of the digits of x is:

The smallest number which when divided by 18, 24, 38 and 42 leaves the remainder 15, 21,     35 and 39 respectively is :-

Which is the largest 3 digit number that is exactly divisible by 15, 25 and 30?

If ' n ' be any natural number , then by which number ( n⁴-n ) is always divisible ? 

The smallest number, which should be added to 756896 so as to obtain a multiple of 11, is :

$$ {109.07\sqrt{?}}-{61\over 21.02} ×?=47.96\sqrt{?}$$

Direction : What value should come in the place of question mark (?) in the following questions?

3505 × 69.89 ÷ 102 – 1699=?

Of the three numbers, the sum of the first two is 55, sum of the second and third is 65 and sum of third with thrice of the first is 110. The third number is: