If the average of 11, 23 and x is 40, then what is the value of x?

The largest number of five digits, which is a perfect square is 

The value of x in the given equation
$$ {23 ^2 + \sqrt{x}=625}$$

The sum of the squares of 2 number is 146 and the square root of one of them is 5. The cube of the other number is 

Find the value of   $$ {(0.75)^3\over1-.75}+[0.75+(0.75)^2+1]$$

$$ (17)^{2} + 6 × (13)^{2}-212×6$$

$$\sqrt{x}÷ \sqrt{144} = 0.02, $$ then the value of x is 

Evaluate: $$ {9।3-5।-5।-5।4।÷10\over-3(5)-2×4÷2}$$