Given :- Two positive numbers differ by 1280 

When the greater number is divided by the smaller number The quotient is 7 and the remainder is 50 

Concept :- Dividend = Quotient × divisor + remainder 

Calculation :- Let greater number = a and Smaller number = b From question, ⇒ a - b = 1280 ....(1) Again from question, ⇒ a = 7b + 50 ....(2) 

Put the value of a from equation (2) into equation (1) ⇒ 7b + 50 - b = 1280 ⇒ 6b = 1280 - 50 ⇒ 6b = 1230 ⇒ b = (1230/6) ⇒ b = 205 

Put the value of b in equation (1) ⇒ a - 205 = 1280 ⇒ a = 1280 + 205 ⇒ a = 1485 ⇒ Greater number = 1485 ∴ Greater number is 1485

Let the consecutive odd numbers be x and (x+2)

We know that x2 + (x + 2)2 = 394

We know   x2 + x2 + 4x + 4 = 394

We know   2 x2 +4x – 390 = 0

We know   x2 + 2x – 195 = 0

We know  (x +15) (x-13) = 0

We know   x = 13

We know    Required sum = 13 +15 =28

Let the quotient be Q and the remainder be R. Then

Divisor = 7 Q = 3 R

∴ Divisor = 7 Q = 7 × 12 = 84

Dividend = Divisor × Quotient + Remainder = 84 × 12 + 28 = 1008 + 28 = 1036