The value of x in the given equation
$$ {23 ^2 + \sqrt{x}=625}$$

The smallest number that must be subtracted from 1000 to make the resulting number a perfect square is 

  $$25\% \ of (50\% \ of \ 30\% \ of \ 150)\over 40\% of \ 2250$$ is equal to:

Given that ( 1² +2²+3²+………..+10²)=385, the value of (2²+4²+6²+……20²) is equal to

If $${b\over a}=0.7$$ find the value of $${a-b\over a+b}={11\over34}.$$

If $$ {y={2x-1\over x+3}}$$ find x when y=1

Solve: 12–[26–{2+5×(6–3)}]

Find the value of $$ (2 {1\over6}+1 {13\over18}-{1\over6}) × {16÷4}$$