Simplify : $$ {(7) ^{2} ÷(7^{1\over 2})^{4}}$$

If the average of 11, 23 and x is 40, then what is the value of x?

If $$ {\sqrt{1+{473\over{256}}}=1+{x\over 16}}$$ then what does x equal to ?

The value of $${\sqrt{40+\sqrt{9\sqrt{81}}} }$$ is

The product of two whole numbers is 37. The square root of the difference of the numbers is

The value of $$ \sqrt{11.981+7\sqrt{1.2996}}$$ is closest to 

 If $$ x=\sqrt{(1.96)}-\sqrt{(0.04)}$$ then the value of x is

If 12x – 15 y =9x + 5y, the value of $$ {x^{2}+{y^{2}}\over{x^{2}-y^{2}}}$$ is