If the sum of the squares of three consecutive natural numbers is 110, then the smallest of these natural numbers is:

What is the value of $$ {0.55 × 4.5\over 0.81}$$ ?

Simplify the following expression.

 25-(4÷2)+11.5+9.5

If $$ {(x-2)^{2}+(y-{1\over2})^{2}}=0$$, then the value of $$ {x\over y}$$ is

25.6% of 250 +√ ? = 119

Solve: 12–[26–{2+5×(6–3)}]

Direction : What should come in place of the question (?) in the following question.

$$ {\sqrt{441}}+ {(71)^{2}} -{(?)^{2}}=2707 $$

If p = 8.15, q = 9.06 and r = −17.21, then the value of p³+q³+r³-3pqr