Simplify the following equation
$$ {\sqrt{(1-sin^{2}θ) ÷{(1-cos^{2}θ)}}}$$

If $$ {1\over3} ({12x\over5}-{1\over2})+{6\over5}={7\over6}$$ then what is the value of x?

The value of $${4- \sqrt{0.04} \over 4+\sqrt{0.4} } $$  is closed to

The value of 24 ÷ 4 ×(3 +3) ÷2 is:

2x + 4y – 8xy -1 =?

$$ { \sqrt{(0.798)^2+0.404×0.798+(0.202)^2}+1=?} $$

5-[4-{3-(3-3-6)}] is equal to:

If the average of 11, 23 and x is 40, then what is the value of x?