Simplify the following equation.
$$ {(100)}^{1\over2}.{(0.001)}^{1\over3}-{(0.0016)}^{1\over4}.{3}^{0}+({5\over4})^{-1} $$

$$ \sqrt{0.00004761} $$   equal to

The Value of $$ {\sqrt{6-\sqrt{17-2\sqrt{72}}}}$$ is closest to:

$$ { \sqrt{(0.798)^2+0.404×0.798+(0.202)^2}+1=?} $$

The least number, by which 1944 must be multiplied so as to make the result a perfect cube is 

Find the value of given equations

$$\left({216\over1} \right) ^{-{2\over3}}÷\left({27\over1} \right) ^{-{4\over3}}=? $$

The largest number of five digits, which is a perfect square is 

Simplify : $$ {(2x)^{2}-(2y)^{2}-(4x)^{2}}$$