Percentage problems Practice Question and Answer
8 Q: In a group of students, 70 % can speak English and 65 % can speak Hindi. If 27 % of the students can speak none of the two languages, then what percent of the group can speak both the languages?
2524 05e32700d7a6228708566372b
5e32700d7a6228708566372b- 138%false
- 262%true
- 328%false
- 423%false
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Answer : 2. "62% "
Q: If 10% of m is the same as 20% of n, then m : n is equal to : 2283 05cda918d40678f4146def8ff
5cda918d40678f4146def8ff- 12 : 1true
- 21 : 2false
- 31: 10false
- 41 : 20false
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Answer : 1. "2 : 1"
Q: If 30% of A = 0.25 of B = $$ ({1\over 5}) $$ of C, then A : B : C is equal to : 2007 05cda8daa40678f4146def8d3
5cda8daa40678f4146def8d3- 15 : 6 : 4false
- 25 : 24 : 5false
- 36 : 5 : 4false
- 410 : 12 :15true
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Answer : 4. " 10 : 12 :15"
Q: $${2\over 3}$$ is what percent of $${1\over 3}=? $$ 1721 05cda913e40678f4146def8f9
5cda913e40678f4146def8f9- 150%false
- 2$$33{1\over 3}\% $$false
- 350%false
- 4200%true
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Answer : 4. " 200%"
Q: The price of wheat is reduced by 4 % How many kilogram of wheat can now be bought for the money which was sufficient to buy 48 kg of wheat earlier?
1239 0631f34f2b0a2a82fc5667e2d
631f34f2b0a2a82fc5667e2d- 145 kgfalse
- 250 kgtrue
- 355 kgfalse
- 440 kgfalse
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Answer : 2. "50 kg "
Q: The sum of weights of A and B is 80 kg. 50% of A's weight is $${5\over6}$$ times the weight of B. Find the difference between their weights.
1205 064ccef6ba919c8488e304799
64ccef6ba919c8488e304799- 120 kgtrue
- 210 kgfalse
- 325 kgfalse
- 415 kgfalse
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Answer : 1. "20 kg"
Explanation :
Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.
Given:
- 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
- 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)
We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.
From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y
Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30
Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50
So, the weight of A is 50 kg and the weight of B is 30 kg.
Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20
Therefore, the difference between their weights is 20 kg.
Q: If a number x is 10% less than another number y and y is 10% more than 125, then x is equal to-
1064 0639c8e96d319b37ca1dfd406
639c8e96d319b37ca1dfd406- 1150false
- 2143false
- 3140.55false
- 4123.75true
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Answer : 4. "123.75"
Q: The cost of an article was 75. The cost was first increased by 20% and later on it was reduced by 20%. The present cost of the article is:
1041 0639c91d6c7eb1b240b5fc0e7
639c91d6c7eb1b240b5fc0e7- 172true
- 260false
- 375false
- 490false
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