Find the value of   $$ {(0.75)^3\over1-.75}+[0.75+(0.75)^2+1]$$

The sum of the squares of 2 number is 146 and the square root of one of them is 5. The cube of the other number is 

1-[5-{2+(-5+6-2)2}] is equal to 

$$ (17)^{2} + 6 × (13)^{2}-212×6$$

Simplify : $$ {(2x)^{2}-(2y)^{2}-(4x)^{2}}$$

If  $$\sqrt{2}=1.414$$, the value of $${ \sqrt{2}-1\over\sqrt{2}+1}$$  is nearest to 

The value of x in the given equation
$$ {23 ^2 + \sqrt{x}=625}$$

$$\sqrt{x}÷ \sqrt{144} = 0.02, $$ then the value of x is